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Pair production and annihilation PDF

18 Pages·2016·0.76 MB·English
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P P A R I O R D U C T I O N Book page 288 - 490 ©cgrahamphysics.com 2016 Pair production and annihilation • All particles have anti particles of 1 Identical mass and spin 2 Opposite charge • Antiparticles have opposite charge, lepton number, baryon number and strangeness • Electrical neutral bosons and mesons are their own antiparticles ©cgrahamphysics.com 2016 History • 1928: Paul Dirac • 1932: Carl Anderson Particle with same mass but opposite charge might exist in the Universe • Cosmic radiation traveling through a bubble chamber during pair production split up into electron path and path with same mass as electron but opposite direction • Positron was discovered • In 1959 antiproton was discovered ©cgrahamphysics.com 2016 Pair production • In the strong field close to the nucleus a photon of the right energy can turn into a particle and its antiparticle • I.e. a proton and antiproton • They always come in pairs to conserve charge, L and B and strangeness ©cgrahamphysics.com 2016 Feynman diagram • Since particle and antiparticle have the same mass:  photon must have enough energy to create both masses • The minimum energy needed to create the 2 mass is 𝐸 = 2𝑚𝑐 • m = rest mass of particle / antiparticle ©cgrahamphysics.com 2016 Example • The following figure is a sketch of the path of the pair production of an proton and antiproton. There is a magnetic field pointing out of the page. a) Use RHR to show A is an antiproton b) No, they have different radii  they have different speeds and different KE c) 𝐸 = 2𝑚 𝑐2 𝑚𝑖𝑛 0 = 2𝑥1.673 × 10;27 × 9 × 1016 3.01 × 10;10 = = 1.9𝐺𝑒𝑉 1.6 × 10;19 • (a) Explain which of the tracks is due to the antiproton, A or B. • (b) Deduce whether the particles have the same energy. • (c) Calculate the minimum energy required for the pair production in GeV. ©cgrahamphysics.com 2016 Feynmann diagram • In this case gamma photon must at least have energy of 1.02MeV, which is twice the rest energy of an electron • Photon energy in excess is converted to KE of : ; 𝑒 𝑎𝑛𝑑 𝑒 pair and the original electron ©cgrahamphysics.com 2016 Orbital electrons • Pair production can also occur • Pair production near atomic near orbital electrons electron  photon is non ionizing, leaves •  more energy is needed no trace •  electron itself gains • Newly formed electron and momentum and KE positron are spiraling in opposite directions in a magnetic field • Recoiling electron gains large amount of KE  hardly bends in magnetic field  bends slightly in same direction as new electron • Threshold energy needed 2 for this pair production 𝐸 = 4𝑚 𝑐 = 2.04MeV 𝑚𝑖𝑛 0 • Equation for this interaction: ; ; ©cgrah;amphysics.:com 2016 𝛾 + 𝑒 → 𝑒 + 𝑒 + 𝑒 Annihilation • Matter collides with its corresponding antimatter • Both particles are annihilated • Two gamma rays with same energy but with a 0 direction at 180 to each other are produced • Pair annihilation • Momentum is conserved • Energy – positron annihilation gives energy 2 equal to 𝐸 = 𝑚𝑐 • The energy is released in form of gamma rays ©cgrahamphysics.com 2016 • Energy released is higher if particles annihilate in a collision •  One or both particles contribute KE • Sometimes a pair of particles annihilate, but then one of the photons produces another pair of particles • The new photon has a “clean slate” – it does not have any charge, baryon or lepton number, etc • Any pair of particles can emerge ; : ; : • 𝑒 + 𝑒 → 𝛾 → 𝑒 + 𝑒 ; : ; : • 𝑒 + 𝑒 → 𝛾 → 𝜇 + 𝜇 ; : ; : • 𝑒 + 𝑒 → 𝛾 → 𝜏 + 𝜏 ; : • 𝑒 + 𝑒 → 𝛾 → 𝑞 + 𝑞 ©cgrahamphysics.com 2016

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Pair production and annihilation. • All particles have Pair production. • In the strong (a) Explain which of the tracks is due to the antiproton, A or B.
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