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EE101: Op Amp circuits (Part 2) M. B. Patil [email protected] www.ee.iitb.ac.in/~sequel DepartmentofElectricalEngineering IndianInstituteofTechnologyBombay M.B.Patil,IITBombay Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd M.B.Patil,IITBombay Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. M.B.Patil,IITBombay Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. M.B.Patil,IITBombay R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, M.B.Patil,IITBombay (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. M.B.Patil,IITBombay Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. M.B.Patil,IITBombay Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. M.B.Patil,IITBombay Theamplifiershouldonlyamplifyv2−v1=0.0375V (sincethatisthesignalarisingfrom∆R). Definitions: Givenv1andv2, 1 vc = 2(v1+v2)=common-modevoltage, vd =(v2−v1)=differential-modevoltage. v1andv2canberewrittenas, v1=vc−vd/2, v2=vc+vd/2. Intheaboveexample,vc ≈7.5V, vd =37.5mV. Notethatthecommon-modevoltageisquitelargecomparedtothedifferential-modevoltage. Thisisacommonsituationintransducercircuits. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd v1=7.5V, v2=7.5+0.0375V. M.B.Patil,IITBombay Definitions: Givenv1andv2, 1 vc = 2(v1+v2)=common-modevoltage, vd =(v2−v1)=differential-modevoltage. v1andv2canberewrittenas, v1=vc−vd/2, v2=vc+vd/2. Intheaboveexample,vc ≈7.5V, vd =37.5mV. Notethatthecommon-modevoltageisquitelargecomparedtothedifferential-modevoltage. Thisisacommonsituationintransducercircuits. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd v1=7.5V, v2=7.5+0.0375V. Theamplifiershouldonlyamplifyv2−v1=0.0375V (sincethatisthesignalarisingfrom∆R). M.B.Patil,IITBombay

Description:
Department of Electrical Engineering M. B. Patil, IIT Bombay Consider a bridge circuit for sensing temperature, pressure, etc., with Ra = Rb = Rc Vo = Is R . The diode is under a reverse bias, with Vn = 0 V and Vp = Vbias .
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EE101: Op Amp circuits (Part 2) M. B. Patil [email protected] www.ee.iitb.ac.in/~sequel DepartmentofElectricalEngineering IndianInstituteofTechnologyBombay M.B.Patil,IITBombay Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd M.B.Patil,IITBombay Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. M.B.Patil,IITBombay Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. M.B.Patil,IITBombay R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, M.B.Patil,IITBombay (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. M.B.Patil,IITBombay Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. M.B.Patil,IITBombay Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd Considerabridgecircuitforsensingtemperature,pressure,etc.,withRa=Rb=Rc =R. Rd =R+∆R varieswiththequantitytobemeasured. Typically,∆R isasmallfractionofR. Thebridgeconverts∆R toasignalvoltagewhichcanthenbesuitablyamplifiedandusedfor displayorcontrol. Assumingthattheamplifierhasalargeinputresistance, R 1 v1= R+R VCC = 2VCC. (R+∆R) 1 1+x 1 1 v2= R+(R+∆R)VCC = 2 1+x/2VCC ≈ 2(1+x)(1−x/2)VCC = 2(1+x/2)VCC, wherex=∆R/R. Forexample,withVCC =15V,R=1k,∆R=0.01k , v1=7.5V, v2=7.5+0.0375V. M.B.Patil,IITBombay Theamplifiershouldonlyamplifyv2−v1=0.0375V (sincethatisthesignalarisingfrom∆R). Definitions: Givenv1andv2, 1 vc = 2(v1+v2)=common-modevoltage, vd =(v2−v1)=differential-modevoltage. v1andv2canberewrittenas, v1=vc−vd/2, v2=vc+vd/2. Intheaboveexample,vc ≈7.5V, vd =37.5mV. Notethatthecommon-modevoltageisquitelargecomparedtothedifferential-modevoltage. Thisisacommonsituationintransducercircuits. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd v1=7.5V, v2=7.5+0.0375V. M.B.Patil,IITBombay Definitions: Givenv1andv2, 1 vc = 2(v1+v2)=common-modevoltage, vd =(v2−v1)=differential-modevoltage. v1andv2canberewrittenas, v1=vc−vd/2, v2=vc+vd/2. Intheaboveexample,vc ≈7.5V, vd =37.5mV. Notethatthecommon-modevoltageisquitelargecomparedtothedifferential-modevoltage. Thisisacommonsituationintransducercircuits. Common-mode and differential-mode voltages VCC Ra Rc v1 v2 Amplifier Vo Rb Rd v1=7.5V, v2=7.5+0.0375V. Theamplifiershouldonlyamplifyv2−v1=0.0375V (sincethatisthesignalarisingfrom∆R). M.B.Patil,IITBombay

Description:
Department of Electrical Engineering M. B. Patil, IIT Bombay Consider a bridge circuit for sensing temperature, pressure, etc., with Ra = Rb = Rc Vo = Is R . The diode is under a reverse bias, with Vn = 0 V and Vp = Vbias .
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