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Physical Limits on the Notion of Very Low Temperatures 8 Juhao Wu and A. Widom 9 Department of Physics, Northeastern University, Boston, Massachusetts 02115 9 1 n a J Abstract 8 2 ] h Standard statistical thermodynamic views of temperature fluctuations c predict a magnitude ( < (∆T)2 >/T) (k /C) for a system with heat e B ≈ m capacity C. The extent to which low temperatures can be well defined is p p - discussed for those systems which obey the thermodynamic third law in the t a t form lim(T→0)C = 0. Physical limits on the notion of very low temperatures s areexhibitedforsimplesystems. Application oftheseconceptstoboundBose . t a condensed systems are explored, and the notion of bound Boson superfluidity m is discussed in terms of the thermodynamic moment of inertia. - d n PACS numbers: 05.30.Ch, 03.75.Fi, 05.30.Jp, 05.40.+j o c [ 1 v 7 8 2 1 0 8 9 / t a m - d n o c : v i X r a Typeset using REVTEX 1 I. INTRODUCTION A problem of considerable importance in low temperature physics concerns physical limi- tations on how small a temperature can be well defined in the laboratory[1]. In what follows, we shall consider temperature fluctuations which define a system temperature “uncertainty” δT = < (T < T >) >2 , (1.1) s s − q whenever a finite system at temperature T is in thermal contact with a large reservoir s at bath temperature T. Only on the thermodynamic average do we expect the system temperature to be equal to the bath temperature; i.e. < T > T. The fluctuation from s ≈ thisaverageresult (quotedinthebetter textbooksdiscussing statisticalthermodynamics[2]), has the magnitude δT k B , (1.2) T ≈ s C (cid:16) (cid:17) where C is the heat capacity of the finite system, and k is Boltzman’s constant. Since C B is an extensive thermodynamic quantity, one expects the usual small fluctuation in temper- ature (δT/T) (1/√N) in the thermodynamic limit N , where N is the number of ∝ → ∞ microscopic particles. However, in low temperature physics (for systems with finite values for N), temperature fluctuations are by no means required to be negligible. For those finite sized systems which obey the thermodynamic third law lim C = 0, (1.3) T→0 one finds from Eqs.(1.2) and (1.3) that δT as T 0 with N < . (1.4) T → ∞ → ∞ (cid:16) (cid:17) Eq.(1.4) sets the limits on what can be regarded as the ultimate lowest temperatures for finite thermodynamic systems; i.e. the temperature must at least obey δT << T. In Sec.II, the theoretical foundations for Eq.(1.4) will be discussed. In brief, the micro- canonical entropy of a thermodynamic system is given by S(E) = k lnΓ(E), (1.5) B where Γ(E) is the number of system quantum states with energy E. The micro-canonical entropy defines the system temperature T via s 1 dS = . (1.6) T dE s (cid:16) (cid:17) (cid:16) (cid:17) The thermal bath temperature T, which is not quite the system temperature T , enters into s the canonical free energy F(T) = k T lnZ(T), (1.7) B − where the partition function is defined as Z(T) = Tr e−H/kBT = Γ(E)e−E/kBT. (1.8) (cid:16) (cid:17) XE 2 The probability distribution for the energy of the system, when in contact with a thermal bath at temperature T, is given by Γ(E) E F(T) E +TS(E) P(E;T) = exp − = exp − , (1.9) Z(T) k T k T B B (cid:16) (cid:17) (cid:16) (cid:17) (cid:16) (cid:17) as dictated by Gibbs. Thus, the temperature T (of the thermal bath) does not fluctuate while system energy E does fluctuate according to the probability rule of Eq.(1.9). On the other hand, the system temperature T (E) in Eq.(1.6) depends on the system energy and s thereby fluctuates since E fluctuates. It is only for the energy E∗ of maximum probability Max P(E;T) = P = P(E∗;T) that the system temperature is equal to the bath tem- E max ∗ perature T (E ) = T. If the energy probability distribution is spread out at low thermal s bath temperatures, then temperature fluctuations are well defined in the canonical ensemble of Gibbs. In Sec.III, temperature fluctuations are illustrated using the example of black body radiation in a cavity of volume V. For this case, it turns out that the thermal wave length Λ of the radiation in the cavity, T h¯c Λ = , (1.10) T k T B (cid:16) (cid:17) must be small on the scale of the cavity length V1/3; i.e. Λ << V1/3. For example, in a T cavity of volume V 1 cm3, the lowest temperature for the radiation within the cavity is ∼ of order T 1 oK. It is of course possible to cool the conducting metal walls of a cavity min ∼ with a length scale 1 cm to well below 1 oK. However, this by no means implies that the ∼ radiation within the cavity can have a temperature well below 1 oK. The point is that at temperatures T < 1 oK, there are perhaps only a few photons (in total) in the cavity. The s total number of photons are far too few for the cavity radiation system temperature to be well defined. In Sec.IV, a confined system of atoms obeying ideal gas Bose statistics is discussed. N Such systems can be Bose condensed, and are presently (perhaps) the lowest temperature systems available in laboratories. In the quasi-classical approximation, the free energy is computed in Sec.V. Questions concerning bounds on ultra-low temperatures are explored. Whether or not such Bose condensed atoms can exhibit superfluid behavior is discussed in Sec.VI. The superfluid and normal fluid contributions to the moment of inertia are com- puted. In the concluding Sec.VII, another simple system with fluctuation limits on ultra-low temperatures will be briefly discussed. II. THEORETICAL FOUNDATIONS Let φ(E) denote some physical quantity which depends on the energy E of a physi- cal system. If the system is in contact with a thermal bath at temperature T, then the thermodynamic average may be calculated from < φ >= P(E;T)φ(E), (2.1) E X 3 where the probability P(E;T) has been defined in Eq.(1.9). Using the “summation by parts”[3,4] formula ∂ P(E;T)φ(E) = 0, (2.2) ∂E XE (cid:16) (cid:17) i.e. with a strongly peaked P(E;T) dφ(E) ∂P(E;T) P(E;T) = φ(E) , (2.3) − dE ∂E XE (cid:16) (cid:17) XE (cid:16) (cid:17) one finds dφ(E) ∂P(E;T) k = k φ(E) . (2.4) B B − dE ∂E D E XE (cid:16) (cid:17) Employing Eqs.(1.6) and (1.9), ∂P(E;T) 1 1 k = P(E;T). (2.5) B ∂E T (E) − T s (cid:16) (cid:17) (cid:16) (cid:17) Eqs.(2.4) and (2.5) imply the central result of this section dφ 1 1 k = φ . (2.6) B − dE T − T s D E D(cid:16) (cid:17) E If we choose φ(E) = 1, then Eq.(2.6) reads 1 1 = ; (2.7) T T s D E i.e. on average, the reciprocal of the system temperature is equal to the reciprocal of the thermal bath temperature. Thus, with fluctuations from the mean ∆φ = φ < φ >, (2.8) − 1 1 1 1 1 ∆ = = , (2.9) T T − T T − T s s s (cid:16) (cid:17) D E Eq.(2.6) reads dφ 1 k = ∆ ∆φ . (2.10) B − dE T D E D (cid:16) (cid:17) E If we choose in Eq.(2.10) the function φ to be 1 dφ 1 dT 1 s φ = and = = (2.11) T − dE T2 dE T2C (cid:16) s(cid:17) (cid:16) (cid:17) s (cid:16) (cid:17) (cid:16) s (cid:17) (where C = (dE/dT ) is the system heat capacity), then s 1 2 1 kB ∆ = . (2.12) T T2 C D (cid:16) (cid:17) E D s (cid:16) (cid:17)E 4 The standard Eqs.(1.1) and (1.2) follow from the more precise Eqs.(2.7) and (2.12) in the limit of small temperature fluctuations; i.e. k T2 < (∆T)2 > B if δT = < (∆T)2 > << T. (2.13) ≈ C (cid:16) (cid:17) q The condition δT << T is required in order that the canonical thermal bath tempera- ture be equivalent to the micro-canonical system temperature. If the micro-canonical and canonical temperatures are not equivalent, then the statistical thermodynamic definition of temperature would no longer be unambiguous. This raises fundamental questions as to the physical meaning of temperature. The view of this work is that in an ultra-low temperature limit, whereby δT T for sufficiently small T, the whole notion of system temperature is ∼ undefined, although the notion of a thermal bath temperature retains validity. III. BLACK BODY RADIATION EXAMPLE The heat capacity of black body radiation in a cavity of volume V with the walls of the cavity at temperature T is given by[5] 4π2 V C(Black Body) = k , (3.1) B 15 Λ3 (cid:16) (cid:17)(cid:16) T(cid:17) where Λ is given by Eq.(1.10). From Eqs.(1.2) and (3.1) it follows that the radiation T temperature of a black body cavity of volume V is δT(Black Body) 15 Λ3 Λ3 T 0.6 T . (3.2) T ≈ s 4π2 V ≈ s V (cid:16) (cid:17) (cid:16) (cid:17)(cid:16) (cid:17) (cid:16) (cid:17) In order to achieve a well defined radiation temperature inside the cavity, δT(Black Body) must be small on the scale of T or equivalently Λ << V1/3. As stated in Sec.1, this implies T a minimum temperature of T 1 oK for a cavity of V 1 cm3. min ∼ ∼ IV. CONFINED IDEAL BOSE GAS The grand canonical free energy of an ideal Bose gas is determined by the trace[6] Ξ(T,µ) = k T tr ln 1 e(µ−h)/kBT , (4.1) B − (cid:16) (cid:17) where h is the one Boson Hamiltonian and dΞ = dT dµ (4.2) −S −N determines the number of Bosons . If the one Boson partition function is defined as N q(T) = tr e−h/kBT , (4.3) (cid:16) (cid:17) 5 then the free energy obeys ∞ 1 T Ξ(T,µ) = k T q enµ/kBT. (4.4) B − n n nX=1(cid:16) (cid:17) (cid:16) (cid:17) The mean number of Bosons is ∞ T (T,µ) = q enµ/kBT, (4.5) N n nX=1 (cid:16) (cid:17) and the statistical entropy is given by ∞ Ξ(T,µ)+µ (T,µ) 1 T (T,µ) = N +k T q′ enµ/kBT, (4.6) B S − T n2 n (cid:16) (cid:17) nX=1(cid:16) (cid:17) (cid:16) (cid:17) where q′(T) = dq(T)/dT . { } Of considerable theoretical[7,8] experimental[9,10,11] interest is the bound Boson in an anisotropic oscillator potential, h¯2 1 h¯ h = 2 + Mr ωˆ2 r tr(ωˆ) (4.7) − 2M ∇ 2 · · − 2 (cid:16) (cid:17) (cid:16) (cid:17) (cid:16) (cid:17) where ω2 0 0 1 ωˆ2 = 0 ω2 0 . (4.8)  2  0 0 ω2  3   Eqs.(4.3) and (4.7) imply 3 1 q(T) = . (4.9) 1 e−¯hωj/kBT jY=1(cid:16) − (cid:17) The heat capacity may be defined by ∂S C = T , (4.9) ∂T N (cid:16) (cid:17) which must be calculated numerically. Shown in Fig.1 is a plot of the heat capacity (in units of k ) versus temperature (in B N unitsofthecriticaltemperatureT )forthecaseof = 2 103 and = 2 106 particles. We c N × N × choose, forexperimentalinterest[12], thefrequencyeigenvalues(ω /2π) = (ω /2π) = 320Hz, 1 2 and (ω /2π) = 18Hz. 3 6 FIGURES Heat Capacity vs. Temperature N=2,000 (Dotted) N=2,000,000 (Solid) 11 10 9 8 7 k) 6 N C/ ( 5 4 3 2 1 0 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 2.2 (T/Tc) FIG. 1. The heat capacity (in units of k ) is plotted as a function of temperature (in units B N of T ) for = 2 103 atoms (dotted curve) and = 2 106 atoms (solid curve). c N × N × Figure 1. For finite , there is strictly speaking no Bose-Einstein condensation phase transition. N The critical temperature T is therefore defined as that temperature for which the heat c capacity reaches the maximum value C = C(T ). Although phase transitions are defined max c in mathematics only in the thermodynamic limit , for all practical purposes, a N → ∞ quasi-classical approximation of Eq.(4.1) in the form d3rd3p Ξ(T,µ) = k T ln 1 e(µ−h(p,r))/kBT (quasi classical), (4.10) B (2πh¯)3 − − Z Z (cid:16) (cid:17) (cid:16) (cid:17) where p2 1 h(p,r) = + Mr ωˆ2 r, (4.11) 2M 2 · · does yield a Bose-Einstein condensation phase transition whose heat capacity is sufficiently accurate for values of 105 or higher. Thus, we regardrecent experiments on Bose atoms N ∼ confined in a magnetic bottle to be probing a physical Bose-Einstein ordered phase. Let us consider Eq.(4.10) in more detail. 7 V. QUASI-CLASSICAL BOSE CONDENSATION In order to evaluate Eq.(4.10) we employ the quasi-classical form[13,14] of Eqs.(4.3) and (4.11); i.e. q(T) = d3rd3p e−h(p,r)/kBT = 3 kBT = kBT 3, (5.1) (2πh¯)3 h¯ω h¯ω¯ Z Z (cid:16) (cid:17) jY=1(cid:16) j (cid:17) (cid:16) (cid:17) where ω¯ = (ω ω ω )1/3. From Eqs.(4.4) and (5.1), it follows that Eq.(4.10) evaluates to 1 2 3 ∞ Ξ(T,µ) = h¯ω¯ kBT 4 1 enµ/kBT. (5.2) − h¯ω¯ n4 (cid:16) (cid:17) nX=1(cid:16) (cid:17) From Eqs.(4.2) and (5.2), the number of particles obeys ∞ (T,µ) = kBT 3 1 enµ/kBT, (µ < 0). (5.3) N h¯ω¯ n3 (cid:16) (cid:17) nX=1(cid:16) (cid:17) With the usual definition of the ζ-function ∞ 1 ζ(s) = , e(s) > 1, (5.4) ns R nX=1(cid:16) (cid:17) the Bose-Einstein condensation critical temperature is h¯ω¯ N 1/3 T = . (5.5) c k ζ(3) B (cid:16) (cid:17)(cid:16) (cid:17) The non-zero number of Bosons (below the critical temperature) in the condensate state is given by T 3 (T) = 1 , (T < T ). (5.6) 0 c N N − T c n (cid:16) (cid:17) o Finally, the entropy below the critical temperature kBT 3 4ζ(4) T 3 (T) = 4k ζ(4) = Nk , (T < T ), (5.7) B B c S h¯ω¯ ζ(3) T c (cid:16) (cid:17) (cid:16) (cid:17)(cid:16) (cid:17) obeys the thermodynamic third law lim (T) = 0. The heat capacity in the Bose- (T→0) S Einstein Condensed phase is then given by C 12ζ(4) T 3 T 3 = 10.81 , (T < T ). (5.8) c k ζ(3) T ≈ T B c c (cid:16)N (cid:17) (cid:16) (cid:17)(cid:16) (cid:17) (cid:16) (cid:17) Employing Eqs.(1.2)and(5.8)wefindthatthetemperatureuncertaintybelowthecritical temperature obeys δT 0.3 Tc 3/2 , (T < T ). (5.9) c T ≈ √ T (cid:16) (cid:17) (cid:16) N(cid:17)(cid:16) (cid:17) Thus, for 105 one may safely consider the temperature of the ordered phase to be well N ∼ defined in the range T > T > T , where T 0.05 T . The open question as to whether c min min c ∼ the ordered phase is a superfluid may now be considered. 8 VI. SUPERFLUID FRACTION OF THE BOUND BOSON SYSTEM The notion of a superfluid fraction in an experimental Bose fluid (such as liquid He4) may be viewed in the following manner: Suppose that we pour the liquid into a very slowly rotating vessel and close it off from the environment. The walls of the vessel are at a bath temperature T, and the vessel itself rigidly rotates at a very small angular velocity Ω. In the “two-fluid” model[15,16], the normal part of the fluid rotates with a rigid body angular velocity Ω, which is the same as the angular velocity of the vessel. On the other hand, the superfluid part of the fluid does not rotate. The superfluid exhibits virtually zero angular momentum for sufficiently small Ω. The total fluid moment of inertia tensor Iˆis defined by the fluid angular momentum L = IˆΩ (as Ω 0). We here take the limit Ω 0, to avoid · → → questions concerning the effects of vortex singularities on the superfluid. The normal fluid, which rotates along with the rotating vessel, contributes to the fluid moment of inertia. The superfluid, which does not rotate with the vessel, does not contribute to the moment of inertia. Thus, the geometric moment of inertia, Iˆgeometric = d3rρ¯(r)(r2δ r r ), (6.1) ij ij − i j Z where ρ¯(r) is the mean mass density of the fluid (at rest), overestimates the physical moment of inertia eigenvalues when the fluid is actually a superfluid. The normal fluid contributes to the moment of inertia and the superfluid does not do so in the limit Ω 0. Below, we → consider in detail the moment of inertia of the bound Bose gas. For the bound Bose system, we consider a mesoscopic rotational state[17] with a thermal angular velocity Ω. The rotational version of Eq.(4.2) reads dΞ = dT dµ L dΩ, (6.2) Ω −S −N − · where L is the bound Boson angular momentum. Eq.(4.11) gets replaced by p2 1 h (p,r) = + Mr ωˆ2 r Ω (r p), (6.3) Ω 2M 2 · · − · × so that Eq.(5.1) now reads d3rd3p q (T) = e−hΩ(p,r)/kBT = q(T) Det(1 ωˆ−2Ωˆ2) , (6.4) Ω (2πh¯)3 − Z Z (cid:16) (cid:17) (cid:16) .q (cid:17) where the matrix ωˆ2 is written in Eq.(4.8) and (Ω2 +Ω2) Ω Ω Ω Ω Ωˆ2 = 2Ω Ω3 (Ω−2 +1 Ω22) −Ω1Ω3 . (6.5)  − 1 2 1 3 − 2 3  Ω Ω Ω Ω (Ω2 +Ω2)  − 1 3 − 2 3 1 2    From Eqs.(4.4) and (6.4), it follows that Ξ (T,µ) = Ξ(T,µ) Det(1 ωˆ−2Ωˆ2) , (6.6) Ω − (cid:16) .q (cid:17) 9 The fluid moment of inertia tensor has the matrix elements ∂L ∂2Ξ Iˆ = lim i = lim Ω . (6.7) ij Ω→0 ∂Ω T,µ −Ω→0 ∂Ω ∂Ω T,µ j j j (cid:16) (cid:17) (cid:16) (cid:17) Eqs.(4.8), (6.5), (6.6) and (6.7) imply (in the unordered phase) 1 + 1 0 0 ω22 ω32 Iˆ= Ξ(T,µ)(cid:16) 0 (cid:17) 1 + 1 0 , (T > T ). (6.8) − ω12 ω32 c  0 (cid:16) 0 (cid:17) 1 + 1   ω12 ω22   (cid:16) (cid:17) In the unordered phase, obeying Eq.(5.2), one finds that Eq.(6.8) is precisely what would be expected from a normal fluid with geometric moment of inertia Iˆ = d3rρ¯(r)(r2δ r r ), (T > T ), (6.9) ij ij i j c − Z where ρ¯(r) is the mean mass density of the atoms. In the ordered phase (T < T ), the moment of inertia of the particles over and above the c condensate is given by Eq.(6.8) with µ = 0, i.e. 1 + 1 0 0 Iˆexcitation = ζ(4)h¯ω¯ kBT 4(cid:16)ω22 0 ω32(cid:17) 1 + 1 0 , (T < T ). (6.10) h¯ω¯ ω12 ω32 c (cid:16) (cid:17)  0 (cid:16) 0 (cid:17) 1 + 1   ω12 ω22   (cid:16) (cid:17) The question of superfluidity concerns the magnitude of the moment of inertia of those particles within the condensate. For T < T , we use the notation that Iˆ denotes the mo- c ment of inertia of the excited Bosons, and Jˆ represents the moment of inertia of the Bose condensate. If the moment of inertia of the particles in the condensate were zero, then the condensate particles would all be “superfluid”. Let ψ (r) be the normalized ( d3r ψ (r) 2 = 1) Bose condensation state. From the 0 0 | | geometric viewpoint, the moment of inertia of the condensate would be given by R Jgeometric = d3r ψ (r) 2(r2δ r r ); (6.11) ij N0 | 0 | ij − i j Z i.e. 1 + 1 0 0 h¯ ω2 ω3 Jˆgeometric = N0 (cid:16) 0 (cid:17) 1 + 1 0 . (6.12) 2 ω1 ω3  0 (cid:16) 0 (cid:17) 1 + 1     ω1 ω2   (cid:16) (cid:17) The physical Bose condensate moment of inertia tensor is in reality < ψ l ψ >< ψ l ψ > + < ψ l ψ >< ψ l ψ > Jphysical = 0| i| κ κ| j| 0 0| j| κ κ| i| 0 , (6.13) ij N0 ǫ ǫ Xκ (cid:16) κ − 0 (cid:17) where l = ih¯(r ). One may derive Eq.(6.13) by treating the rotational coupling ∆h = − ×∇ Ω l to second order perturbation theory in the energy ∆ǫ (Ω) as Ω 0. Eq.(6.13) 0 − · → 10

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