ebook img

Model independent constraints from vacuum and in-medium QCD Sum Rules PDF

6 Pages·0.11 MB·English
Save to my drive
Quick download
Download
Most books are stored in the elastic cloud where traffic is expensive. For this reason, we have a limit on daily download.

Preview Model independent constraints from vacuum and in-medium QCD Sum Rules

EPJ manuscript No. (will be inserted by the editor) Model independent constraints from vacuum and in-medium QCD Sum Rules 9 9 F. Klingl and W. Weise a 9 1 n Physik-Department,Theoretische Physik,Technische Universit¨at Mu¨nchen, D-85747 Garching, Germany a J 1 Received: date/ Revised version: date 2 1 v Abstract. WediscussQCDsumruleconstraintsbasedonmomentsofvectormesonspectraldistributionsin 8 5 thevacuumandinanuclearmedium.Sumrulesforthetwolowestmomentsofthesespectraldistributions 0 1 donotsufferfrom uncertaintiesrelated toQCDcondensatesofdimension higherthanfour.Weexemplify 0 9 these relations for the case of the ω meson and discuss the issue of in-medium mass shifts from this 9 h/ viewpoint. t - l c u PACS. 12.40.Vv Vector-meson dominance – 24.85.+p Quarks, gluons, and QCD in nuclei and nuclear n : v processes i X r QCD sum rules have repeatedly been used in recent four-quarkcondensatesintermsof q¯q 2,thesquareofthe a h i times to arrive at estimates for possible in-medium mass standard chiral condensate. The first objection is far less shiftsofvectormesons[1,7].Thevalidityofsuchestimates serious for the ω meson which may well have a chance to has been questioned, however, for several reasons. First, survive as a reasonably narrow quasi-particle in nuclear for broadstructuressuchas theρ mesonwhose largevac- matter [3,4]. The second objection, however, is difficult uum decay width is further magnified by in-medium re- to overcome:factorization of four-quark condensates may actions, the QCD sum rule analysis does not provide a indeed be questionable. reliableframeworkto extractanythinglike a“massshift” [3,5].Secondly,notoriousuncertaintiesexistatthelevelof In the present note we focus on the two lowest mo- factorizationassumptionscommonlyusedtoapproximate ments ( dssnR(s) with n = 0,1) of vector meson spec- R traldistributions,in vacuumas wellas in nuclear matter, Send offprint requests to: [email protected] a Work supported in part by BMBF and GSI andpointoutthatthesearesubjecttosumruleswhichdo 2 F. Klingl and W. Weise: Model independentconstraints from vacuumand in-medium QCD Sum Rules notsufferfromtheuncertaintiesintroducedbyfour-quark tor product (Wilson) expansion gives condensates.Thesesumrulesareshowntoprovideuseful, Q2 c c 12π2Π(q2 = Q2)= c Q2ln +c + 2 + 3 +... − − 0 (cid:18)µ2(cid:19) 1 Q2 Q4 modelindependentconstraintswhichweexemplifyforthe (3) case of the ω meson spectral distribution and its change Wespecifythecoefficientsc fortheisoscalarcurrentjµ = i in the nuclear medium. The sum rule for the second mo- 1(u¯γµu+d¯γµd), the case of the ω meson that we wish to 6 ment, dss2R(s),doesinvolvethefour-quarkcondensate. use here for explicit evaluations. In vacuum we have: R In fact it can be used in principle to determine this par- 1 α 1 c = 1+ S , c = (m2 +m2), (4) ticular condensate and test the factorization assumption. 0 6(cid:16) π (cid:17) 1 −2 u d π2 α 2π2 c = S µν + m uu¯+m dd¯, (5) The detailed analysis of this question will be defered to 2 µν u d 18h π G G i 3 h i a longer paper. In this short note we confine ourselves to while c involves combinations of four-quark condensates 3 conclusions that can be drawn without reference to four- of (mass) dimension 6. The quark mass term c is small 1 quark condensates. and can be dropped in the actual calculations. For the The starting point is the current-current correlation gluon condensate we use αS 2 = (0.36GeV)4 [9], and h π G i function the(chiral)quarkcondensateisgivenby m u¯u+m d¯d u d h i≃ m u¯u+d¯d = m2f2 (0.11GeV)4 throughthe Gell- Π (q)=i d4xeiq·x j (x)j (0) (1) qh i − π π ≃− µν µ ν Z hT i Mann, Oakes, Renner relation. where denotes the time-ordered product and the ex- In the nuclear medium with baryondensity ρ we have T pectation value is taken either in the vacuum or in the c (ρ) = c (ρ = 0)+δc (ρ) with c (0) given by eqs.(4,5), i i i i groundstate ofnuclear matter at rest.In vacuumthe po- and larizationtensor(1)canbe reducedto a singlescalarcor- π2 4 δc (ρ)= M(0)+2σ +A M ρ (6) 2 3 (cid:20)−27 N N 1 N(cid:21) relation function, Π(q2) = 1gµνΠ (q). In nuclear mat- 3 µν to linear order in ρ. The first term in brackets is the tertherearetwo(longitudinalandtransverse)correlation leading density dependent correction to the gluon con- functions which coincide for a meson at rest with respect densate and involves the nucleon mass in the chiral limit, to the medium (i.e. with qµ =(ω,q=0)). M(0) 0.75GeV[6].The secondpartproportionalto the Thereducedcorrelationfunctioniswrittenasa(twice N ≃ nucleon sigma term σ 45MeV is the first order cor- N subtracted) dispersion relation, ≃ rectionofthe quarkcondensate,andthethirdtermintro- q4 ImΠ(s) Π(q2)=Π(0)+Π′(0)q2+ ds . (2) duces the first moment of the quark distribution function π Z s2(s q2 iǫ) − − in the nucleon: whereΠ(0)vanishesinvacuumbutcontributesinnuclear matter. At largespacelike Q2 = q2 >0 the QCD opera- A1 =2 dxx u(x)+u¯(x)+d(x)+d¯(x) . (7) Z − (cid:2) (cid:3) F. Klingl and W. Weise: Model independentconstraints from vacuumand in-medium QCD Sum Rules 3 It represents twice the fraction of momentum carried by s0dss2R(s)= s30c +c . (12) 0 3 Z 3 0 quarks in the proton. We take A 1 as determined by 1 ≃ Note thatthe firsttwo sumrules arewelldetermined and deep-inelastic lepton scattering at Q 2GeV. Note that ∼ δc (ρ ) 4 10−3GeV4atρ=ρ =0.17fm−3,thedensity represent useful constraints for the spectrum R(s). Only 2 0 0 ≃ · the third sum rule (12) involves four-quark condensates of nuclear matter, and almost all of this correctioncomes which are uncertain. In this short paper we concentrate from the term proportional to A . 1 on eqs. (10,11). A detailed analysis of eq.(12) will be pre- Next we introduce the Borel transform of eq. (3): sented in a forthcoming longer paper. It is instructive to ∞ 12π2Π(0)+ dsR(s)e−s/M2 =c 2+c + c2 + c3 +... Z 0M 1 2 2 4 illustratethesumrules(10,11)fortheω mesoninvacuum 0 M M (8) using Vector Meson Dominance (VMD) for the resonant with R(s)= 12πImΠ(s) andΠ(0)= ρ/4M ,the vec- − s − N part of R(s). In this model we have tor meson analogue of the Thomson term in photon scat- m2 1 α R(s)=12π2 ω δ(s m2)+ 1+ S Θ(s s ). (13) tering. gω2 − ω 6(cid:16) π (cid:17) − o We separate the spectrum R(s) into a resonance part with g = 3g 16.8 (using the vector coupling constant ω ≃ with s s and a continuum R (s) which must approach ≤ 0 c g = 5.6). We can neglect the small quark mass term c1 the perturbative QCD limit for s>s : 0 and find from eq. (10): 1 α R (s)= 1+ S Θ(s s ). (9) 8π2m2 α c 6(cid:16) π (cid:17) − o ω =1+ S, (14) g2 s π 0 The factor 1 is again specific for the isoscalar channel. 6 whichfixes√s =1.16GeVusingα (s ) 0.4andm = 0 S 0 ω ≃ The Borel mass parameter must be sufficiently large M 0.78GeV. It is interesting to identify the spectral gap so that eq.(8) converges rapidly, but otherwise it is ar- ∆=√s with the scale for spontaneous chiral symmetry 0 bitrary. We choose > √s0 so that e−s/M2 can be ex- M breaking, ∆ = 4πf , where f = 92.4 MeV is the pion π π pandedinpowersofs/ 2fors<s .Theremaininginte- 0 M decayconstant.IntheVMDmodel,takingthezerowidth gral ∞dsR (s)e−s/M2 isevaluatedinsertingtherunning s0 c limit,eq.(14)holdsforboththeωandρmeson,withequal R couplingstrengthα (s )ineq.(9).Thentheterm-by-term S o mass m = m = m . Inserting s = 16π2f2 in eq.(14) V ρ ω 0 π comparison in eq.(8) gives the following set of sum rules one recovers the famous KSFR relation m =√2 gf up V π for the moments of the spectrum R(s) (see also refs. [7, to a small QCD correction. 8]) The sum rule (11) for the first moment gives s0 Zs00 dsR(s)= ss02c0+c1−12π2Π(0), (10) 8gπ22m4ω = s220 (cid:16)1+ απS(cid:17)−π32 hhαπSG2i+12hmuu¯u+mdd¯dii. dssR(s)= 0c c , (11) Z 2 0− 2 (15) 0 4 F. Klingl and W. Weise: Model independentconstraints from vacuumand in-medium QCD Sum Rules Inserting the values for the gluon and quark condensates – the in-medium case: wefindindeedperfectconsistency.Givenamodelfortheω now we have to match the moments of the density mesonspectralfunction inthe vacuumandin the nuclear dependent spectral distributions, medium, the sum rules (10,11) therefore provide useful s0 s α (s ) 3π2 0 S 0 dsR(s,ρ)= 1+ + ρ, (17) Z 6 (cid:18) π (cid:19) M constraints to test the calculated spectra. 0 N We nowcontinueonfromVMDtoamorerealisticap- together with proach.Inrefs.[3,4]wehaveusedaneffectiveLagrangian s0 s2 α (s ) dssR(s,ρ)= 0 1+ S 0 c (0) δc (ρ). 2 2 Z 12(cid:18) π (cid:19)− − based on chiral SU(3) SU(3) symmetry with inclusion 0 ⊗ (18) of vector mesons as well as anomalous couplings from Using our calculated spectrum [4] shown in Fig. 1b, the Wess-Zumino action in order to calculate the ω me- we find √s0 = 1.08GeV at ρ = ρ0 = 0.17fm−3, with son spectrum both in the vacuum and in nuclear mat- s0dsR(s,ρ ) = 0.26GeV2. Then s0dssR(s,ρ ) = 0 0 0 0 ter. The resulting vacuum spectrum reproduces the ob- R R 0.11GeV4 is to be compared with the right hand side served e+e− hadrons(I = 0) data very well [3] (see → of eq. (18) which gives 0.12GeV4, so there is again Fig. 1a). The predicted in-medium mass spectrum (for excellent consistency. ω excitations with q = 0) shows a pronounced down- Note again that these tests do not involve uncertain wardshiftoftheω-mesonpeakandasubstantial,butnot four-quarkcondensates.Furthermore,ifthein-medium overwhelmingincreaseof its width from reactionssuch as spectrumshowsareasonablynarrowquasiparticleex- ωN πN, ππN etc. (see Fig. 1b). At large s>s , both → 0 citation, the quantity m¯2 = s0dssR(s)/ s0dsR(s) 0 0 spectra should approach the QCD limit (9). The consis- R R canindeedbeinterpretedasthesquareofanin-medium tency test of these calculated spectral distributions with “mass”ofthisexcitation.Forourωmesoncasewefind the sum rules (10) and (11) goes as follows: m¯ =0.65GeVatρ=ρ ,asubstantialdownwardmass 0 – the vacuum case: shift as discussed in refs. [3,4]. (For the broad ρ me- the two sides of eq. (10), sonspectrum,ontheotherhand,theinterpretationof s0 s α (s ) m¯ as an in-medium mass is not meaningful as demon- 0 S 0 dsR(s)= 1+ , (16) Z 6 (cid:18) π (cid:19) 0 strated in ref. [3]). now match at √s0 = 1.25GeV, with 0s0dsR(s) = Amusingly, the spectral gap ∆ = √s0 decreases by R 0.29GeV2. The sum rule for the first moment gives about 15 percent when replacing the vacuum by nu- s0dssR(s)=0.19GeV4,tobecomparedwith 1s2(1+ clear matter. This is in line with the proposition that 0 2 0 R α /π) c =0.22GeV4, so there is consistency at the this gap reflects the order parameter for spontaneous s 2 − 10% level. chiral symmetry breaking and scales like the pion de- F. Klingl and W. Weise: Model independentconstraints from vacuumand in-medium QCD Sum Rules 5 cay constant f (or, equivalently, like the square root π of the chiral condensate q¯q ). h i In summary, we have shown that the combination of sum rules (10) and (11)for the lowestmoments of the spectraldistributionsdoesserveasamodel-independent consistency test for calculated spectral functions. References 1. T. Hatsudaand S.H. Lee, Phys. Rev. C 46 (1992) R34. 2. M.A. Shifman, A.I. Vainshtein and V.I. Zakharov, Nucl.Phys. B 147 (1979) 385. 3. F. Klingl, N. Kaiser and W. Weise, Nucl. Phys. A 624 (1997) 527 4. F. Klingl and W.Weise, preprint hep-ph/9802211, submit- ted to Nucl. Phys.A; ActaPhys. Pol. B 29 (1998) 3225 5. S. Leupold, W. Peters and U. Mosel, Nucl. Phys. A 628 (1998) 311. 6. B.BorasoyandU.-G.Meissner,Phys.Lett.365(1996)285. 7. T. Hatsuda, S.H. Lee and H. Shiomi, Phys. Rev. C 52 (1995) 3364. 8. N. V. Krasnikov, A. A. Pivovarov and N. N. Tavkhelidze, Z. Phys. C 19 (1983) 301; Th. Sch¨afer, Dissertation, Univ. Regensburg(1992). 9. L.J. Reinders, H.R. Rubinstein and S. Yazaki, Phys. Re- ports 127 (1985) 1. 10. L.M.Barkovetal.,JETPLett.46 (1987)164;S.I.Dolin- sky et al., Phys. Reports 202 (1991) 99. 6 F. Klingl and W. Weise: Model independentconstraints from vacuumand in-medium QCD Sum Rules 101 101 (b) Barkov (3π) Dolinsky (3π) 100 Dolinsky (I=0) ρ=0 ρ=ρ 100 0 s) R( 10-1 10-1 10-2 ((aa)) 10-3 10-2 0.6 0.8 1.0 1.2 1.4 0.4 0.6 0.8 1.0 1.2 √s [GeV] √s [GeV] Fig. 1. a) SpectrumR(s)in theω meson channelas calculated in ref. [3] (solid line). Thedatapointsrefer toe+e− →3π and e+e− → hadrons (I =0) [10] b) In-medium spectrum of ω meson excitations in nuclear matter at density ρ0 = 0.17fm−3 as calculated in refs.[3,4] (solid line) in comparison with the vacuumspectrum (dashed line).

See more

The list of books you might like

Most books are stored in the elastic cloud where traffic is expensive. For this reason, we have a limit on daily download.