WRITING REACTION MECHANISMS IN ORGANIC CHEMISTRY THIRD EDITION KENNETH A. SAVIN EliLillyandCompany ButlerUniversity AMSTERDAM(cid:129)BOSTON(cid:129)HEIDELBERG(cid:129)LONDON NEWYORK(cid:129)OXFORD(cid:129)PARIS(cid:129)SANDIEGO SANFRANCISCO(cid:129)SINGAPORE(cid:129)SYDNEY(cid:129)TOKYO AcademicPressisanimprintofElsevier AcademicPressisanimprintofElsevier 225WymanStreet,Waltham,MA02451,USA 525BStreet,Suite1800,SanDiego,CA92101-4495,USA 32JamestownRoad,LondonNW17BY,UK TheBoulevard,LangfordLane,Kidlington,OxfordOX51GB,UK Thirdedition2014 Copyright©2014,2000,1992ElsevierInc.Allrightsreserved. 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Acknowledgments for the Third Edition Forthe third edition ofthis text, the focus I am indebted to the authors of the first on the how of writing organic reaction two editions of this book, Philippa Solomon mechanisms remains the foremost objective. and Audrey Miller, for the original con- The book has been expanded with a new ceptualarchitectureandcontent.Ihavetried chapter focused on oxidation and reduction to hold to the original philosophy and mechanisms as well as new material organizational design of the material from throughoutthetext.Althoughoxidationand thepreviousversions.Ifeelitispresentedin reduction reactions were considered for pre- the best way possible for a text used as a viousversionsofthetext,itwasdecidedthat “teaching book”. this important and yet often under repre- IamgratefulforthehelpIreceivedfromthe sented topic should be included to better reviewers who took the time to read and equipthereader.Thisnewchapterissetupto improve the text. Their suggestions go far allowstudentstoseehowourunderstanding beyond the grammatical corrections, but are of mechanisms has developed and apply expressive of a group of individuals who are whattheyhavelearnedintheearlierchapters committed to learning and have a bias for ofthebooktoagreaternumberofsituations doing chemistry, not just talking about it. In and more sophisticated systems. We have particularIwouldliketothankAlisonCamp- added new problems throughout the text to bell for her contributions to the discussions update and provide illustrative examples to aroundmetals,DougKjellwhoreviewedand the text that will aid in identifying key sit- suggested problems, LuAnne McNulty for uationsandpatterns.Theoxidationschapter lookingatthetextfromboththeperspectiveof also allows us to touch on other mechanistic astudentaswellasfromthestandpointofthe topics including organometallics, stereo- professor, and Andrea Frederick and Nick chemistry, radiolabeling, and a more philo- Magnus for their key discussion around the sophical view of the mechanistic models we orderinwhichthematerialispresented,how areapplying.Thisnewchapter,aswellasthe oxidation number should be described, and changestothepreviouschapters,hasallbeen how to draw connections to topics that the done with consideration to the ultimate studentshavealreadybeenexposedto. lengthofthebookandthegoalofkeepingit I would, of course, also like to thank my portableandreasonableinlength. family. Mywife Lisa and myboys Zachand Additional references for the examples, Cory, for their support and prodding problems, and key topics have been expan- throughallthe long evenings and weekends ded with an eye toward the practical spent in developing the manuscript and for application of the concepts to yet to be being tolerant of the time together we have encountered challenges. missed as a result of this effort. vii C H A P T E R 1 d Introduction Molecular Structure and Reactivity Reaction mechanisms offer us insights into how molecules react, enable us to manipu- late the course of known reactions, aid us in predicting the course of known reactions us- ing new substrates, and help us to develop new reactions and reagents. In order to understand and write reaction mechanisms, it is essential to have a detailed knowledge ofthestructuresofthemoleculesinvolvedandtobeabletonotatethesestructuresunam- biguously. In this chapter, we present a review of the fundamental principles relating to molecular structure and of the ways to convey structural information. A crucial aspect ofstructurefromthemechanisticviewpointisthedistributionofelectrons,sothischapter outlines how to analyze and depict electron distributions. Mastering the material in this chapter will provide you with the tools you need to propose reasonable mechanisms and to convey these mechanisms clearly to others. 1. HOW TO WRITE LEWIS STRUCTURES AND CALCULATE FORMAL CHARGES The ability to construct Lewis structures is fundamental to writing or understanding organic reaction mechanisms. It is particularly important because lone pairs of electrons frequently arecrucial to the mechanism but often areomitted from structuresappearing in the chemical literature. There are two methods commonly used to show Lewis structures. One shows all elec- trons as dots. The other shows all bonds (two shared electrons) as lines and all unshared electrons as dots. WritingReactionMechanismsinOrganicChemistry http://dx.doi.org/10.1016/B978-0-12-411475-3.00001-4 1 Copyright(cid:1)2014ElsevierInc.Allrightsreserved. 2 1. INTRODUCTIONdMOLECULARSTRUCTUREANDREACTIVITY A. Determining the Number of Bonds HINT 1.1 TofacilitatethedrawingofLewisstructures,estimatethenumberofbonds. For a stable structurewith aneven numberof electrons, the numberof bonds is given by the equation: ðElectronDemand(cid:2)ElectronSupplyÞ=2 ¼ NumberofBonds The electrondemand is two forhydrogen and eight for all other atoms usually considered in organicchemistry.(Thetendencyofmostatomstoacquireeightvalenceelectronsisknownasthe octetrule.)ForelementsingroupIIIA(e.g.,B,Al,Ga),theelectrondemandissix.Otherexceptions arenoted,astheyarise,inexamplesandproblems. For neutral molecules, the contribution of each atom to the electron supply is the number of valence electrons of the neutral atom. (This is the same as the group number of the element when the periodic table is divided into eight groups.) For ions, the electron supply is decreased by one for each positive charge of a cation and is increased by one for each negative charge of an anion. Usetheestimatednumberofbondstodrawthenumberoftwo-electronbondsinyourstructure. Thismayinvolvedrawinganumberofdoubleandtriplebonds(seethefollowingsection). B. Determining the Number of Rings and/or p Bonds (Degree of Unsaturation) Thetotalnumberofringsand/orpbondscanbecalculatedfromthemolecularformula, bearinginmindthatinanacyclicsaturatedhydrocarbonthenumberofhydrogensis2nþ2, wherenisthenumberofcarbonatoms.Eachtimearingorpbondisformed,therewillbe two fewerhydrogens needed to complete thestructure. HINT 1.2 Onthebasisofthemolecularformula,thedegreeofunsaturationforahydrocarboniscalculated as(2mþ2(cid:2)n)/2,wheremisthenumberofcarbonsandnisthenumberofhydrogens.Thenumber calculated is the number of rings and/or p bonds. For molecules containing heteroatoms, the degreeofunsaturationcanbecalculatedasfollows: Nitrogen:Foreachnitrogenatom,subtract1fromn. Halogens:Foreachhalogenatom,add1ton. Oxygen:Usetheformulaforhydrocarbons. Thismethodcannotbeusedformoleculesinwhichthereareatomslikesulfurandphosphorus whosevalenceshellcanexpandbeyondeight. 3 1. HOWTOWRITELEWISSTRUCTURESANDCALCULATEFORMALCHARGES EXAMPLE 1.1. CALCULATE THE NUMBER OF RINGS AND/OR p BONDS CORRESPONDING TO EACH OF THE FOLLOWING MOLECULAR FORMULAS a. C H Cl Br 2 2 2 2 There are a total of four halogen atoms. Using the formula (2mþ2(cid:2)n)/2, we calculate the degreeofunsaturationtobe(2(2)þ2(cid:2)(2þ4))/2¼0. b. C H N 2 3 Thereisonenitrogenatom,sothedegreeofunsaturationis(2(2)þ2(cid:2)(3(cid:2)1))¼2. C. Drawing the Lewis Structure Start by drawing the skeleton of the molecule, using the correct number of rings or p bonds, and then attach hydrogen atoms to satisfy the remaining valences. Fororganic mol- ecules, the carbon skeleton frequently isgiven in anabbreviated form. Oncetheatomsandbondshavebeenplaced,addlonepairsofelectronstogiveeachatom a total of eight valence electrons. When this process is complete, there should be two elec- trons for hydrogen; six for B, Al, or Ga; and eight for all other atoms. The total number of valence electrons for each element in the final representation of a molecule is obtained by counting each electron around the element as one electron, even if the electron is shared with another atom. (This should not be confused with counting electrons for charges or formalcharges;seeSection1.D.)Thenumberofvalenceelectronsaroundeachatomequals the electron demand. Thus, when the number of valence electrons around each element equals the electrondemand,the numberof bonds willbeas calculated in Hint 1.1. Atomsofhigheratomicnumbercanexpandthevalenceshelltomorethaneightelectrons. These atoms include sulfur, phosphorus, and the halogens (exceptfluorine). HINT 1.3 WhendrawingLewisstructures,makeuseofthefollowingcommonstructuralfeatures. 1. Hydrogenisalwaysontheperipherybecauseitformsonlyonecovalentbond. 2. Carbon,nitrogen,andoxygenexhibitcharacteristicbondingpatterns.Intheexamplesthat follow,theRgroupsmaybehydrogen,alkyl,orarylgroups,oranycombinationofthese.These substituentsdonotchangethebondingpatterndepicted. (a) Carboninneutralmoleculesusuallyhasfourbonds.Thefourbondsmayallbesbonds,or theymaybevariouscombinationsofsandpbonds(i.e.,doubleandtriplebonds). 4 1. INTRODUCTIONdMOLECULARSTRUCTUREANDREACTIVITY Thereareexceptionstotherulethatcarbonhasfourbonds.TheseincludeCO,isonitriles (RNC),andcarbenes(neutralcarbonspecieswithsixvalenceelectrons;seeChapter4). (b) Carbonwithasinglepositiveornegativechargehasthreebonds. (c) Neutralnitrogen,withtheexceptionofnitrenes(seeChapter4),hasthreebondsandalone pair. (d) Positivelychargednitrogenhasfourbondsandapositivecharge;exceptionsarenitrenium ions(seeChapter4). (e) Negativelychargednitrogenhastwobondsandtwolonepairsofelectrons. (f) Neutraloxygenhastwobondsandtwolonepairsofelectrons. (g) Oxygeneoxygenbondsareuncommon;theyarepresentonlyinperoxides,hydroperoxides, anddiacylperoxides(seeChapter5).Theformula,RCO R,impliesthefollowingstructure: 2 5 1. HOWTOWRITELEWISSTRUCTURESANDCALCULATEFORMALCHARGES (h) Positiveoxygenusuallyhasthreebondsandalonepairofelectrons;exceptionsarethevery unstableoxeniumions,whichcontainasinglebondtooxygenandtwolonepairsof electrons. 3. Sometimesaphosphorusorsulfuratominamoleculeisdepictedwith10electrons.Because phosphorusandsulfurhavedorbitals,theoutershellcanbeexpandedtoaccommodatemorethan eightelectrons.Iftheshell,andthereforethedemand,isexpandedto10electrons,onemorebond willbecalculatedbytheequationusedtocalculatethenumberofbonds.SeeExample1.5. Intheliterature,aformulaofteniswrittentoindicatethebondingskeletonforthemolecule.This severelylimits,oftentojustone,thenumberofpossiblestructuresthatcanbewritten. EXAMPLE 1.2. THE LEWIS STRUCTURE FOR ACETALDEHYDE, CH CHO 3 ElectronSupply ElectronDemand 2C 8 16 4H 4 8 1O 6 8 18 32 Theestimatednumberofbondsis(32(cid:2)18)/2¼7. The degree of unsaturation is determined by looking at the corresponding saturated hydro- carbonC H .BecausethemolecularformulaforacetaldehydeisC H Oandtherearenonitrogen, 2 6 2 6 phosphorus, or halogen atoms, the degree of unsaturation is (6(cid:2)4)/2¼1. There is either one doublebondoronering. ThenotationCH CHOindicatesthatthemoleculeisastraight-chaincompoundwithamethyl 3 group,sowecanwrite Wecompletethestructurebyaddingtheremaininghydrogenatomandtheremainingvalence electronstogive 6 1. INTRODUCTIONdMOLECULARSTRUCTUREANDREACTIVITY NotethatifwehadbeengivenonlythemolecularformulaC H O,asecondstructurecouldbe 2 6 drawn A third possible structure differs from the first only in the position of the double bond and a hydrogenatom. Thisenolstructureisunstablerelativetoacetaldehydeandisnotisolable,althoughinsolution smallquantitiesexistinequilibriumwithacetaldehyde. D. Formal Charge Eveninneutralmolecules,someoftheatomsmayhavecharges.Becausethetotalcharge ofthemoleculeiszero,thesechargesarecalledformalchargestodistinguishthemfromionic charges. Formalchargesareimportantfortworeasons.First,determiningformalchargeshelpsus pinpoint reactive sites within the molecule and can help us in choosing plausible mecha- nisms.Also,formalchargesarehelpfulindeterminingtherelativeimportanceofresonance forms (seeSection 5). HINT 1.4 Tocalculateformalcharges,usethecompletedLewisstructureandthefollowingformula: FormalCharge ¼ NumberofValenceShellElectrons(cid:2)ðNumberofUnsharedElectrons þHalftheNumberofSharedElectronsÞ The formal charge is zero if the number of unshared electrons, plus the number of shared electronsdividedbytwo,isequaltothenumberofvalenceshellelectronsintheneutralatom(as ascertainedfromthegroupnumberintheperiodictable).Asthenumberofbondsformedbythe atomincreases,sodoestheformalcharge.Thus,theformalchargeofnitrogenin(CH ) Niszero, 33 buttheformalchargeonnitrogenin(CH ) Nþisþ1. 34 Note: An atom always “owns” all unshared electrons. This is true both when counting the number of electrons for determining formal charge and in determining the number of valence electrons. However, in determining formal charge, an atom “owns” half of the bonding electrons, whereas in determining the number of valence electrons, the atom “owns” all the bonding electrons. 7 1. HOWTOWRITELEWISSTRUCTURESANDCALCULATEFORMALCHARGES EXAMPLE 1.3. CALCULATION OF FORMAL CHARGE FOR THE STRUCTURES SHOWN (a) Theformalchargesarecalculatedasfollows: Hydrogen 1$(no.ofvalenceelectrons)(cid:2)2/2$(2bondingelectronsdividedby2)¼0 Carbon 4$(no.ofvalenceelectrons)(cid:2)8/2$(8bondingelectronsdividedby2)¼0 Nitrogen 5(cid:2)8/2$(8bondingelectrons)¼þ1 Therearetwodifferentoxygenatoms: Oxygen(doublebonded) 6(cid:2)4$(unsharedelectrons)(cid:2)4/2$(4bondingelectrons)¼0 Oxygen(singlebonded) 6(cid:2)6$(unsharedelectrons)(cid:2)2/2$(2bondingelectrons)¼(cid:2)1. (b) Thecalculationsforcarbonandhydrogenarethesameasthoseforpart(a). Formalchargeforeachoxygen: 6(cid:2)6(cid:2)(2/2)¼(cid:2)1 Formalchargeforsulfur: 6(cid:2)0(cid:2)(8/2)¼þ2 EXAMPLE 1.4. WRITE POSSIBLE LEWIS STRUCTURES FOR C H N 2 3 ElectronSupply ElectronDemand 3H 3 6 2C 8 16 1N 5 8 16 30 Theestimatednumberofbondsis(30e16)/2¼7.
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