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AN INFINITE PRESENTATION FOR THE MAPPING CLASS GROUP OF A NON-ORIENTABLE SURFACE 6 1 GENKIOMORI 0 2 l u J Abstract. Wegiveaninfinitepresentationforthemappingclassgroupofa 1 non-orientable surface. Thegenerating set consists of all Dehn twists and all 1 crosscappushingmapsalongsimpleloops. ] 1. Introduction T G Let Σ be a compact connected orientable surface of genus g ≥ 0 with n ≥ 0 g,n . boundary components. The mapping class group M(Σg,n) of Σg,n is the group h of isotopy classes of orientation preserving self-diffeomorphisms on Σ fixing the t g,n a boundary pointwise. A finite presentation for M(Σ ) was given by Hatcher- g,n m Thurston[6],Wajnryb[17],Harer[5],Gervais[4]andLabru`ere-Paris[9]. Gervais[3] [ obtained an infinite presentation for M(Σ ) by using Wajnryb’s finite presenta- g,n tionforM(Σ ),andLuo[12]rewroteGervais’presentationintoasimplerinfinite 2 g,n v presentation (see Theorem 2.5). 6 Let N be a compact connected non-orientable surface of genus g ≥ 1 with g,n 1 n ≥ 0 boundary components. The surface N = N is a connected sum of g real g g,0 4 projectiveplanes. ThemappingclassgroupM(N )ofN isthegroupofisotopy 1 g,n g,n classesofself-diffeomorphismsonN fixingtheboundarypointwise. Forg ≥2and 0 g,n . n ∈{0,1}, a finite presentation for M(Ng,n) was given by Lickorish [10], Birman- 1 Chillingworth [1], Stukow [14] and Paris-Szepietowski [13]. Note that M(N ) and 0 1 6 M(N1,1)aretrivial(see[2,Theorem3.4])andM(N2)isfinite(see[10,Lemma5]). 1 Stukow[15]rewroteParis-Szepietowski’spresentationintoafinitepresentationwith : Dehn twists and a “Y-homeomorphism” as generators (see Theorem 2.11). v i In this paper, we give a simple infinite presentation for M(Ng,n) (Theorem 3.1) X when g ≥ 1 and n ∈ {0,1}. The generating set consists of all Dehn twits and all r “crosscappushing maps” alongsimple loops. We review the crosscappushing map a in Section 2. We prove Theorem 3.1 by applying Gervais’ argument to Stukow’s finite presentation. 2. Preliminaries 2.1. Relations among Dehn twists and Gervais’ presentation. Let S be either N or Σ . We denote by N (A) a regular neighborhood of a subset A g,n g,n S in S . For every simple closed curve c on S, we choose an orientation of c and fix it throughout this paper. However, for simple closed curves c , c on S and 1 2 f ∈M(S), f(c )=c means f(c ) is isotopic to c or the inverse curve of c . If S 1 2 1 2 2 is a non-orientable surface, we also fix an orientation of N (c) for each two-sided S simple closed curve c. For a two-sidedsimple closed curve c on S, denote by t the c Date:July12,2016. 1 2 G.OMORI right-handed Dehn twist along c on S. In particular, for a given explicit two-sided simple closed curve, an arrow on a side of the simple closed curve indicates the direction of the Dehn twist (see Figure 1). Figure 1. Theright-handedDehntwistt alongatwo-sidedsim- c ple closed curve c on S. Recallthe followingrelationsonM(S) amongDehn twists along two-sidedsim- ple closed curves on S. Lemma 2.1. For a two-sided simple closed curve c on S which bounds a disk or a M¨obius band in S, we have t =1 on M(S). c Lemma 2.2 (The braid relation (i)). For a two-sided simple closed curve c on S and f ∈M(S), we have tεf(c) =ft f−1, f(c) c where εf(c) = 1 if the restriction f|NS(c) : NS(c) → NS(f(c)) is orientation pre- serving and εf(c) =−1 if the restriction f|NS(c) :NS(c)→NS(f(c)) is orientation reversing. When f in Lemma 2.2 is a Dehn twist t along a two-sided simple closed curve d d and the geometric intersection number |c∩d| of c and d is m, we denote by T m the braid relation. Let c , c , ..., c be two-sided simple closed curves on S. The sequence c , 1 2 k 1 c , ..., c of simple closed curves on S is a k-chain on S if c , c , ..., c satisfy 2 k 1 2 k |c ∩c |=1 for each i=1, 2, ..., k−1 and |c ∩c |=0 for |j−i|>1. i i+1 i j Lemma 2.3 (The k-chain relation). Let c , c , ..., c be a k-chain on S and let 1 2 k δ , δ (resp. δ) be distinct boundary components (resp. the boundary component) 1 2 of N (c ∪c ∪···∪c ) when k is odd (resp. even). Then we have S 1 2 k (tcε1c1tcε2c2 ···tcεkck)k+1 = tδε1δ1tδε2δ2 when k is odd, (tcε1c1tcε2c2 ···tcεkck)2k+2 = tεδδ when k is even, awnhderteεδε2c1(,reεscp2., .tε.δ.), aεrcek,rεigδh1,t-εhδa2ndaenddDεeahrnet1wiosrts−fo1r, saonmdetcεo1cr1i,entcεt2ca2t,io.n..o,ftNcεkck,(ctδε1δ∪1 δ2 δ S 1 c ∪···∪c ). 2 k Lemma 2.4 (The lanternrelation). Let Σ be a subsurface of S which is diffeomor- phic to Σ and let δ , δ , δ , δ , δ , δ and δ be simple closed curves on Σ as 0,4 12 23 13 1 2 3 4 in Figure 2. Then we have tεδ12tεδ23tεδ13 =tεδ1tεδ2tεδ3tεδ4, δ12 δ23 δ13 δ1 δ2 δ3 δ4 where ε , ε , ε , ε , ε , ε and ε are 1 or −1, and tεδ12, tεδ23, tεδ13, tεδ1, tεδ2, tεδ3δ12andδ2t3εδ4 δa1r3e riδg1ht-δh2andδe3d Dehnδ4twists for some orienδ1t2ationδ23of Σδ.13 δ1 δ2 δ3 δ4 PRESENTATION FOR MAPPING CLASS GROUP 3 Figure 2. Simple closed curves δ , δ , δ , δ , δ , δ and δ on Σ. 12 23 13 1 2 3 4 Luo’s presentation for M(Σ ), which is an improvement of Gervais’ one, is as g,n follows. Theorem 2.5 ([3], [12]). For g ≥0 and n≥0, M(Σ ) has the following presen- g,n tation: generators: {t |c: s.c.c. on Σ }. c g,n relations: (0′) t =1 when c bounds a disk in Σ , c g,n (I′) All the braid relations T and T , 0 1 (II) All the 2-chain relations, (III) All the lantern relations. 2.2. Relations among the crosscap pushing maps and Dehn twists. Let µ be a one-sided simple closed curve on N and let α be a simple closed curve on g,n N suchthatµandαintersecttransverselyatonepoint. Recallthatαisoriented. g,n Forthesesimpleclosedcurvesµ andα, wedenotebyY aself-diffeomorphismon µ,α N which is described as the result of pushing the Mo¨bius band N (µ) once g,n Ng,n along α. We call Y a crosscap pushing map. In particular, if α is two-sided, we µ,α callY aY-homeomorphism (orcrosscap slide),whereacrosscapmeansaMo¨bius µ,α band in the interior of a surface. The Y-homeomorphism was originally defined by Lickorish[10]. We have the following fundamental relationon M(N ) and we g,n also call the relation the braid relation. Lemma 2.6 (The braid relation (ii)). Let µ be a one-sided simple closed curve on N and let α be a simple closed curve on N such that µ and α intersect g,n g,n transversely at one point. For f ∈M(N ), we have g,n Yεf(α) =fY f−1, f(µ),f(α) µ,α where ε = 1 if the fixed orientation of f(α) coincides with that induced by the f(α) orientation of α, and ε =−1 otherwise. f(α) We describe crosscappushing maps froma differentpoint ofview. Let e:D′ ֒→ intS be a smooth embedding of the unit disk D′ ⊂ C. Put D := e(D′). Let S′ be the surface obtainedfromS−intD by the identificationofantipodalpoints of ∂D. WecallthemanipulationthatgivesS′ fromS theblowup ofS onD. Notethatthe image M ⊂ S′ of NS−intD(∂D)⊂ S−intD with respect to the blowup of S on D is a crosscap. Conversely, the blowdown of S′ on M is the following manipulation thatgivesS fromS′. WepasteadiskontheboundaryobtainedbycuttingS along the center line µ of M. The blowdown of S′ on M is the inverse manipulation of the blowup of S on D. 4 G.OMORI Let µ be a one-sided simple closed curve on Ng,n. Note that we obtain Ng−1,n from N by the blowdown of N on N (µ). Denote by x the center point g,n g,n Ng,n µ of a disk D that is pasted on the boundary obtained by cutting S along µ. Let µ e:D′ ֒→Dµ ⊂Ng−1,n be a smooth embedding of the unit disk D′ ⊂C to Ng−1,n such that Dµ = e(D′) and e(0) = xµ. Let M(Ng−1,n,xµ) be the group of isotopy classes of self-diffeomorphisms on Ng−1,n fixing the boundary ∂Ng−1,n and the pointxµ,where isotopiesalsofix the boundary∂Ng−1,n andxµ. Thenwehavethe blowup homomorphism ϕµ :M(Ng−1,n,xµ)→M(Ng,n) that is defined as follows. For h ∈ M(Ng−1,n,xµ), we take a representative h′ of h which satisfies either of the following conditions: (a) h′| is the identity map Dµ on D , (b) h′(x)=e(e−1(x)) for x∈D , where e−1(x) is the complex conjugation µ µ of e−1(x) ∈ C. Such h′ is compatible with the blowup of Ng−1,n on Dµ, thus ϕ (h)∈M(N ) is induced and well defined (c.f. [16, Subsection 2.3]). µ g,n The point pushing map jxµ :π1(Ng−1,n,xµ)→M(Ng−1,n,xµ) is a homomorphism that is defined as follows. For γ ∈ π1(Ng−1,n,xµ), jxµ(γ) ∈ M(Ng−1,n,xµ) is described as the result of pushing the point xµ once along γ. The point pushing map comes from the Birman exact sequence. Note that for γ , 1 γ2 ∈π1(Ng−1,n),γ1γ2meansγ1γ2(t)=γ2(2t)for0≤t≤ 21 andγ1γ2(t)=γ1(2t−1) for 1 ≤t≤1. 2 Following Szepietowski [16] we define the composition of the homomorphisms: ψxµ :=ϕµ◦jxµ :π1(Ng−1,n,xµ)→M(Ng,n). For each closed curve α on N which transversely intersects with µ at one point, g,n we take a loop α on Ng−1,n based at xµ such that α has no self-intersection points on Dµ and α is the image of α with respect to the blowup of Ng−1,n on Dµ. If α is simple, we take α as a simple loop. The next two lemmas follow from the description of the point pushing map (see [8, Lemma 2.2, Lemma 2.3]). Lemma 2.7. For a simple closed curve α on N which transversely intersects g,n with a one-sided simple closed curve µ on N at one point, we have g,n ψ (α)=Y . xµ µ,α Lemma 2.8. For a one-sided simple closed curve α on N which transversely g,n intersects with a one-sided simple closed curve µ on N at one point, we take g,n N (α) such that the interior of N (α) contains D . Suppose that δ and Ng−1,n Ng−1,n µ 1 δ are distinct boundary components of N (α), and δ and δ are two-sided 2 Ng−1,n 1 2 simple closed curves on N which are image of δ , δ with respect to the blowup g,n 1 2 of Ng−1,n on Dµ, respectively. Then we have Y =tεδ1tεδ2, µ,α δ1 δ2 where ε and ε are 1 or −1, and ε and ε depend on the orientations of α, δ1 δ2 δ1 δ2 N (δ ) and N (δ ) (see Figure 3). Ng,n 1 Ng,n 2 By the definition of the homomorphism ψ and Lemma 2.7, we have the fol- xµ lowing lemma. PRESENTATION FOR MAPPING CLASS GROUP 5 Figure 3. If the orientations of α, N (δ ) and N (δ ) are Ng,n 1 Ng,n 2 as above, then we have Y = t t−1. The x-mark means that µ,α δ1 δ2 antipodal points of ∂D are identified. µ Lemma2.9. Letαandβ besimple closedcurves onN which transverselyinter- g,n sect with a one-sided simple closed curve µ on N at one point each. Suppose the g,n product αβ of α and β in π1(Ng−1,n,xµ) is represented by a simple loop on Ng−1,n, and αβ is a simple closed curve on N which is the image of the representative of g,n αβ with respect to the blowup of Ng−1,n on Dµ. Then we have Y =Y Y . µ,αβ µ,α µ,β Finally, we recall the following relation between a Dehn twist and a Y- homeomorphism. Lemma 2.10. Let α be a two-sided simple closed curve on N which transversely g,n intersect with a one-sided simple closed curve µ on N at one point and let δ be g,n the boundary of N (α∪µ). Then we have Ng,n Y2 =tε, µ,α δ where ε is 1 or −1, and ε depends on the orientations of α and N (δ) (see Ng,n Figure 4). Lemma 2.10 follows from relations in Lemma 2.1, Lemma 2.8 and Lemma 2.9. Figure 4. IftheorientationsofαandN (δ)areasabove,then Ng,n we have Y2 =t . µ,α δ1 6 G.OMORI 2.3. Stukow’s finite presentation for M(N ). Let e : D′ ֒→ Σ for i = 1, g,n i 0 2,..., g+1 be smooth embeddings of the unit disk D′ ⊂C to a 2-sphere Σ such 0 that D :=e (D′) and D are disjoint for distinct 1≤i,j ≤g+1. Then we take a i i j model of N (resp. N ) as the surface obtained from Σ (resp. Σ −intD ) by g g,1 0 0 g+1 theblowupsonD ,...,D andwedescribetheidentificationof∂D bythex-mark 1 g i asinFigures5and6. Whenn∈{0,1},for1≤i <i <···<i ≤g,letγ 1 2 k i1,i2,...,ik bethesimpleclosedcurveonN asinFigure5. Thenwedefinethesimpleclosed g,n curves α := γ for i = 1, ..., g−1, β := γ and µ := γ (see Figure 6), i i,i+1 1,2,3,4 1 1 and the mapping classes a := t for i = 1, ..., g−1, b := t and y := Y . i αi β µ1,α1 Then the following finite presentation for M(N ) is obtained by Lickorish [10] g,n for (g,n) = (2,0), Stukow [14] for (g,n) = (2,1), Birman-Chillingworth [1] for (g,n)=(3,0)andTheorem3.1andProposition3.3in[15]forthe other(g,n)such that g ≥3 and n∈{0,1}. Figure 5. Simple closed curve γ on N . i1,i2,...,ik g,n Figure 6. Simple closed curves α1, ..., αg−1, β and µ1 on Ng,n. Theorem 2.11 ([10], [1], [14], [15]). For (g,n) = (2,0), (2,1) and (3,0), we have the following presentation for M(N ): g,n M(N ) = a ,y |a2 =y2 =(a y)2 =1 ∼=Z ⊕Z , 2 1 1 1 2 2 M(N2,1) = (cid:10)a1,y |ya1y−1 =a−11 , (cid:11) M(N3) = (cid:10)a1,a2,y |a1a2a1 =a(cid:11)2a1a2,y2 =(a1y)2 =(a2y)2 =(a1a2)6 =1 . If g ≥ 4 and (cid:10)n ∈ {0,1} or (g,n) = (3,1), then M(Ng,n) admits a presentati(cid:11)on with generators a1,...,ag−1,y, and b for g ≥4. The defining relations are (A1) [a ,a ]=1 for g ≥4, |i−j|>1, i j (A2) a a a =a a a for i=1,...,g−2, i i+1 i i+1 i i+1 (A3) [a ,b]=1 for g ≥4, i6=4, i (A4) a ba =ba b for g ≥5, 4 4 4 (A5) (a a a b)10 =(a a a a b)6 for g ≥5, 2 3 4 1 2 3 4 PRESENTATION FOR MAPPING CLASS GROUP 7 (A6) (a a a a a b)12 =(a a a a a a b)9 for g ≥7, 2 3 4 5 6 1 2 3 4 5 6 (A9a) [b ,b]=1 for g =6, 2 (A9b) [ag−5,bg−2]=1 for g ≥8 even, 2 where b =a , b =b and 0 1 1 bi+1 =(bi−1a2ia2i+1a2i+2a2i+3bi)5(bi−1a2ia2i+1a2i+2a2i+3)−6 for 1≤i≤ g−4, 2 (B1) y(a a a a ya−1a−1a−1a−1) = (a a a a ya−1a−1a−1a−1)y for g ≥ 2 3 1 2 2 1 3 2 2 3 1 2 2 1 3 2 4, (B2) y(a a y−1a−1ya a )y =a (a a y−1a−1ya a )a , 2 1 2 1 2 1 2 1 2 1 2 1 (B3) [a ,y]=1 for g ≥4, i=3,...,g−1, i (B4) a (ya y−1)=(ya y−1)a , 2 2 2 2 (B5) ya =a−1y, 1 1 (B6) byby−1 = {a a a (y−1a y)a−1a−1a−1}{a−1a−1(ya y−1)a a } for 1 2 3 2 3 2 1 2 3 2 3 2 g ≥4, (B7) [(a a a a a a a a ya−1a−1a−1a−1a−1a−1a−1a−1),b]=1 for g ≥6, 4 5 3 4 2 3 1 2 2 1 3 2 4 3 5 4 (B8) {(ya−1a−1a−1a−1)b(a a a a y−1)}{(a−1a−1a−1a−1)b−1(a a a a )} 1 2 3 4 4 3 2 1 1 2 3 4 4 3 2 1 ={(a−1a−1a−1)y(a a a )}{a−1a−1y−1a a }{a−1ya }y−1 for g ≥5, 4 3 2 2 3 4 3 2 2 3 2 2 (C1) (a1a2···ag−1)g =1 for g ≥4 even and n=0, (C2) [a ,ρ]=1 for g ≥4 and n=0, 1 where ρ=(a1a2···ag−1)g for g odd and ρ=(y−1a2a3···ag−1ya2a3···ag−1)g−22y−1a2a3···ag−1 for g even, (C3) ρ2 =1 for g ≥4 and n=0, (C4) (y−1a2a3···ag−1ya2a3···ag−1)g−21 =1 for g ≥4 odd and n=0, where [x ,x ]=x x x−1x−1. 1 2 1 2 1 2 3. Presentation for M(N ) g,n The main theorem in this paper is as follows: Theorem 3.1. For g ≥1 and n∈{0,1}, M(N ) has the following presentation: g,n generators: {t |c: two-sided s.c.c. on N } c g,n ∪{Y |µ: one-sided s.c.c. on N , α: s.c.c. on N , |µ∩α|=1}. µ,α g,n g,n Denote the generating set by X. relations: (0) t =1 when c bounds a disk or a M¨obius band in N , c g,n (I) All the braid relations (i) ft f−1 =tεf(c) for f ∈X, c f(c) (ii) fY f−1 =Yεf(α) for f ∈X, ( µ,α f(µ),f(α) (II) All the 2-chain relations, (III) All the lantern relations, (IV) All the relations in Lemma 2.9, i.e. Y =Y Y , µ,αβ µ,α µ,β (V) All the relations in Lemma 2.8, i.e. Y =tεδ1tεδ2. µ,α δ1 δ2 In (I) and (IV) one can substitute the right hand side of (V) for each generator Y with one-sided α. Then one can remove the generators Y with one-sided α µ,α µ,α and relations (V) from the presentation. 8 G.OMORI We denote by G the group which has the presentation in Theorem 3.1. Let ι : Σ ֒→ N be a smooth embedding and let G′ be the group whose pre- h,m g,n sentation has all Dehn twists along simple closed curves on Σ as genera- h,m tors and Relations (0′), (I′), (II) and (III) in Theorem 2.5. By Theorem 2.5, M(Σ ) is isomorphic to G′, and we have the homomorphism G′ → G de- h,m fined by the correspondence of t to tει(c), where ε = 1 if the restriction c ι(c) ι(c) ι|NΣh,m(c) : NΣh,m(c) → NNg,n(ι(c)) is orientation preserving, and ει(c) = −1 if the restriction ι|NΣh,m(c) : NΣh,m(c) → NNg,n(ι(c)) is orientation reversing. Then we remark the following. Remark 3.2. The composition ι∗ : M(Σh,m) → G of the isomorphism M(Σ ) → G′ and the homomorphism G′ → G is a homomorphism. In par- h,m ticular, if a product tεc11tεc22···tεckk of Dehn twists along simple closed curves c1, c2, ...,c onaconnectedcompactorientablesubsurfaceofN isequaltotheidentity k g,n map in the mapping class group of the subsurface, then tε1tε2···tεk is equal to 1 c1 c2 ck in G. That means such a relation tε1tε2···tεk = 1 is obtained from Relations (0), c1 c2 ck (I), (II) and (III). Set X± :=X ∪{x−1 |x∈X}. By Relation (I), we have the following lemma. Lemma 3.3. For f ∈G, suppose that f =f f ...f , where f , f , ..., f ∈X±. 1 2 k 1 2 k Then we have (i) ft f−1 =tεf(c), c f(c) (ii) fY f−1 =Yεf(α) . ( µ,α f(µ),f(α) The next lemma follows from an argument of the combinatorial group theory (for instance, see [7, Lemma 4.2.1, p42]). Lemma 3.4. For groups Γ, Γ′ and F, a surjective homomorphism π :F →Γ and a homomorphism ν : F → Γ′, we define a map ν′ : Γ → Γ′ by ν′(x) := ν(x) for x∈Γ, where x∈F is a lift of x with respect to π (see the diagram below). Then if kerπ ⊂kerν, ν′ is well-defined and a homomorphism. e e F π (cid:15)(cid:15)(cid:15)(cid:15) ❅❅❅❅❅❅ν❅❅ Γ❴ ❴ ❴//Γ′ ν′ Proof of Theorem 3.1. M(N ) and M are trivial (see [2]). Assume g ≥ 2 and 1 n ∈ {0,1}. Then we obtain Theorem 3.1 if M(N ) is isomorphic to G. Let g,n ϕ : G → M(N ) be the surjective homomorphism defined by ϕ(t ) := t and g,n c c ϕ(Y ):=Y . µ,α µ,α Set X0 := {a1,...,ag−1,b,y} ⊂ M(Ng,n) for g ≥ 4 and X0 := {a1,...,ag−1,y} ⊂ M(Ng,n) for g = 2, 3. Let F(X0) be the free group which is freely generated by X and let π :F(X )→M(N ) be the natural projection 0 0 g,n (by Theorem 2.11). We define the homomorphism ν : F(X ) → G by ν(a ) := a 0 i i for i=1, ..., g−1, ν(b):=b and ν(y):=y, and a map ψ =ν′ :M(N )→G by g,n ψ(a±1):=a±1 fori=1,...,g−1,ψ(b±1):=b±1,ψ(y±1):=y±1 andψ(f):=ν(f) i i for the other f ∈ M(N ), where f ∈ F(X ) is a lift of f with respect to π (see g,n 0 the diagram below). e e PRESENTATION FOR MAPPING CLASS GROUP 9 F(X ) 0 π (cid:15)(cid:15)(cid:15)(cid:15) ●●●●●●ν●●●●## M(N )❴ ❴ ❴//G g,n ψ Ifψ isahomomorphism,ϕ◦ψ =idM(Ng,n) bythedefinitionofϕandψ. Thusit is sufficient for proving that ψ is isomorphism to show that ψ is a homomorphism and surjective. 3.1. Proof that ψ is a homomorphism. M(N ) and M(N ) are trivial (see 1 1,1 [2, Theorem3.4]). For (g,n)∈{(2,0),(2,1),(3,0)},relationsofthe presentationin Theorem 2.11 are obtained from Relations (0), (I), (II), (III), (IV) and (V), clearly. Thus by Lemma 3.4, ψ is a homomorphism. Assume g ≥4 or (g,n)=(3,1). By Lemma 3.4, if the relations of the presenta- tion in Theorem 2.11 are obtained from Relations (0), (I), (II), (III), (IV) and (V), then ψ is a homomorphism. Thegroupgeneratedbya1,...,ag−1andbwithRelations(A1)-(A9b)asdefining relations is isomorphic to M(Σ ) (resp. M(Σ )) for g = 2h+1 (resp. g = h,1 h,2 2h + 2) by Theorem 3.1 in [13], and Relations (A1)-(A9b) are relations on the mapping class group of the orientable subsurface NNg,n(α1 ∪···∪αg−1) of Ng,n. Hence Relations (A1)-(A9b) are obtained from Relations (0), (I), (II) and (III) by Remark 3.2. Stukow [15] gave geometric interpretations for Relations (B1)-(B8) in Section 4 in [15]. By the interpretation, Relations (B1), (B2), (B3), (B4), (B5), (B7) are obtained from Relations (I) (use Lemma 3.3), Relation (B6) is obtained from Re- lations (0), (I), (III), (IV) and (V) (use Lemma 2.10 and Lemma 3.3), and Rela- tion (B8) is obtained from Relations (I), (IV) and (V) (use Lemma 3.3). Thus ψ is a homomorphism when n=1. We assume n = 0. By Remark 3.2, k-chain relations are obtained from Rela- tions (0), (I), (II) and (III) for each k. Relation (C1) is interpreted in G as follows. (a1a2···ag−1)g (0),(I)=,(II),(III)tγ1,2,...,gt−γ11,2,...,g =1. Thus Relation (C1) is obtained from Relations (0), (I), (II) and (III). Relation (C2) is obtained from Relations (I) by Lemma 3.3, clearly. When g is odd, by using the (g−1)-chain relation, Relation (C3) is interpreted in G as follows. ρ2 =(a1a2···ag−1)2g (0),(I)=,(II),(III)tε∂NNg(γ1,2,...,g) (=0)1, where ε is 1 or −1. Note that N (γ ) is a Mo¨bius band in N . Thus Rela- Ng 1,2,...,g g tion (C3) is obtained from Relations (0), (I), (II) and (III) when g is odd. When g is even, we rewrite the left-hand side ρ2 of Relation (C3) by braid relations. Set A:=a2a3···ag−1. Note that Y A2Y A−2 =Y µ1,γ1,2,3 µ1,γ1,2,...,2i−1 µ1,γ1,2,...,2i+1 for i=2, ..., g−2 by Relation (I), (IV) and then we have 2 ρ = y−1A(yAy−1A)g−22 10 G.OMORI (=I) y−1A(ya2y−1a3···ag−1A)g−22 = y−1A(y(a2y−1a−21)A2)g−22 (I)=,(IV) y−1A(Yµ1,γ1,2,3A2)g−22. = y−1AY A2···Y A2Y A2Y A2 µ1,γ1,2,3 µ1,γ1,2,3 µ1,γ1,2,3 µ1,γ1,2,3 = y−1AY A2···Y A2Y A2Y A−2A4 µ1,γ1,2,3 µ1,γ1,2,3 µ1,γ1,2,3 µ1,γ1,2,3 (I)=,(IV) y−1AY A2···Y A2Y A4 µ1,γ1,2,3 µ1,γ1,2,3 µ,γ1,2,3,4,5 = y−1AY A2···Y A2Y A−2A6 µ1,γ1,2,3 µ1,γ1,2,3 µ,γ1,2,3,4,5 (I)=,(IV) y−1AY A2···Y A6 µ1,γ1,2,3 µ1,γ1,2,3,4,5,6,7 . . . (I)=,(IV) y−1AY Ag−2 µ1,γ1,2,...,g−1 = y−1·AY A−1·Ag−1 µ1,γ1,2,...,g−1 (I)=,(IV) Y Ag−1. µ1,γ1,2,...,g Since Y commutes with a for i=2, ..., g−1,and∂N (µ ∪γ )= µ1,γ1,2,...,g i Ng 1 1,2,...,g ∂NNg(α2∪···∪αg−1) (see Figure 7), we have ρ2 = Y Ag−1Y Ag−1 µ1,γ1,2,...,g µ1,γ1,2,...,g (=I) Y2 A2g−2 µ1,γ1,2,...,g (0),(I)=,(II),(III) Yµ21,γ1,2,...,gt∂NNg(α2∪···∪αg−1) Lem=.2.10 t−∂N1Ng(α2∪···∪αg−1)t∂NNg(α2∪···∪αg−1) = 1. Recall that the relations in Lemma 2.10 are obtained from Relations (0), (IV) and (V). Thus Relation (C3) is obtained from Relations (0), (I), (II), (III), (IV) and (V) when g is even. Figure 7. Simple closed curve ∂NNg(α2∪···∪αg−1) on Ng. Finally, we alsorewrite the left-hand side (y−1a2a3···ag−1ya2a3···ag−1)g−21 of Relation (C4) by braid relations. Remark that g is odd. For 1 ≤ i < i < ··· < 1 2 i ≤g,wedenotebyγ′ thesimpleclosedcurveonN asinFigure8. Note k i1,i2,...,ik g,n that Yµ1,γ1′,2,3A2Yµ1,γ1′,2,...,2i−1A−2 =Yµ1,γ1′,2,...,2i+1

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