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Solution of Mechanics - Part 2. Lesson 9th to 13th PDF

82 Pages·2013·24.61 MB·English
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Preview Solution of Mechanics - Part 2. Lesson 9th to 13th

Solutions of Mechanics Part-II Lesson 9th to 13th By DC Pandey Mechanics of Rotational Motion = Introductory Exercise 9.1 1, The mass distribution is at minimum separation from the diagonal passing ‘through entre to opposite corners ofthe tube, 0, moment of inertia fe minimum Shout that ai. mi ae while Ly = mr? =: (oy = 2 +22? + mat) Mechanics of Rotational Motion | 9 6. 10. ‘The disk with smaller dengity will have larger radius and as T=3 67, eo the ‘isk with larger radius will have higher ‘moment of inertia, = Introductory Exercise 9.2 1. of =of +200 10 8. a(x 49? +2548" 43% 47? =5Nm ft A) + 50% 08 + (100% 50" +99 49% + 08 488 4 BI) = 100% 50" + 100% 494 +... + 100% = 100018 +28 +3? +... +50") 00 50160 + D400 + D 6 50% 51% 100% 101, 4: | Mechanics-2 6 a. Lom@xd-mGisy) x (00s 45°i + vsin 45°5) =f 2x19 dt =10%# tot Mechanics of Rotational Motion | § 5. It depends upon the distance, velocity 4 ‘and angle from the axis, which may not ‘ven zero from a different point. = Introductory Exercise 9.4 1 u sin ae, = Introductory Exercise 9.6 " 2 6 | Mechanics-2 3. fs ‘As the torque due to applied force is ‘anti-clockwise, so the point of contact ‘tos to slip rightwards and fiction tries ‘tw provent it and so acts lftwards As during rolling down, friction acts ‘upward which exerts a torque, thus the ‘angular momentum ofthe system is not ‘conserved. Even if we take axis of rotation at point of contact, then ‘component of weight exerts torque, 80, statement is false ‘Force of fretion wil be zero, only when Mechanics of Rotational Motion | 7 tan 0>y ‘And for toppling, img sin 05 > mg cos 0% tan 0>1 (@) Cube will slide before toppling sf tan 0<l, Ley <land (©) Cube will topple before sliding if tan 0>1,4e,h>1 2 : F20 ie, oven a lightest amount of fore can Iniate motion af the dk 4 Accleration of point of contact is zoo Gy when thers unforn pure rolling ind no alipping = Introductory Exercise 9.8 foruonta pane,f =O L “ Impulse, I, ‘Angular Impulse, For shiding ing sin 0 > mg con 9 AIEEE Corner = Subjective Questions (Level 1) 2. 1=1, +1, 1. = 1G? +24) 4268 +48 8 | Mechanics-2 4 wey 10. 1 T=myl + myt Substituting the values we get, mim) 2 im +m, dl =dmx? = 24), de =3* (ax +P) de at? + fa?) de Jia +82) ae Lye ge roid 8. In socond!s clock, it takes 60 s by the ‘seconds hand to rotate by 2m. Evade, 0 2.608 60° x 01 - 10 0.25 -9% 0.25 19 _24-19 166 _ 83 05-12 188 83 Nm 20 1 29 _ 2x 50x28 at =p q = 28 2850038 2 ee =Bnradle? Srrad/s® x 5s ~40radle 1B. 0-0, +0, +05 aff tam tat, of hy (f, +) =2x56+2=70rad 2 20. ona, +t = -20rads 20 rad/s —2rad/s* x t pa) 7 (As KE= Lio! is same foro) monat-tat Ro} 1 4ug 9R° ad, “4ug 2° BR 167g? ahahaha Cr 28. @t-Te and 0-05 ot art

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