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Hyperdeterminantal relations among symmetric principal minors 7 Olga Holtz Bernd Sturmfels 0 Mathematics Department Mathematics Department 0 2 University of California University of California n Berkeley, CA 94720 Berkeley, CA 94720 a J February 2, 2008 6 1 ] Abstract A R Theprincipalminorsofasymmetricn×n-matrixformavectoroflength2n. Wecharacterize . these vectors in terms of algebraic equations derived from the 2×2×2-hyperdeterminant. h t a Key words. Hyperdeterminant,tensors, principal minors, symmetric matrices, minor assignment problem. m [ AMS subject classification. 14M12, 15A15, 15A72, 15A29, 13P10 2 v 4 1 Introduction 7 3 4 The principal minors of a real symmetric n×n-matrix A form a vector of length 2n. This vector is 0 denoted A , and its entries are indexed by subsets I of [n]:={1,2,...,n}. Namely, A denotes the ∗ I 6 minor of A whose rows and columns are indexed by I. This includes the 0×0-minor A = 1. The 0 ∅ / aimofthispaperistogiveanalgebraiccharacterization ofallvectorsinR2n whichariseinthisform. h (n+1) t Our question can be rephrased as follows. We write R 2 for the space of real symmetric n×n- ma matrices. Ouraimistodeterminetheimageoftheprincipal minor map φ :R(n+21) → R2n, A7→ A∗. If n= 2 then the image of φ is characterized by the trivial equation A = 1 and the one inequality : ∅ v i X A ·A ≤ A ·A . (1) ∅ 12 1 2 r a For n ≥ 2, the entries of the symmetric matrix A = (a ) are determined up to sign by their ij principal minors of size 1×1 and 2×2, in view of the relation a2 = A A −A A . ij i j ij ∅ Remark 1. The image of the principal minor map φ is a closed subset of R2n. The same holds for the map φC :C(n+21) → C2n which takes a complex symmetric matrix to its principal minors. Proof. Let A be a vector in R2n (resp. in C2n) that lies in the closure of the image of φ (resp. the ∗ imageofφC). Consideranysequence {A(k)}k≥0 ofsymmetricn×n-matriceswhoseprincipalminors tend to A as k → ∞. This sequence must beuniformly bounded, since the diagonal entries of A(k) ∗ have prescribed limits, and so do the magnitudes of all off-diagonal entries. By compactness, we can extract a convergent subsequence A(kj), whose limit A therefore has principal minors A . (cid:3) ∗ 1 Remark 1 implies that the image of φ is a complex algebraic variety in C2n. That variety is C the object of study in this paper. Equivalently, we seek to determine all polynomial equations that are valid on the image of the map φ: R(n+21) → R2n. For n = 3, the matrix A has six distinct entries, so the seven non-trivial minors A must satisfy I one polynomial equation. Expanding the determinant A , the desired equation is found to be 123 (A −A A −A A −A A +2A A A )2 = 4·(A A −A )(A A −A )(A A −A ), 123 12 3 13 2 23 1 1 2 3 1 2 12 2 3 23 1 3 13 Our point of departure is the observation that this equation coincides with the hyperdeterminant of format 2×2×2. Namely, after homogenization using A = 1, this equation is equivalent to ∅ A2A2 + A2A2 + A2A2 + A2A2 + 4·A A A A + 4·A A A A ∅ 123 1 23 2 13 3 12 ∅ 12 13 23 1 2 3 123 − 2·A A A A − 2·A A A A − 2·A A A A − 2·A A A A (2) ∅ 1 23 123 ∅ 2 13 123 ∅ 3 12 123 1 2 13 23 −2·A A A A − 2·A A A A = 0. 1 3 12 23 2 3 12 13 Replacing subsets of {1,2,3} by binary strings in {0,1}3, and thus setting A = a ,A = a , ∅ 000 1 100 ...,A = a , we see that this polynomial has the full symmetry group of the 3-cube, and it 123 111 does indeed coincide with the familiar formula for the hyperdeterminant (see [4, Prop. 14.B.1.7]). The hyperdeterminantal relations on A (of format 2×2×2) are obtained from (2) by substituting ∗ A 7→ A , A 7→ A , ∅ I 123 I∪{j1,j2,j3} A 7→ A , A 7→ A , A 7→ A (3) 1 I∪{j1} 2 I∪{j2} 3 I∪{j3} A 7→ A , A 7→ A , A 7→ A 12 I∪{j1,j2} 13 I∪{j1,j3} 23 I∪{j2,j3} for any subset I ⊂ [n] and any elements j ,j ,j ∈ [n]\I. Our first result states: 1 2 3 Theorem 2. The principal minors of a symmetric matrix satisfy the hyperdeterminantal relations. The proof of this theorem is presented in Section 2, after reviewing some relevant background frommatrix theory andthehistoryof ourproblem. We alsocomment onconnections toprobability theory. A key question is whether the converse to Theorem 2 holds, i.e., whether every vector of length 2n which satisfies the hyperdeterminantal relations arises from the principal minors of a (possibly complex) symmetric n×n-matrix. The answer to this question is “not quite but almost”. A useful counterexample to keep in mind is the following point on the hyperdeterminantal locus. Example 3. For n ≥ 4, define the vector A ∈ R2n by A = 1, A = −1 and A = 0 for all ∗ ∅ 123···n I other subsets I of [n]. Then A satisfies all hyperdeterminantal relations. It also satisfies all the ∗ Hadamard-Fischer inequalities, which are the generalization of the inequality (1) to arbitrary n: A ·A ≤ A ·A for all I,J ⊆ [n]. (4) I∩J I∪J I J These inequalities hold for positive semidefinite symmetric matrices (see, e.g., [2]). Nonetheless, the vector A is not the vector of principal minors of any symmetric n×n-matrix. ∗ To see this, we note that a symmetric n×n-matrix A which has all diagonal entries A and all i principal 2×2-minors A zero must be the zero matrix, so its determinant A would be zero. ij 123···n We spell out different versions of a converse to Theorem 2 in the later sections. In Section 3 we derive a converse under a genericity hypothesis, and in Section 5 we discuss larger hyperdetermi- nants and derive a converse usingso-called condensation relations. The ultimate converse would be 2 an explicit list of generators for the prime ideal Pn of the algebraic variety image(φC). In Section 6 we conjecture that the ideal P is generated by quartics, namely, the orbit of the hyperdeterminan- n tal relations under a natural group action. Section 4 verifies this conjecture for n = 4. Theorem 2 together with these converses resolves the Symmetric Principal Minor Assignment Problem which was stated as an open question in Problem 3.4 of [9] and in Section 3.2 of [14]. 2 Matrix Theory and Probability This work is motivated by a number of recent results and problems from matrix theory and proba- bility. Information about the principal minors of a given matrix is crucial in many matrix-theoretic settings. Of interest may be their exact value, their sign, or inequalities they satisfy. Among these problems are detection of P-matrices [13] and of GKK-matrices [8, 9], counting spanning trees of a graph [5] and the inverse multiplicative eigenvalue problem [3]. The Principal Minor Assignment Problem, as formulated in [9], is to determine whether a given vector A of length 2n is realizable ∗ as the vector of all principal minors of some n×n-matrix A. Very recently, Griffin and Tsatsomeros gave an algorithmic solution to this problem [6, 7]. Their work gives an algorithm, which, under a certain “genericity” condition, either outputs a solution matrix or determines that none exists. Our approach offers a more conceptual algebraic solution in the case of symmetric matrices. In probability theory, information about principal minors is important in determinantal point processes. Determinantal processes arise naturally in several fields, including quantum mechanics of fermions [11], eigenvalues of random matrices, random spanning trees and nonintersecting paths (see[10]andreferencestherein). Adeterminantal pointprocessonalocally compactmeasurespace (Λ,µ) is determined by a kernel K(x,y) so that the joint intensities of the process can be written as det(K(x ,x )). In particular, if Λ is a finite set and µ is the counting measure on Λ, then K i j reduces to a |Λ|×|Λ|-matrix, whose principal minors give the joint densities of the process. The matrix K is not necessarily Hermitian (or real symmetric), even though very often it is. In the theory of negatively correlated random variables [12, 14], principal minors of a real n×n- matrix give values of a function ω : 2[n] → [0,∞) on the Boolean algebra 2[n] of all subsets of [n] = {1,2,...,n}. The function ω must be non-negative and must meet the following negative correlation condition. Suppose y ,...,y are indeterminates, and consider the partition function 1 n Z(ω;y) := ω(I)·yI, where yI := y . i IX⊆[n] Yi∈I For any positive vector y = (y ,...,y ), this determines a probability measure µ = µ on 2[n] by 1 n y ω(I)yI µ(I) := for all I ⊆ [n]. Z(ω;y) The atomic random variables of this theory are given by X (I):=1 if i∈ I and 0 otherwise. Their i expectations and covariances are hXi := X(I)µ(I) and Cov(X,Y) :=hXYi−hXihYi, X I⊆[n] and the negative correlation hypothesis requires that Cov(X ,X ) ≤ 0 for all y > 0, i 6= j. i j 3 Wagner [14] asks how to characterize all functions ω satisfying these conditions and arising from some matrix A, i.e., such that ω(I) = A is the minor of A with columns and rows indexed by the I subset I ⊆ [n]. This application to probability theory is one of the motivations for our algebraic approach to the principal minor assignment problem, namely, the characterization of algebraic relations among principal minors. In this paper we restrict ourselves to the symmetric case. We now recall a basic fact about Schur complements (e.g. from [1]). The Schur complement of an invertible principal submatrix H in a matrix A is the matrix AH:=E −FH−1G where E F A =: . (cid:18) G H (cid:19) The Schur complement is the result of Gaussian elimination applied to reduce the submatrix F to zero using the rows of H. The principal minors of the Schur complement satisfy Schur’s identity A I∪α (AH) = for all subsets α ⊆ [n]\I, (5) α A I assuming that H is the principal submatrix of A with rows and columns indexed by I. The hyperdeterminantal relations of format 2×2×2 are now derived from Schur’s identity (5): Proof of Theorem 2. The validity of the relation (2) for symmetric 3×3-matrices is an easy direct calculation. Next suppose that A is a symmetric n×n-matrix all of whose principal minors A are I non-zero. The hyperdeterminantal relation for I ∪{j ,j ,j } coincides with the relation (2) for 1 2 3 the principal 3×3-minor indexed by {j ,j ,j } in the Schur complement AH, after multiplying by 1 2 3 A4 to clear denominators. Here we are using Schur’s identity (5) for any non-empty subset α of I {j ,j ,j }. Now, if A is any symmetric matrix that has vanishing principal minorsthen we write A 1 2 3 as thelimitof asequenceof matrices whoseprincipalminorsarenon-zero. Thehyperdeterminantal relations hold for every matrix in the sequence, and hence they hold for A as well. (cid:3) In Section 5 we offer an alternative proof of Theorem 2, by showing that the vector A satisfies ∗ the hyperdeterminantalrelations of higher-dimensionalformats 2×2×···×2. At this pointwe note that the hyperdeterminantal relations do not suffice even if all principal minors are non-zero. Example 4. For n = 4 there are 8 hyperdeterminantal relations, one for each facet of the 4-cube: A2A2 + A2A2 + A2A2 + A2A2 + 4A A A A + 4A A A A − 2A A A A ∅ 123 1 23 2 13 3 12 ∅ 12 13 23 1 2 3 123 ∅ 1 23 123 −2A A A A − 2A A A A − 2A A A A − 2A A A A − 2A A A A = 0, ∅ 2 13 123 ∅ 3 12 123 1 2 13 23 1 3 12 23 2 3 12 13 A2A2 + A2A2 + A2A2 + A2A2 + 4A A A A + 4A A A A − 2A A A A ∅ 124 1 24 2 14 4 12 ∅ 12 14 24 1 2 4 124 ∅ 1 24 124 −2A A A A − 2A A A A − 2A A A A − 2A A A A − 2A A A A = 0, ∅ 2 14 124 ∅ 4 12 124 1 2 14 24 1 4 12 24 2 4 12 14 A2A2 + A2A2 + A3A2 + A3A2 + 4A A A A + 4A A A A − 2A A A A ∅ 134 1 34 3 14 4 13 ∅ 13 14 34 1 3 4 134 ∅ 1 34 134 −2A A A A − 2A A A A − 2A A A A − 2A A A A − 2A A A A = 0, ∅ 3 14 134 ∅ 4 13 134 1 3 14 34 1 4 13 34 3 4 13 14 A2A2 + A2A2 + A2A2 + A2A2 + 4A A A A + 4A A A A − 2A A A A ∅ 234 2 34 3 24 4 23 ∅ 23 24 34 2 3 4 234 ∅ 2 34 234 −2A A A A − 2A A A A − 2A A A A − 2A A A A − 2A A A A = 0, ∅ 3 24 234 ∅ 4 23 234 2 3 24 34 2 4 23 34 3 4 23 24 4 A2A2 +A2 A2 +A2 A2 +A2 A2 +4A A A A +4A A A A 4 1234 14 234 24 134 34 124 4 124 134 234 14 24 34 1234 −2A A A A −2A A A A −2A A A A 4 14 234 1234 4 24 134 1234 4 34 124 1234 −2A A A A −2A A A A −2A A A A = 0, 14 24 134 234 14 34 124 234 24 34 124 134 A2A2 +A2 A2 +A2 A2 +A2 A2 +4A A A A +4A A A A 3 1234 13 234 23 134 34 123 3 123 134 234 13 23 34 1234 −2A A A A −2A A A A −2A A A A 3 13 234 1234 3 23 134 1234 3 34 123 1234 −2A A A A −2A A A A −2A A A A = 0, 13 23 134 234 13 34 123 234 23 34 123 134 A2A2 +A2 A2 +A2 A2 +A2 A2 +4A A A A +4A A A A 2 1234 12 234 23 124 24 123 2 123 124 234 12 23 24 1234 −2A A A A −2A A A A −2A A A A 2 12 234 1234 2 23 124 1234 2 24 123 1234 −2A A A A −2A A A A −2A A A A = 0, 12 23 124 234 12 24 123 234 23 24 123 124 A2A2 +A3 A2 +A3 A2 +A3 A3 +4A A A A +4A A A A 1 1234 12 134 13 124 14 123 1 123 124 134 12 13 14 1234 −2A A A A −2A A A A −2A A A A 1 12 134 1234 1 13 124 1234 1 14 123 1234 −2A A A A −2A A A A −2A A A A = 0. 12 13 124 134 12 14 123 134 13 14 123 124 The set of solutions to these equations has the correct codimension (five) but it is too big. To illustrate this phenomenon, consider the case when all minors of a given size have the same value: A := x , A := x , A := x , A := x , A := x . ∅ 0 i 1 ij 2 ijk 3 1234 4 Under this specialization, the eight hyperdeterminants above reduce to a system of two equations: x2x2−6x x x x +4x x3+4x3x −3x2x2 = x2x2−6x x x x +4x x3+4x3x −3x2x2 = 0. (6) 0 3 0 1 2 3 0 2 1 3 1 2 1 4 1 2 3 4 1 3 2 4 2 3 The solution set to these equations in P4 is the union of two irreducible surfaces, of degree ten and six respectively. The degree ten surface is extraneous and is gotten by requiring additionally that x x2 = x2x . (7) 0 3 1 4 The degree six surface is our desired locus of principal minors. It is defined by the two equations 3x2−4x x +x x = 4x3−6x x x +x x2+x2x = 0. (8) 2 1 3 0 4 2 1 2 3 0 3 1 4 For a concrete numerical example let us consider the symmetric 4×4-matrix 2 1 1 1 1 2 1 1 A = . 1 1 2 1   1 1 1 2   Its principal minors are (x ,x ,x ,x ,x )= (1,2,3,4,5) and these satisfy (8) but not (7). On the 0 1 2 3 4 other hand, the vector (x ,x ,x ,x ,x )= (1,2,3,4,4) satisfies (6) and (7) but not (8). The cor- 0 1 2 3 4 responding vector A ∈R16 has all its entries non-zero and satisfies the eight hyperdeterminantal ∗ relations but it does not come from the principal minors of any symmetric 4×4-matrix. (cid:3) 5 3 A First Converse to Theorem 2 We now derive two additional classes of relations that the principal minors of a symmetric n×n matrix A = (a ) must satisfy. Throughout this section we set A = 1. For n ≥ 4 and for distinct ij ∅ i, j, k, l, we can write the product 8a2 a2 a2a a a in two different ways: ij ik il jk jl kl (A −A A −A A −A A +2A A A )(A −A A −A A −A A +2A A A ) ijk ij k ik j jk i i j k ijl ij l il j jl i i j l ×(A −A A −A A −A A +2A A A ) (9) ikl ik l il k kl i i k l = 4·(A −A A −A A −A A +2A A A )(A A −A )(A A −A )(A A −A ). jkl jk l jl k kl j j k l i j ij i k ik i l il Thus conditions (9) are necessary for the realizability of A . Note that the 2×2×2 hyperdetermi- ∗ nantal relations alone imply a weaker version of (9), with both sides squared. Also for n ≥ 4 and for distinct i, j, k, l, we define f (A ) := A3A −3·A A A A −A2A A −A2A A −A2A A −A2A A ijkl ∗ ∅ ijkl i j k l ∅ i ijk ∅ j ikl ∅ k ijl ∅ l ijk +A ·(A A A +A A A +A A A +A A A +A A A +A A A ) ∅ i j kl i k jl i l jk j k il j l ik k l ij −(A A −A A )(A A −A A )−(A A −A A )(A A −A A ) i j ∅ ij k l ∅ kl i k ∅ ik j l ∅ jl −(A A −A A )(A A −A A ). i l ∅ il j k ∅ jk This operation extracts the products of entries of A that occur in the determinant A indexed ijkl by permutations of order four. Namely, we find that f (A ) = −2·(a a a a +a a a a +a a a a ). ijkl ∗ ij il jk kl ij ik jl kl ik il jk jl To rewrite these terms differently, we use the polynomials g (A ) := A2A −A ·(A A +A A +A A )+2·A A A = 2·a a a , ijk ∗ ∅ ijk ∅ i jk j ik k ij i j k ij ik jk and we observe that g (A )g (A ) = 4·a2 a a a a , ikl ∗ ijk ∗ ik ij il jk kl g (A )g (A ) = 4·a2a a a a , ikl ∗ ijl ∗ il ij ik jl kl g (A )g (A ) = 4·a2a a a a . ijl ∗ ijk ∗ ij ik il jk jl Using the relation a2 = A A −A , we thus obtain ij i j ij 2f (A )(A A −A A )(A A −A A )(A A −A A ) ijkl ∗ i j ∅ ij i k ∅ ik i l ∅ il +g (A )g (A )(A A −A A )(A A −A A ) ikl ∗ ijk ∗ i j ∅ ij i l ∅ il +g (A )g (A )(A A −A A )(A A −A A ) ikl ∗ ijl ∗ i j ∅ ij i k ∅ ik +g (A )g (A )(A A −A A )(A A −A A ) = 0. (10) ijl ∗ ijk ∗ i k ∅ ik i l ∅ il By the Schur complement argument from Section 2, we conclude that the relations (10) continue to hold after the substitution A 7→ A , A 7→ A , A 7→ A , A 7→ A , A 7→ A , ∅ I i I∪{i} j I∪{j} k I∪{k} l I∪{l} A 7→ A , A 7→ A , A 7→ A , ij I∪{i,j} ik I∪{i,k} il I∪{i,l} A 7→ A , A 7→ A , A 7→ A , (11) jk I∪{j,k} jl I∪{j,l} kl I∪{k,l} A 7→ A , A 7→ A , A 7→ A , A 7→ A , ijk I∪{i,j,k} ijl I∪{i,j,l} ikl I∪{i,k,l} jkl I∪{j,k,l} A 7→ A ijkl I∪{i,j,k,l} for all subsets I ⊆ [n]\{i,j,k,l}. We thus proved the following addition to Theorem 2. 6 Lemma 5. The principal minors of asymmetric matrix satisfy the conditions (9)and allconditions obtained from (10) via the substitution (11). We are finally in a position to prove our first converse to Theorem 2. We assume a nondegen- eracy condition to the effect that a subset of the Hadamard-Fischer conditions holds strictly. The condition (12) is equivalent to the condition that weak sign symmetry (see, e.g., [8]) holds strictly. Theorem 6. Let A be a real vector of length 2n with A = 1 that satisfies ∗ ∅ A A < A A whenever #I ∩J = #I −1= #J −1. (12) I∩J I∪J I J There exists a real symmetric matrix A with principal minors given by A if and only if A satisfies ∗ ∗ the hyperdeterminantal relations, the relations (9) and all relations obtained from (10) using (11). Proof. Assuming (12), (9) and (10), we build the real symmetric matrix A= (a ) as follows. The ij entries A indexed by sets I of size 1 and 2 determine all diagonal entries a and the magnitudes I ii of all off-diagonal entries. Note that (12) implies that all off-diagonal entries of A are non-zero. It remains to choose the signs of off-diagonal entries correctly. Since the principal minors of A do not change under diagonal similarity A 7→ DAD−1 where each diagonal entry of the matrix D is ±1, we can fix all first row entries a with j > 1 to be positive. Then the sign of each entry a with 1j 2j j > 2 is determined unambiguously by the values A , the sign of each entry a with j > 3 is 12j 3j determined by the values A , and so on. In this fashion we prescribe all entries of the matrix A. 13j Using hyperdeterminantal relations and condition (9), we see that this assignment is consistent with the values of all principal minors A where the index set I has size at most 3. Indeed, I the hyperdeterminantal relations guarantee that the absolute values of all off-diagonal entries are consistentwiththevaluesofallprincipalminorsoforderatmost3,whereasconditions(9)guarantee that the signs are consistent as well. Theremaining entries of A , i.e., the principal minors indexed ∗ by sets of size more than 3, are determined uniquely by the already specified entries of A . This ∗ followsfromtheconditions(10)andfromallconditionsobtainedfrom(10)viathesubstitution(11), since in every such condition its largest principal minor occurs linearly with a nonzero coefficient (which is a function of smaller minors) due to the inequalities (12). Thus the constructed matrix A= (a ) has the prescribed vector of principal minors A . (cid:3) ij ∗ 4 The Prime Ideal for 4×4-Matrices From the point of view of algebraic geometry, the following version of our problem is most natural: Problem 7. Let P be the prime ideal of all homogeneous polynomial relations among the principal n minors of a symmetric n×n-matrix. Determine a finite set of generators for the prime ideal P . n The ideal P lives in the ring of polynomials in the 2n unknowns A with rational coefficients. n I Forn = 3,theidealI isprincipal,anditsgenerator isthe2×2×2-hyperdeterminant. InTheorem2 3 we identified the subideal H which is generated by all hyperdeterminantal relations, one for each n 3-dimensional face of then-cube. For instance, theideal H for the4-cubeis generated by the eight 4 homogeneous polynomials of degree four in 16 unknowns listed in Example 4. It can beshown that P is a minimal prime of the ideal H but in general we do not know the minimal generators of P . n n n Twoimportantfeatures of bothideals P andH is that they areinvariant underthesymmetry n n groupofthen-cube,andtheyarehomogeneouswithrespecttothe(n+1)-dimensionalmultigrading 7 induced by the n-cube. Both features were used to simplify and organize our computations. In this section we focus on the case n = 4, for which we establish the following result. Theorem 8. The homogeneous prime ideal P is minimally generated by twenty quartics in the 16 4 unknowns A . The corresponding irreducible variety in P15 has codimension five and degree 96. I Thistheoremwasestablishedwiththeaidofcomputationsusingthecomputeralgebrapackages SingularandMacaulay 2. We worked inthepolynomialringwiththe5-dimensionalmultigrading deg(A ) = (1,0,0,0,0), deg(A ) = (1,1,0,0,0), ..., deg(A ) = (1,0,0,0,1) ∅ 1 4 deg(A )= (1,1,1,0,0),..., deg(A ) = (1,0,1,1,1), deg(A )= (1,1,1,1,1). 12 234 1234 Thetwenty minimalgeneratorsofP comeinthreesymmetryclasses, withrespecttothesymmetry 4 groupofthe4-cube(i.e.theWeylgroupB oforder384). Thethreesymmetryclassesareasfollows: 4 Class 1: The eight 2×2×2 hyperdeterminants are listed in Example 4. Their multidegrees are (4,2,2,2,0), (4,2,2,0,2), (4,2,0,2,2), (4,0,2,2,2), (4,2,2,2,4), (4,2,2,4,2), (4,2,4,2,2), (4,4,2,2,2). Class 2: Thereisaunique(uptoscaling)minimalgenerator ofP ineach oftheeightmultidegrees 4 (4,2,2,2,1), (4,2,2,1,2), (4,2,1,2,2), (4,1,2,2,2), (4,2,2,2,3), (4,2,2,3,2), (4,2,3,2,2), (4,3,2,2,2). The representative for multidegree (4,3,2,2,2) is the following quartic with 40 terms: A2 A A −A A A A −A A A A −A A A A −A A A A 1234 1 ∅ 1234 123 14 ∅ 1234 123 1 4 1234 124 13 ∅ 1234 124 1 3 −A A A A −A A A A −A A A A −A A A A −A A A A 1234 134 12 ∅ 1234 134 1 2 1234 12 34 1 1234 13 24 1 1234 14 23 1 −A A A A −A A A A −A A A A −A A A A −A A A A 123 124 13 4 123 124 14 3 123 134 12 4 123 134 14 2 123 234 14 1 −A A A A −A A A A −A A A A −A A A A −A A A A 123 12 14 34 123 13 14 24 124 134 12 3 124 134 13 2 124 234 13 1 −A A A A −A A A A −A A A A −A A A A −A A A A 124 12 13 34 124 13 14 23 134 234 12 1 134 12 13 24 134 12 14 23 +2A A A A +2A A A A +2A A A A +2A A A A +2A A A A 1234 12 13 4 1234 12 14 3 1234 13 14 2 123 124 134 ∅ 123 124 34 1 +2A A A A +2A A A A +2A A A A +A A A2+A2 A A 123 134 24 1 124 134 23 1 234 12 13 14 1234 234 1 123 14 4 +A A2 A +A2 A A +A A2 A +A2 A A +A A2 A . 123 14 23 124 13 3 124 13 24 134 12 2 134 12 34 Class 3: The ideal P contains a four-dimensional space of minimal generators in multidegree 4 (4,2,2,2,2). Thesegeneratorsarenotuniquebutwecanchooseasymmetriccollectionofgenerators by taking the four quartics in the B -orbit of the following polynomial with 36 terms: 4 12· A2A2 +A2A2 +A2A2 +A2 A2 +A2A2 +A2 A2 +A2 A2 +A2 A2 ∅ 1234 4 123 3 124 34 12 2 134 24 13 23 14 234 1 −A A(cid:0)A A −A A A A −A A A A −A A A A +A A A A(cid:1) ∅ 34 12 1234 ∅ 24 13 1234 ∅ 23 14 1234 ∅ 234 1 1234 ∅ 234 14 123 +A A A A +A A A A −A A A A −A A A A +A A A A ∅ 234 13 124 ∅ 234 134 12 4 3 124 123 4 2 134 123 4 23 1 1234 −A A A A +A A A A +A A A A −A A A A −A A A A 4 23 14 123 4 23 13 124 4 23 134 12 4 234 1 123 3 2 134 124 +A A A A +A A A A −A A A A +A A A A −A A A A 3 24 1 1234 3 24 14 123 3 24 13 124 3 24 134 12 3 234 1 124 +A A A A +A A A A +A A A A −A A A A 34 2 1 1234 34 2 14 123 34 2 13 124 34 2 134 12 −A A A A −A A A A −A A A A −A A A A . 34 24 13 12 34 23 14 12 2 234 1 134 24 23 14 13 8 It can be checked, using Macaulay 2 or Singular, that the higher degree polynomials gotten from (9) and (10) by homogenization with A are indeed polynomial linear combinations of these 20 ∅ quartics. We thus obtain the following strong converse to Theorem 2 in the case of 4×4-matrices: Corollary 9. A vector A ∈ C16 with A = 1 can be realized as the principal minors of a symmetric ∗ ∅ matrix A ∈ C4×4 if and only the above twenty quartics are zero at A . If the entries of the given ∗ vector A are real and satisfy (12) then the entries of the symmetric matrix A are real numbers. ∗ Proof. Consider the map which takes complex symmetric 4×4-matrices to their vector of principal minors. The image of this map is closed by Corollary 1, and it hence equals the affine variety in C15 = {A = 1} defined by the prime ideal P . The statement for R is derived from Theorem 6. (cid:3) ∅ 4 5 Big Hyperdeterminants and Condensation Polynomials One ultimate goal is to generalize Theorem 8 and Corollary 9 from n = 4 to n ≥ 5. This section offers first steps in this direction, starting with the general hyperdeterminantal constraints on A . ∗ We recall from [4, Chap.14] that the hyperdeterminant of a tensor A = (a ) of format i1,...,ir 2×2×···×2 is defined as follows. Consider the multilinear form f defined by the tensor A: 1 1 1 f(x) := f(x(1),x(2)...,x(r)) := ··· a ·x(1)x(2)···x(r). (13) i1,i2,...,ir i1 i2 ir iX1=0iX2=0 iXr=0 The hyperdeterminant det(A) is the unique (up to scaling) irreducible polynomial in the entries of A that characterizes the degeneracy of the form f, i.e., det(A) = 0 if and only if the equations ∂f(x) f(x) = = 0 for all i, j (14) (j) ∂x i have a solution x =(x(1),x(2),...,x(r)) where each x(j) is a non-zero complex vector in C2. As before we identify our proposed vector of principal minors A ∈ R2n with the corresponding ∗ 2×2×···×2-tensor. The following result generalizes Theorem 2 and gives an alternative proof. Theorem 10. Let A= (a ) be a symmetric n×n matrix. Then the tensor A of all principal mi- ij ∗ nors of A is a common zero of all the hyperdeterminants of formats from 2×2×2 up to 2×2×···×2. nterms | {z } Proof. It suffices to prove that the highest-dimensional hyperdeterminant vanishes, using Schur complements and induction. Let f be the form (13) corresponding to the tensor A . Take ∗ x(1) :=(a a −a a , a ), x(2) :=(a a −a a , a ), x(3) :=(a a −a a , a ). (15) 12 13 11 23 23 12 23 13 22 13 13 23 12 33 12 and take the remaining x(j) to be (1,0). With this choice of x, the conditions (14) are satisfied. (cid:3) We next introduce the condensation polynomial C which expresses the determinant A as n 123···n an algebraic function of theprincipalminorsA andA of size at most two. For instance, for n = 3 i ij the determinant A is an algebraic function of degree two in {A ,A ,A ,A ,A ,A }, and thus 123 1 2 3 12 13 23 C coincides with the 2×2×2-hyperdeterminant. In general, the condensation polynomial C is 3 n defined as the uniqueirreducible(and monic in A ) generator of the principal elimination ideal 123···n hC i = (P +hA −1i) ∩ Q[A ,A ,...,A , A ,A ...,A , A ]. n n ∅ 1 2 n 12 13 n−1,n 123···n 9 Using the sign-swapping argument in the proof of Theorem 6, we can show that C is a polynomial n (n−1) (n−1) of degree 2 2 in A123···n. The total degree of Cn is bounded above by n·2 2 . The following derivation proves these assertions for n = 4, and it illustrates the construction of C in general. n Example 11. The condensation polynomial C is an irreducible polynomial of degree 23. It is the 4 sum of 12380 monomials in Q[A ,A ,A ,A ,A ,A ,A ,A ,A ,A ,A ]. To compute C , 1 2 3 4 12 13 14 23 24 34 1234 4 we first consider the following polynomial which expresses the symmetric 4×4-determinant A a a a 1 12 13 14 A − deta12 A2 a23 a24. (16) 1234 a a A a 13 23 3 34   a a a A  14 24 34 4   To get rid of the square roots a = A A −A , we swap the sign on the a with 1 < i < j in ij i j ij ij all eight possible ways. The orbit of (p16) under these sign swaps consists of eight distinct variants of (16). The product of these eight expressions equals C . Interestingly, the degree drops to 23. (cid:3) 4 We could in fact use the condensation polynomials C to replace the hypothesis (12) from n the statement of Theorem 6, thus providing a stronger converse to Theorem 2. However, this is not particularly useful for a practical test, since the condensation polynomials C are too big to n compute explicitly for n ≥ 5. What is desired instead are explicit generators of the prime ideal P . n 6 Invariance and the Quartic Generation Conjecture This section was written after the first version of this paper had been submitted for publication. It is based on discussions with J.M. Landsberg, who suggested Theorem 12 to us in May 2006. Let R[A ] denote the polynomial ring in 2n unknowns A where I runs over all subsets of • I {1,2,...,n}. We are interested in the prime ideal P of all homogeneous polynomials in R[A ] n • which are algebraic relations among the 2n principal minors of a generic symmetric n×n-matrix. Clearly, P is invariant under the action of the symmetric group S on the polynomial ring R[A ]. n n • In what follows we show that P is invariant undera natural Lie group action on R[A ] as well. Let n • SL (R) denote group of real 2×2-matrices with determinant 1. The n-fold product of this group, 2 G := SL (R)×SL (R)×···×SL (R), 2 2 2 acts naturally on the n-fold tensor product R2n := R2⊗R2⊗···⊗R2. Since R[A ] is the ring of polynomial functions of R2n, we get an action of G on R[A ]. • • Theorem 12. The homogeneous prime ideal P is invariant under the group G. n Proof. Consider an n× 2n-matrix (B C) where B and C are generic n×n-matrices subject to the constraint that B−1C is symmetric. We identify each principal minor of the symmetric matrix B−1C with an n×n-minor of the matrix (B C). The 2n maximal minors of (B C) which come from principal minors of B−1C are precisely those whose column index sets J ⊂ {1,2,...,2n} satisfy #(J ∩ {i,i+n}) = 1 for i = 1,2,...,n. We call these the special maximal minors of (B C). The prime ideal P consists of the algebraic relations among the 2n special maximal minors. n 10

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