Table Of ContentThe Optimal Isodual Lattice Quantizer in Three Dimensions
J. H. Conway
Mathematics Department
Princeton University
Princeton, NJ 08544
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N. J. A. Sloane
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0 AT&T Shannon Labs
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180 Park Avenue
n Florham Park, NJ 07932-0971
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J
Email: conway@math.princeton.edu, njas@research.att.com
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] Jan 02 2006.
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Abstract
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t
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The mean-centered cuboidal (or m.c.c.) lattice is known to be the optimal packing and
m
covering among all isodual three-dimensional lattices. In this note we show that it is also the best
[
quantizer. It thus joins the isodual lattices Z, A and (presumably) D , E and the Leech lattice
2 4 8
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in being simultaneously optimal with respect to all three criteria.
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8 Keywords: quantizing, self-dual lattice, isodual lattice, f.c.c. lattice, b.c.c. lattice, m.c.c.
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lattice
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7 AMS 2000 Classification: 52C07 (11H55, 94A29)
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h 1. Introduction
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a
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: An isodual lattice [10] is one that is geometrically similar to its dual. Let Λ be an n-dimensional
v
i lattice andlet V denotethe Voronoi cell containing the origin. We may assumeΛ is scaled sothat
X
r V has unit volume. Three important parameters of Λ are the packing radius (the in-radius of V),
a
the covering radius (the circum-radius of V) and its quantization error, which is the normalized
second moment
1
G := x x dx (1)
n Z ·
V
(see [8], also [11], [12], [13]).
It is known that the face-centered cubic (or f.c.c.) lattice A has the largest packing radius of
3
any three-dimensional lattice (Gauss), while its dual, the body-centered cubic (or b.c.c.) lattice
A has both the smallest covering radius [1] and the smallest quantization error [2]. In [10] it was
∗3
shown that among all isodual three-dimensional lattices, the mean-centered cuboidal (or m.c.c.)
lattice has the largest packing radius and the smallest covering radius.
The m.c.c. lattice, denoted here by M , has Gram matrix
3
1+√2 1 1
− −
1
1 1+√2 1 √2 ,
2 − −
1 1 √2 1+√2
− −
determinant 1, packing radius 1 1 + 1 , center density δ = 0.1657... (which is between the
2q2 √2
values for the f.c.c. and b.c.c. lattices), covering radius 30.52 1.25 (again between the values for
−
the f.c.c. and b.c.c. lattices), kissing number 8 and automorphism group of order 16. The m.c.c.
lattice received a brief mention in [3] and was studied in more detail in [10]. It also arises from
the period matrix of the hyperelliptic Riemann surface w2 = z8 1 [4].
−
The purpose of this note is to prove:
Theorem 1. The m.c.c. lattice M is the optimal quantizer among all isodual three-dimensional
3
lattices.
In higher dimensions, less is known. The lattice D is optimal among all four-dimensional lat-
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tice packings, andhas alower quantization errorthanany other four-dimensionallattice presently
known (see [8] for references). It is not the best four-dimensional lattice covering (A is better),
∗4
but it is isodual and may be optimal among isodual lattices with respect to all three criteria.
Similar remarks apply to the isodual eight-dimensional lattice E (again A is a better covering
8 ∗8
but is not isodual). In 24 dimensions the isodual Leech lattice is known to be the best lattice
packing [6], and may well also be the optimal covering and quantizer.
2. Proof of Theorem 1
We will specify three-dimensional lattices by giving Gram matrices and conorms (or Selling pa-
rameters) — cf. [7], [9], [10]. Itwas shown in [10] that, upto equivalence, indecomposable isodual
three-dimensional lattices of determinant 1 have Gram matrices of the form
2α αβ α(2 β)
β − − −
1
αβ 2β 2β(1−α) , (2)
2 αβ − α − α
−
−α(2−β) −2β(α1−α) α2β+2α+α2β−4αβ
2
where α, β are any real numbers satisfying 0 < α < 1, 0 < β < 1; and decomposable lattices have
Gram matrices
1 0 0
0 α h , (3)
−
0 h β
−
where α, β, h are any real numbers satisfying 0 2h α β, αβ h2 = 1.
≤ ≤ ≤ −
In the indecomposable case the nonzero conorms are:
α(2 β) αβ 2α(1 β)
p = − , p = , p = − ,
01 02 03
γ γ βγ
2β(1 α) 2(1 α)(1 β) β(2 α)
p = − , p = − − , p = − , (4)
12 13 23
αγ γ γ
where γ = 2 αβ; in the decomposable case they are:
−
p = 1, p = α h, p = β h, p = 0, p = 0, p = h. (5)
01 02 03 12 13 23
− −
The m.c.c. lattice corresponds to the case α= β = 2 √2 of Eqs. (2) and (4).
−
From [2] we know that the normalized second moment (1) for a decomposable or indecompos-
able three-dimensional lattice Λ is given by
DS +2S +K
1 2
G = , (6)
36D4/3
where D = det Λ,
S = p +p +p +p +p +p ,
1 01 02 03 12 13 23
S = p p p p +p p p p +p p p p ,
2 01 02 13 23 01 03 12 23 02 03 12 13
K = p p p (p +p +p )+p p p (p +p +p )
01 02 03 12 13 23 01 12 13 02 03 23
+p p p (p +p +p )+p p p (p +p +p ).
02 12 23 01 03 13 03 13 23 01 02 12
For our lattices, D = 1.
We first consider the indecomposable case. From (4), (6) we find that
f(α,β)
G = (7)
36αβ(2 αβ)4
−
where
f(α,β) = 3α5β5 8α4β4(α+β)+4α3β3(α2+10αβ +β2)
−
48α3β3(α+β)+8α2β2(3α2 +4αβ +3β2)+32α2β2(α+β)
−
8αβ(5α2 +6αβ +5β2)+16(α2 +αβ +β2).
−
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It turns out that there is exactly one choice for (α,β) in the range 0 < α < 1, 0 < β < 1 for
which both partial derivatives ∂G and ∂G vanish, namely α = β = 2 √2, corresponding to the
∂α ∂β −
m.c.c. lattice. At all other points in the interior of this region, one of the two partial derivatives
does not vanish and so the point cannot be a local minimum. To show this we used the computer
algebra system Maple [5] to compute the numerators of ∂G and ∂G, giving a pair of simultaneous
∂α ∂β
equations in α and β, symmetrical in α and β. By eliminating β, we obtain a single equation for
α:
α(α 1)(α 2)(α2 +2α 2)(α2 4α+2)(α4 4α3+6α2 4)
− − − − − − ×
(57α6 220α5 102α4 +1448α3 1860α2 +832α 152) = 0.
× − − − −
Theonlyrootsintherange0< α < 1are2 √2,√3 1andtheroot0.9894... ofthesixth-degree
− −
factor. By symmetry, β must also take one of these three values. At only one of these nine points
do both partial derivatives vanish, namely α = β = 2 √2. At that point the matrix of second
−
partial derivatives is positive definite, showing that m.c.c. is a local minimum. The resulting
value of G is
17+4√2
= 0.0786696... ,
288
between the values for the b.c.c. and f.c.c. lattices, which are respectively
19 21/3
22/3 = 0.0785432... and = 0.0787450... .
384 16
Ontheboundaryoftheregionthelatticesareeitherdegenerate(ifαorβ is0)ordecomposable
(if α or β is 1). In the latter case we assume α β and find that there is a unique point where
≤
∂G and ∂G vanish, when α = √3 1, β = 1. This is the lattice Z 3 1/4A , for which
∂α ∂β − ⊕ − 2
G = 5√3 + 1 = 0.0812361.... It is not a local minimum.
162 36
It remains to consider the decomposable case. From (5), (6), we find that
1
G = αβ(α+β)+2(αβ 1)3/2 +2α+2β +1 . (8)
36 n − o
Again we solve ∂G = ∂G = 0, and find that the only possibilities in the range 0 α β are
∂α ∂β ≤ ≤
α = β = 1, G = 1 ; α = 1, β = 2, G = 1 ; and α = β = √3 1 (the decomposable lattice
12 12 −
mentioned above). None of these are local minima. This completes the proof. The proof also
shows that the m.c.c. lattice is the only isodual lattice where G has a local minimum.
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