NASA Technical Reports Server (NTRS) 20130013525: Computational Fluid Dynamics Uncertainty Analysis for Payload Fairing Spacecraft Environmental Control Systems PDF
Preview NASA Technical Reports Server (NTRS) 20130013525: Computational Fluid Dynamics Uncertainty Analysis for Payload Fairing Spacecraft Environmental Control Systems
Dissertation Research Computational Fluid Dynamics Uncertainty Analysis for Payload Fairing Spacecraft Environmental Control Systems I Candidacy Exam Proposed Dissertation Curtis Groves Ph. D. Student Mechanical Engineering University of Central Florida 1 Agenda I • ECS System Overview Problem • Literature Review • Summary of ASME Standard • Example of Backward Facing Step • Proposed Dissertation Topic • Summary 2 Environmental Control System (ECS) System Overview 3 ECS System ·overview • Environmental Control System AIAA2oo2-32s3 - Prior to launch, cold air (air conditioning) flows downward around the spacecraft after it has been encapsulated in the Payload Fairing. - The cold air is delivered through an air-conditioning (AC) pipe, which intersects the fairing and flows past a diffuser located at the pipe/fairing interface - After passing over the spacecraft, it is finally discharged through vents - The Payload Fairing air conditioning is cut off at lift off. 4 ECS System Overview • Environmental Control System (ECS) AC pipe DPAF Diffuser Guidance section Swirl flow AIAA 2002-3253 s ECS System Overview • Example of an ECS system airflow test Kandula, M., Ham mad, K., and Schall horn, P., "CFD Validation with LDV Test Data for Payload/Fairing Internal Flow," AIAA-2005-4910, 2005. 6 Problem, Example • CFD has errors and uncertainties 25 20 15 10 -1.8 -1.0 -1.4 -12 -1 -0.8 -0.6 -0.4 -02 0 0.2 0.4 0.0 0.8 1 12 1.4 1.0 1.8 Problem, Example- How Good is this Prediction? Model Pediction 30 25 20 Q) "'C ::J .c~ 15 bO -C1J ~ > ·u 10 0 Q) > 5 I -2 -1.5 -1 -0.5 0 0.5 1 1.5 2 ~~sition 8 Problem, Example- Grid Independence Study Grid Model Comparision 30 25 20 I I Q) "0 ~ .~ c: 15 00 ro ~ > .~ u _Q ~ -2 -1.5 -1 -0.5 0 0.5 1 1.5 2 ~~sition - coarse - Med - fine 9 Problem, Example- Turbulence Models Turbulence Model Comparision 30 25 20 Q) "'0 ~ .t::: c 15 tiD ro ~ ..>... ·u 10 0 Q) > 5 ---- - - - - -·-- -2 -1.5 -1 -0.5 0 0.5 1 1.5 2 ~~sttion - SA - coarse - Med - fine - ke -realizable - kwsst 10
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