Description:This workbook has been designed for students 11-18 years of the middle and high school, but it is very useful to parents to help and support their children in math and algebra study.The book covers all the topics of grades 6-9 with explanation of rules, properties, examples of solutions, problems to solve and related solutions with step by step explanation.The goal of this workbook is to provide an effective method to improve the young students math skills for solving practical aspects in different cases, applying the proper math rules and properties with useful tricks and simplifications too.How to use the workbook:Each chapter covers a specific topic and it contains three paragraphs:Rules & Properties: the reader will find the explanation of the properties, how to apply them, how to solve problems and expressions by providing many examples, tricks etcProblems to solve: the reader will find the exercises to solve, with spaces to insert his solution, so he can check if it is right by comparing it with the exact one in the next paragraph “Problems Solutions”.Problems Solutions: For each exercise in the previous paragraph, (problems to solve), the reader will find the right solution with the related step by step explanation.Chapters of the book :Divisibility of NumbersIntegersFactorizationPrime and Composite NumbersPrime FactorizationGreatest Common Factor (GCF)Least Common Multiple (LCM)FractionsDecimalsPercentsInteger ExponentsOrder Of Operation (PEMDAS)Rational ExponentsPolynomialsBinomialsRadicalsRadical ExpressionsRational ExpressionsIntro to EquationsIntro to InequalitiesIntro to Coordinate PlanHereafter some examples about problem solving and explanation:Problem 1:Subtract polynomial (3a² - a +5) from (5a² +3a -6)Solution: (5a² + 3a - 6) - (3a² -a +5)Eliminate the parenthesis remembering that the sign minus (-) changes the signs of all terms within the parenthesis:5a² +3a -6 - 3a² + a -5Now you can execute the algebraic sum by grouping first the similar monomials:(5-3)a² + (3+1)a + (-6 -5) = 2a² + 4a -11Problem 2: Solve the Equation - ( 7 - 3x) = -2(1-x) + 8x + 3xSolution:1) Eliminate the parenthesis: -7 + 3x = -2 + 2x + 8x + 3x2) Isolate the terms with x on the left side of equation (remember to change the sign for eaxh term moved from right to the left and viceversa) and constants on the right side3x -2x -8x -3x = 7 -24) execute the algebraic sum on both sides of the equation- 10x = 55) Change the signs in both sides to get a positive term with x10x = -55) Divide both terms by 1010x / 10 = - 5/106) x = - 1/2::