Dr. John Chung’s SAT II Mathematics Level 2 Good Luck! Dr. John Chung's SAT II Math Level 2 1 Dear Beloved Students, With this SAT II Subject Test Math Level 2 Third Edition, I like to thank all students who sent me email to encourage me to revise my books. As I said, while creating this series of math tests has brought great pleasure to my career, my only wish is that these books will help the many students who are preparing for college entrance. I have had the honor and the pleasure of working with numerous students and realized the need for prep books that can simply explain the fundamentals of mathematics. Most importantly, the questions in these books focus on building a solid understanding of basic mathematical concepts. Without understanding these solid foundations, it will be difficult to score well on the exams. These book emphasize that any difficult math question can be completely solved with a solid understanding of basic concepts. As the old proverb says, “Where there is a will, there is a way.” I still remember vividly on fifth‐ grader who was last in his class who eventually ended up at Harvard University seven years later. I cannot stress enough how such perseverance of the endless quest to master mathematical concepts and problems will yield fruitful results. You may sometimes find that the explanations in these books might not be sufficient. In such a case, you can email me at [email protected] and I will do my best to provide a more detailed explanation. Additionally, as you work on these books, please notify me if you encounter any grammatical or typographical errors so that I can provide an update version. It is my great wish that all students who work on these books can reach their ultimate goals and enter the college of their dreams. Thank you. Sincerely, Dr. John Chung 2 Contents 61 Tips TIP 01 Identical Equation Page 06 Tip 02 Remainder Theorem Page 07 Tip 03 Factor Theorem Page 08 Tip 04 Sum and Product of the roots Page 09 Tip 05 Complex Number Page 11 Tip 06 Conjugate Roots Page 12 Tip 07 Linear Function Page 13 Tip 08 Distance from a Point to a line Page 14 Tip 09 Distance from a Point to a Plane Page 15 Tip 10 Quadratic Function Page 16 Tip 11 Discriminant Page 17 Tip 12 Circle Page 18 Tip 13 Ellipse Page 19 Tip 14 Parabola Page 21 Tip 15 Hyperbola Page 23 Tip 16 Function Page 25 Tip 17 Domain and Range of a Composite Function Page 26 Tip 18 Piecewise‐Defined Function Page 28 Tip 19 Odd and Even Function Page 29 Tip 20 Combinations of functions Page 30 Tip 21 Periodic Functions Page 31 Tip 22 Inverse Functions Page 32 Tip 23 The Existence of an Inverse Function Page 33 Tip 24 Leading Coefficient Test (Behavior of Graph) Page 34 Dr. John Chung's SAT II Math Level 2 3 Tip 25 Arithmetic Sequence Page 35 Tip 26 Geometric Sequence Page 36 Tip 27 Exponential Functions Page 37 Tip 28 Logarithmic Functions Page 39 Tip 29 Basic Trigonometric Identities Page 41 Tip 30 Circle(Trigonometry) Page 43 TIP 31 Reference Angles and Cofunctions Page 44 Tip 32 Trigonometric Graphs Page 45 Tip 33 Inverse Trigonometric Functions Page 46 Tip 34 Sum and difference of angles Page 48 Tip 35 Double Angle Formula Page 49 Tip 36 Half Angle Formula Page 50 Tip 37 Trigonometric Equation Page 51 Tip 38 The Law of Sines Page 58 Tip 39 The Law of Cosines Page 54 Tip 40 Permutation Page 55 Tip 41 Combination Page 56 Tip 42 Dividing Group Page 57 Tip 43 Binomial Expansion Theorem Page 58 Tip 44 Sum of Coefficients of a Binomial Expansion Page 59 Tip 45 Binomial Probability Page 60 Tip 46 Probability with Combinations Page 61 Tip 47 Heron’s Formula Page 62 Tip 48 Vectors in the Plane Page 63 Tip 49 Interchange of Inputs Page 65 Tip 50 Polynomial Inequalities Page 67 Tip 51 Rational Inequalities Page 69 Tip 52 Limits Page 71 Tip 53 Rational Function and Asymptote Page 73 Tip 54 Parametric Equations Page 76 4 Tip 55 Polar Coordinates Page 77 Tip 56 Matrix Page 79 Tip 57 Inclination Angle Page 81 Tip 58 Angle between Two Lines Page 82 Tip 59 Intermediate Value Theorem Page 83 Tip 60 Rational Zero Test Page84 Tip 61 Descartes Rule of Sign Page 85 Practice Tests Test 01 Page 087 Test 02 Page 113 Test 03 Page 141 Test 04 Page 167 Test 05 Page 195 Test 06 Page 223 Test 07 Page 249 Test 08 Page 277 Test 09 Page 303 Test 10 Page 329 Test 11 Page 355 Test 12 Page 381 Dr. John Chung's SAT II Math Level 2 5 Tips TIP 01 Identical Equation An identical equation is an equation which is true for all values of the variable. 10x5x15x is an identical equation because it is always true for all real x. 10x515 is an algebraic equation because it is true for x1only. Identical equation has infinitely many solutions. In an identical equation, the expressions of both sides are exactly same. Example 1: 5x55x5 Example 2: axb0 for all real values of x axb0x0 a0 and b0 PRACTICE 1. If axb3x2 is always true for all realx, what are the values of a and b? 2. If a(x1)b(x1)x9 is true for all real values of x, what are the values of aand b? 3. If x2 2x6a(x1)2 b(x1)c is true for all real x, where a,b,and care constants, what are the values of a,b,andc? EXPLANATION 1. The coefficients must be equal. 2. axabxb(ab)xab, (ab)x(ab)x9 Coefficients must be equal. ab1 and ab9 Therefore, a5, b4. 3. Since x2 2x6ax2 (b2a)xabc, then a1, b2a2,and abc6. Therefore, a1, b4, and c1. Answer: 1. a3,b2 2. a5,b4 3. a1,b4,c1 6 Tips TIP 02 Remainder Theorem When polynomial P(x)is divided by (xa), the remainder R is equal to P(a). Polynomial P(x)can be expressed as follows. P(x)(xa)Q(x)R The identical equation is true for any value of x, especially xa. Therefore, P(a)R Example: If P(2)5, then you can say that “When polynomial P(x) is divided by (x2), the remainder is 5. PRACTICE 1. If a polynomial f(x)2x2 3x5is divided by (x1), what is the remainder? 2. If a polynomial g(x)x3 2x2 2x3is divided by (x1)(x2), then what is the remainder? EXPLANATION 1. R f(1)2(1)2 3(1)54 2. g(x)(x1)(x2)Q(x)axb When divided by degree 2 polynomial, the remainder is represented by axb At x1 g(1)8ab At x2 g(2)232ab Therefore, a15 and b7. The remainder is 15x7 Also the remainder can be obtained using long-division or synthetic division. Dr. John Chung's SAT II Math Level 2 7 Tips TIP 03 Factor Theorem If p(a)0, then p(x) has a factor of (xa). Polynomial p(x) can be expressed with a factor of (xa) as follows. p(x)(xa)Q(x), where Q(x) is quotient. If (xa) is a factor of p(x), then the remainder after division should be 0. Example: If p(5)0, then p(x) has a factor of (x5). PRACTICE 1. If a polynomial P(x)x2 kx8has a factor of (x2), then what is the value of constant k? 2. If a polynomial f(x)x3ax2 bx1has a factor of (x2 1), what are the values of aand b? EXPLANATION 1. Using the factor theorem, P(2)0 22 2k80 k 2 2. Sincex3ax2 bx1(x1)(x1)Q(x), f(1)ab20 and f(1)ab0 Therefore, a1 and b1. Answer: 1. k 2 2. a1 and b1 8 Tips TIP 04 Sum and Product of the Roots For a polynomial P(x)a xn a xn1a xn2 a xa 0 n n1 n2 1 o a Sum of the roots n1 a n a Product of the roots o 1n, where n is the degree of the polynomial a n Example 1: P(x)ax2 bxc0, r and s are the roots of the quadratic equation. b Sum of the roots: r s a Difference of the roots: (rs)2 (rs)2 4rs If r and s are real and r s, then b2 4c b2 4ac rs (rs)2 4rs rs a2 a a c c Product of the roots: rs (1)2 a a Example 2: P(x) Ax3Bx2 CxD0 B Sum of the three roots A D D Product of the three roots = 13 A A PRACTICE 1 1 1. If the roots of a quadratic equation 2x2 5x40are and , what is the value of ? 2. What is the sum of all zeros of a polynomial function P(x)2x7 3x35x2 4? 3. What is the product of all zeros of g(x)3x7 5x33x2 x2? 4. If one of the roots of a quadratic equation is 2i, what is the equation? Dr. John Chung's SAT II Math Level 2 9 Tips EXPLANATION 5 4 1 1 5 1. Since and 2, therefore . 2 2 4 a 0 2. Because the coefficient of x6is 0, the sum of the roots n1 0 a 2 n a 2 2 3. Because the product of all zeros is o (1)n 17 a 3 3 n b c 4. The quadratic equation can be defined by x2 x 0. a a b b The sum of the roots (2i)(2i)4 4 a a c c The product of the roots (2i)(2i)5 5 a a Therefore, the equation is x2 4x50. Proof Sum of the two roots: b b2 4ac b b2 4ac 2b b 2a 2a 2a a Product of the two roots: 2 b b2 4acb b2 4ac b2 b2 4ac 2a 2a 4a2 4ac c 4a2 a Answer: 1. 5 2. 0 3. 2 4. x2 4x50 4 3 10