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Preview Singular stochastic equations on Hilbert spaces: Harnack inequalities for their transition semigroups

Singular Stochastic Equations on Hilbert Spaces: Harnack Inequalities for their Transition Semigroups 9 0 0 Giuseppe Da Prato , 2 ∗ n Scuola Normale Superiore di Pisa, Italy a J 3 Michael R¨ockner † 1 Faculty of Mathematics, University of Bielefeld, Germany ] R and P Department of Mathematics and Statistics, . h Purdue University, W. Lafayette, 47906, IN, U. S. A. t a m [ Feng-Yu Wang ‡ 2 School of Math. Sci. and Lab. Math Com. Sys. v 1 Beijing Normal University, 100875, China 6 0 and 2 . Department of Mathematics, Swansea University, 1 1 Singleton Park, SA2 8PP, Swansea, UK 8 0 : v i X Abstract r a We consider stochastic equations in Hilbert spaces with singular drift in the framework of [7]. We prove a Harnack inequality (in the senseof [18])forits transition semigroup andexploitits consequences. ∗Supported in part by “Equazioni di Kolmogorov” from the Italian “Ministero della Ricerca Scientifica e Tecnologica” †Supported by the DFG through SFB-701 and IRTG 1132, by nsf-grant 0603742 as well as by the BIBOS-ResearchCenter. ‡The corresponding author. Supported in part by WIMCS, Creative Research Group Fund of the National Natural Science Foundation of China (No. 10721091) and the 973- Project. 1 In particular, we prove regularizing and ultraboundedness properties of the transition semigroup as well as that the corresponding Kol- mogorov operator has at most one infinitesimally invariant measure µ (satisfying some mild integrability conditions). Finally, we prove existence of such a measure µ for non-continuous drifts. 2000 Mathematics Subject Classification AMS: 60H15, 35R15, 35J15, Key words: Stochasticdifferential equations, Harnack inequality, monotone coefficients, Yosida approximation, Kolmogorov operators. 1 Introduction, framework and main results In this paper we continue our study of stochastic equations in Hilbert spaces withsingulardriftthroughitsassociatedKolmogorovequationsstartedin[7]. The main aim is to prove a Harnack inequality for its transition semigroup in the sense of [18] (see also [1, 16, 19] for further development) and exploit its consequences. See also [14] for an improvement of the main results in [16] concerning generalized Mehler semigroups. To describe our results more precisely, let us first recall the framework from [7]. Consider the stochastic equation dX(t) = (AX(t)+F(X(t)))dt+σdW(t) (1.1)  X(0) = x H.  ∈ Here His a real separable Hilbert space with inner product , and norm h· ·i , W = W(t), t 0, is a cylindrical Brownian motion on H defined on | · | ≥ a stochastic basis (Ω,F,(F ) ,P) and the coefficients satisfy the following t t≥0 hypotheses: (H1) (A,D(A)) is the generator of a C -semigroup, T = etA, t 0, on H 0 t ≥ and for some ω R ∈ Ax,x ω x 2, x D(A). (1.2) h i ≤ | | ∀ ∈ (H2) σ L(H) (the space of all bounded linear operators on H) such that ∈ σ is positive definite, self-adjoint and 2 ∞ (i) (1+t−α) T σ 2 dt < for some α > 0, where denotes the k t kHS ∞ k·kHS Z0 norm on the space of all Hilbert–Schmidt operators on H. (ii) σ−1 L(H). ∈ (H3) F : D(F) H 2H is an m-dissipative map, i.e., ⊂ → u v,x y 0, x,y D(F), u F(x), v F(y), h − − i ≤ ∀ ∈ ∈ ∈ (“dissipativity”) and Range (I F) := (x F(x)) = H. − − x∈D(F) [ Furthermore, F (x) F(x), x D(F), is such that 0 ∈ ∈ F (x) = min y . 0 | | y∈F(x)| | Here we recall that for F as in (H3) we have that F(x) is closed, non empty and convex. The corresponding Kolmogorov operator is then given as follows: Let E (H) denote the linear span of all real parts of functions of the form ϕ = A eihh,·i, h D(A∗), where A∗ denotes the adjoint operator of A, and define for ∈ any x D(F), ∈ 1 L ϕ(x) = Tr (σ2D2ϕ(x))+ x,A∗Dϕ(x) + F (x),Dϕ(x) , ϕ E (H). 0 0 A 2 h i h i ∈ (1.3) Additionally, we assume: (H4) There exists a probability measure µ on H (equipped with its Borel σ-algebra B(H)) such that (i) µ(D(F)) = 1, (ii) (1+ x 2)(1+ F (x) )µ(dx) < , 0 | | | | ∞ ZH (iii) L ϕdµ = 0 for all ϕ E (H). 0 A ∈ ZH 3 Remark 1.1 (i) A measure for which the last equality in (H4) (makes sense and) holds is called infinitesimally invariant for (L ,E (H)). 0 A (ii) Since ω in (1.2) is an arbitrary real number we can relax (H3) by allowing that for some c (0, ) ∈ ∞ u v,x y c x y 2, x,y D(F), u F(x), v F(y). h − − i ≤ | − | ∀ ∈ ∈ ∈ We simply replace F by F c and A by A+c to reduce this case to (H3). − (iii) At this point we would like to stress that under the above assumptions (H1)-(H4) (and (H5) below) because F is merely measurable and σ is not 0 Hilbert-Schmidt, it is unknown whether (1.1) has a strong solution. (iv) Similarly as in [7] (see [7, Remark 4.4] in particular) we expect that (H2)(ii) can be relaxed to the condition that σ = ( A)−γ for some γ − ∈ [0,1/2]. However, some of the approximation arguments below become more involved. So, for simplicity we assume (H2)(ii). The following are the main results of [7] which we shall use below. Theorem 1.2 (cf. [6, Theorem 2.3 and Corollary 2.5]) Assume (H1), (H2)(i), (H3) and (H4). Then for any measure µ as in (H4) the op- erator (L ,E (H)) is dissipative on L1(H,µ), hence closable. Its closure 0 A (L ,D(L )) generates a C -semigroup Pµ, t 0, on L1(H,µ) which is µ µ 0 t ≥ Markovian, i.e., Pµ1 = 1 and Pµf 0 for all nonnegative f L1(H,µ) t t ≥ ∈ and all t > 0. Furthermore, µ is Pµ-invariant, i.e., t Pµfdµ = fdµ, f L1(H,µ). t ∀ ∈ ZH ZH Below B (H),C (H)denotetheboundedBorel-measurable, continuous func- b b tions respectively from H into R and denotes the usual norm on L(H). k·k Theorem 1.3 (cf. [6, Proposition 5.7]) Assume (H1)–(H4) hold. Then for any measure µ as in (H4) and H := supp µ (:=largest closed set of H 0 whose complement is a µ-zero set) there exists a semigroup pµ(x,dy), x H , t ∈ 0 t > 0, of kernels such that pµf is a µ-version of Pµf for all f B (H), t > 0, t t ∈ b where as usual pµf(x) = f(y)pµ(x,dy), x H . t t ∈ 0 ZH 4 Furthermore, for all f B (H), t > 0, x,y H b 0 ∈ ∈ e|ω|t pµf(x) pµf(y) f σ−1 x y (1.4) | t − t | ≤ √t 1 k k0k k| − | ∧ and for all f Lip (H) (:= all bounded Lipschitz functions on H) b ∈ pµf(x) pµf(y) e|ω|t f x y , t > 0, x,y H , (1.5) | t − t | ≤ k kLip| − | ∀ ∈ 0 and limpµf(x) = f(x), x H . (1.6) t→0 t ∀ ∈ 0 (Here f , f denote the supremum, Lipschitz norm of f respectively.) 0 Lip k k k k Finally, µ is pµ-invariant. t Remark 1.4 (i) Both results above have been proved in [7] on L2(H,µ) rather than on L1(H,µ), but the proofs for L1(H,µ) are entirely analogous. (ii) In [7] we assume ω in (H1) to be negative, getting a stronger estimate than (1.4) (cf. [7, (5.11)]). But the same proof as in [7] leads to (1.4) for arbitrary ω R (cf. the proof of [7, Proposition 4.3] for t [0,1]). Then by ∈ ∈ virtue of the semigroup property and since pµ is Markov we get (1.4) for all t t > 0. (iii) Theorem 1.3 holds in more general situations since (H2)(ii) can be relaxed (cf. [7, Remark 4.4] and [5, Proposition 8.3.3]). (iv) (1.4)above implies thatpµ, t > 0,isstrongly Feller, i.e., pµ(B (H)) t t b ⊂ C(H ) (=all continuous functions on H ). We shall prove below that under 0 0 the additional condition (H5) we even have pµ(Lp(H,µ)) C(H ) for all t ⊂ 0 p > 1 and that µ in (H4) is unique. However, so far we have not been able to prove that for this unique µ we have supp µ = H, though we conjecture (cid:3) that this is true. For the results on Harnack inequalities, in this paper we need one more condition. (H5) (i) (1+ω A,D(A)) satisfies the weak sector condition (cf. e.g. [12]), i.e., − there exists a constant K > 0 such that (1+ω A)x,y K (1+ω A)x,x 1/2 (1+ω A)y,y 1/2, x,y D(A). h − i ≤ h − i h − i ∀ ∈ (1.7) 5 (ii) There exists a sequence of A-invariant finite dimensional subspaces H D(A) such that ∞ H is dense in H. n ⊂ n=1 n S We note that if A is self-adjoint, then (H2) implies that A has a discrete spectrum which in turn implies that (H5)(ii) holds. Remark 1.5 Let (A,D(A)) satisfy (H1). Then the following is well known: (i) (H5) (i) is equivalent to the fact that the semigroup generated by (1+ ω A,D(A)) on the complexification HC of H is a holomorphic contraction − semigroup on HC (cf. e.g. [12, Chapter I, Corollary 2.21]). (ii) (H5) (i) is equivalent to (1+ω A,D(A)) being variational. Indeed, − let (E,D(E)) be the coercive closed form generated by (1 + ω A,D(A)) − (cf. [12, Chapter I, Section 2]) and (E,D(E)) be its symmetric part. Then define e V := D(E) with inner product E and V∗ to be its dual. (1.8) Then e V H V∗ (1.9) ⊂ ⊂ and 1+ω A : D(A) H has a natural unique continuous extension from − → V to V∗ satisfying all the required properties (cf. [12, Chapter I, Section 2, in particular Remark 2.5]). Now we can formulate the main result of this paper, namely the Harnack inequality for pµ, t > 0. t Theorem 1.6 Suppose (H1) (H5) hold and let µ be any measure as in − (H4) and pµ(x,dy) as in Theorem 1.3 above. Let p (1, ). Then for all t ∈ ∞ f B (H), f 0, b ∈ ≥ pω x y 2 (pµf(x))p pµfp(y)exp σ−1 2 | − | , t > 0, x,y H . t ≤ t k k (p 1)(1 e−2ωt) ∈ 0 (cid:20) − − (cid:21) (1.10) As consequences in the situation of Theorem 1.6 (i.e. assuming (H1)-(H5)) we obtain: Corollary 1.7 For all t > 0 and p (1, ) ∈ ∞ pµ(Lp(H,µ)) C(H ). t ⊂ 0 6 Corollary 1.8 µ in (H4) is unique. Because of this result below we write p (x,dy) instead of pµ(x,dy). t t Finally, we have Corollary 1.9 (i) For every x H , p (x,dy) has a density ρ (x,y) with 0 t t ∈ respect to µ and 1 ρ (x, ) p/(p−1) , x H , p (1, ). k t · kp ≤ exp σ−1 2 pω|x−y|2 µ(dy) ∈ 0 ∈ ∞ H −k k (1−e−2ωt) R h i (1.11) (ii) If µ(eλ|·|2) < for some λ > 2(ω 0)2 σ−1 2, then p is hyperbounded, t ∞ ∧ k k i.e. p < for some t > 0. t L2(H,µ)→L4(H,µ) k k ∞ Corollary 1.10 For simplicity, let σ = I and instead of (H1) assume that more strongly (A,D(A)) is self-adjoint satisfying (1.2). We furthermore as- sume that F L2(H,µ). 0 | | ∈ (i) There exists M B(H ), M D(F), µ(M) = 1 such that for every 0 ∈ ⊂ x M equation (1.1) has a pointwise unique continuous strong solution (in ∈ the mild sense see (4.11) below), such that X(t) M for all t 0 P-a.s.. ∈ ≥ (ii) Suppose there exists Φ C([0, )) positive and strictly increasing such ∈ ∞ that lim s−1Φ(s) = and s→∞ ∞ ∞ dr Ψ(s) := < , s > 0. (1.12) Φ(r) ∞ ∀ Zs If there exists a constant c > 0 such that F (x) F (y),x y c Φ( x y 2), x,y D(F), (1.13) 0 0 h − − i ≤ − | − | ∀ ∈ then p is ultrabounded with t λ(1+Ψ−1(t/4)) kptkL2(H,µ)→L∞(H,µ) ≤ exp (1 e−ωt/2)2 , t > 0, h − i holding for some constant λ > 0. Remark 1.11 We emphasize that since the nonlinear part F of our Kol- 0 mogorov operator is in general not continuous, it was quite surprising for us that in this infinite dimensional case nevertheless the generated semigroup P maps L1- functions to continuous ones as stated in Corollary 1.7. t 7 The proof that Corollary 1.9 follows from Theorem 1.6 is completely standard. So, we will omit the proofs and instead refer to [16], [19]. Corollary 1.7 is new and follows whenever a semigroup p satisfies the t Harnack inequality (see Proposition 4.1 below). Corollary1.8isnew. Since(1.10)impliesirreducibilityofpµ andCorollary t 1.7 implies that it is strongly Feller, a well known theorem due to Doob immediately implies that µ is the unique invariant measure for pµ, t > 0. pµ, t t however, depends on µ, so Corollary 1.8 is a stronger statement. Corollary 1.10 is also new. Theorem 1.6 as well as Corollaries 1.7, 1.8 and 1.10 will be proved in Section 4. In Section 3 we first prove Theorem 1.6 in case F is Lipschitz, 0 and in Section 2 we prepare the tools that allow us to reduce the general case to the Lipschitz case. In Section 5 we prove two results (see Theorems 5.2 and 5.4) on the existence of a measure satisfying (H4) under some additional conditions and present an application to an example where F is not contin- 0 uous. For a discussion of a number of other explicit examples satisfying our conditions see [7, Section 9]. 2 Reduction to regular F 0 Let F be as in (H3). As in [7] we may consider the Yosida approximation of F, i.e., for any α > 0 we set 1 F (x) := (J (x) x), x H, (2.1) α α α − ∈ where for x H ∈ J (x) := (I αF)−1(x), α > 0, α − and I(x) := x. Then each F is single valued, dissipative and it is well known α that limF (x) = F (x), x D(F), (2.2) α 0 α→0 ∀ ∈ F (x) F (x) , x D(F). (2.3) α 0 | | ≤ | | ∀ ∈ Moreover, F is Lipschitz continuous, so F is B(H)-measurable. Since F α 0 α is not differentiable in general, as in [7] we introduce a further regularization by setting F (x) := eβBF (eβBx+y)N (dy), α,β > 0, (2.4) α,β α 1 B−1(e2βB−1) 2 ZH 8 where B : D(B) H H is a self-adjoint, negative definite linear operator ⊂ → such that B−1 is of trace class and as usual for a trace class operator Q the measure N is just the standard centered Gaussian measure with covariance Q given by Q. F is dissipative, of class C∞, has bounded derivatives of all the orders α,β and F F pointwise as β 0. α,β α → → Furthermore, for α > 0 F (x) α,β c := sup | | : x H, β (0,1] < . (2.5) α 1+ x ∈ ∈ ∞ (cid:26) | | (cid:27) We refer to [10, Theorem 9.19] for details. Now we consider the following regularized stochastic equation dX (t) = (AX (t)+F (X (t)))dt+σdW(t) α,β α,β α,β α,β (2.6)  X (0) = x H.  α,β ∈ It is well known that (2.6) has a unique mild solution X (t,x), t 0. Its α,β ≥ associated transition semigroup is given by Pα,βf(x) = E[f(X (t,x))], t > 0, x H, t α,β ∈ for any f B (H). Here E denotes expectation with respect to P. b ∈ Proposition 2.1 Assume (H1) (H4). Then there exists a K -set K H σ − ⊂ such that µ(K) = 1 and for all f B (H), T > 0 there exist subsequences b ∈ (α ), (β ) 0 such that for all x K n n → ∈ lim lim Pαn,βmf(x) = pµf(x) weakly in L2(0,T;dt). (2.7) • • n→∞m→∞ Proof. This follows immediately from the proof of [7, Proposition 5.7]. (A closer look at the proof even shows that (2.7) holds for all x H = supp 0 µ.) (cid:3) ∈ As we shall see in Section 4, the proof of Theorem 1.6 follows from Propo- sition 2.1 if we can prove the corresponding Harnack inequality for each Pα,β. t Hence in the next section we confine ourselves to the case when F is dissi- 0 pative and Lipschitz. 3 The Lipschitz case Inthissectionweassumethat(H1)-(H3)and(H5)holdandthatF in(H3)is 0 in addition Lipschitz continuous. The aimof this section is to prove Theorem 9 1.6 for such special F (see Proposition 3.1 below). We shall do this by finite 0 dimensional (Galerkin) approximations, since for the approximating finite dimensional processes we can apply the usual coupling argument. We first note that since F is Lipschitz (1.1) has a unique mild solution 0 X(t,x), t 0, for every initial condition x H (cf.[10]) and we denote the ≥ ∈ corresponding transition semigroup by P , t > 0, i.e. t P f(x) := E[f(X(t,x))], t > 0, x X, t ∈ where f B (H). b ∈ Now we need to consider an appropriate Galerkin approximation. To this endlete D(A), k N,beorthonormalsuchthatH = linear span e ,..., k n 1 ∈ ∈ { e , n N. Hence e : k N is an orthonormal basis of (H, , ). Let n k } ∈ { ∈ } h· ·i π : H H be the orthogonal projection with respect to (H, , ). So, we n n → h· ·i can define A := π A (= A by (H5)(ii)) (3.1) n n |Hn |Hn and, furthermore F := π F , σ := π σ . n n 0|Hn n n |Hn Obviously, σ : H H is a self-adjoint, positive definite linear operator n n n → on H . Furthermore, σ is bijective, since it is one-to-one. To see the latter, n n one simply picks an orthonormal basis eσ,...,eσ of H with respect to the { 1 n} n inner product , defined by x,y := σx,y . Then if x H is such that σ σ n h· ·i h i h i ∈ σ x = π σx = 0, it follows that n n x,eσ = σx,eσ = 0, 1 i n. h iiσ h ii ∀ ≤ ≤ But x = n x,eσ eσ, hence x = 0. i=1h iiσ i Now fix n N and on H consider the stochastic equation n P ∈ dX (t) = (A X (t)+F (X (t)))dt+σ dW (t) n n n n n n n (3.2)  X (0) = x H ,  n n ∈ whereW (t) = π W(t) = n e ,W(t) e . n n i=1h k i k (3.2) has a unique strong solution X (t,x), t 0, for every initial con- n dition x H which is paPthwise continuous P-a.s.≥. Consider the associated n ∈ transition semigroup defined as before by Pnf(x) = E[f(X (t,x))], t > 0, x H , (3.3) t n ∈ n where f B (H ). b n ∈ Below we shall prove the following: 10

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