ebook img

Lyapunov exponents and anomalous diffusion of a Lorentz gas with infinite horizon using approximate zeta functions PDF

14 Pages·0.17 MB·English
Save to my drive
Quick download
Download
Most books are stored in the elastic cloud where traffic is expensive. For this reason, we have a limit on daily download.

Preview Lyapunov exponents and anomalous diffusion of a Lorentz gas with infinite horizon using approximate zeta functions

Lyapunov exponents and anomalous diffusion of a Lorentz gas with infinite horizon using approximate zeta functions Per Dahlqvist Mechanics Department 5 Royal Institute of Technology, S-100 44 Stockholm, Sweden 9 9 1 n a J 2 1 Abstract - We compute the Lyapunov exponent, generalized Lyapunov exponents v and the diffusion constant for a Lorentz gas on a square lattice, thus having infinite 1 horizon. Approximate zeta functions, written in terms of probabilities rather than 0 0 periodic orbits, are used in order to avoid the convergence problems of cycle expan- 1 sions. The emphasis is on the relation between the analytic structure of the zeta 0 function, where a branch cut plays an important role, and the asymptotic dynam- 5 ics of the system. We find a diverging diffusion constant D(t) ∼ logt and a phase 9 transition for the generalized Lyapunov exponents. / n y d - o a 1 Introduction h c : v MaybethemostwellknownmeasureofachaoticsystemistheLyapunovexponent. Inthetheory i ofchaoticdynamicsoneisofcourseinterestedincalculatingthisandsimilarquantities,eitherby X findinganalyticalestimatesorbydevisingeffectivecalculationschemesbutoftenonefindoneself r compelled to numerical simulation. This is unsatisfactory since it is not an easy task to extract a information on the asymptotic behaviour from numerical data. Variousaveragesofchaotic systems areobtainablevia transfer operatorsandandtheir Fred- holm determinants or zeta functions. This is a beautiful formalism but the best results are obtained for a very restricted class of chaotic systems, namely those fulfilling Axiom-A. This is because Axiom-A guarantees nice analytical features of the zeta functions [1, 2, 3, 4] which enables fast convergent cycle expansions to deduce its leading zeros [5]. Applications of cycle expansions to non Axiom-A systems are not very successful [6, 7]. Inthispaperwewillstudyasystemwhichisfarfromthetextbook1-dAxiom-Amap,namely the two-dimensional Lorentz gas on a square lattice. This is a Hamiltonian system with two degreesoffreedom,continous time andwith aninfinite symbolic dynamics. We will demonstrate that zeta functions may be of great use even here. The key point is that we will avoid writing the zeta function in terms of periodic orbits as that would lead us to divergence problems that we could not handle. The price we will pay is that our zeta functions are no longer exact, but they are approximate in a sense that won’t effect the leading zero very much. The averages we willcomputearedirectlyrelatedto themotionofthis leadingzerowithrespectto variationsofa parameter. However, matters will be complicated if there are non-analyticities in the vicinity of the leading zero,like branchcuts. This is, we believe, a genericfeature ofnon Axiom-Asystems. Such singularities will cause problems for cycle expansions but do carry important information 1 Lyapunov exponents and anomalous diffusion ... 2 about the asymptotic dynamics. In the Lorentz gas there will be a branch cut connected to the existence of the infinite horizon. It will not prevent the Lyapunov exponent from being well defined but will yield a diverging diffusion constant. It will also imply a phase transition for the generalized Lyapunov exponents. In section 2 we review the necessary theory. In section 3 we perform all calculations and we then end with some comments in section 4. 2 Theory 2.1 Lyapunov exponents and zeta functions The largest Lyapunov exponent is defined by 1 λ= lim log|Λ(x ,t)| , (1) 0 t→∞ t provided the limit exists and is independent of the initial point x (except for a set of measure 0 zero: namely the periodic points). Λ(x ,t) is the largest eigenvalue of the Jacobian along the 0 trajectorystarting at x and evolvingduring time t. Using ergodicity this may be rewritten as a 0 phase space average 1 1 λ= µ(dx)log|Λ(x ,t)|≡ <log|Λ(x ,t)|> , (2) 0 0 t Z t where µ(dx) is the invariant density. We willnowformulatetheLyapunovexponentintermsofevolutionoperatorsandzetafunc- tions. Consider the following evolution operator acting on a phase space density Φ(x) according to Lt Φ(x)= w(x,t)δ(x−ft(y))Φ(y)dy . (3) w Z Itis essentialfor the further developmentthatthe weightw(x,t) is multiplicative along the flow. Weintendtoevaluatethetraceofthisoperatorasthatgivestheexpectationvaluesoftheweight (see appendix) <w >= lim trLt . (4) w t→∞ The trace naturally turns out to be a sum over the periodic orbits ∞ δ(t−nT ) trLt = w(x,t)δ(x−ft(x))dx= T wn p , (5) w Z p p|det(1−Mn)| Xp nX=1 p wherenisthenumberofrepetitionsofprimitiveorbitp,havingperiodT ,andM istheJacobian p p (transverse to the flow). w is the weight associated with cycle p. p Zeta functions are introduced by observing that the trace may we written as 1 ∞−ia Z′ (k) trLt = eikt w dk . (6) w 2πiZ Z (k) −∞−ia w For a Hamiltonian system with two degrees of freedom the zeta function reads [8] ∞ e−ikTp m+1 Z (k)= 1−w , (7) w (cid:18) p|Λ |Λm(cid:19) Yp mY=0 p p where Λ is the expanding eigenvalue of M . p p Suchinfiniteproductsoverperiodicorbitsareoftentroublesomebecausetheydivergebeyond the first(nontrivial) zero. It is essentialthat the constanta in eq. (6) is sufficiently largeso that the products converge. In our subsequent calculation it suffices if a is small and positive. Lyapunov exponents and anomalous diffusion ... 3 Cycleexpansionsofthezetafunctionsgenerallyhavebetterconvergencepropertiessincethey converge up to the first singularity [5]. The zeta function is entire for Axiom-A system which makes cycle expansions very successful for this special case. In this paper we will consider cases where the leading zero is also a singularity (branch point) so a cycle expansionwill not converge even there and the zeta function is rather useless as it stands. We return to these problems in section 2.3. We must now find a weight w appropriate for computing the Lyapunov exponent. The quantitywhoseaveragewearegoingtostudyislog|Λ(x ,t)|whichiscertainlynotmultiplicative. 0 Inonedimensionwecanstudytheaverageofthemultiplicativeweightw =|Λ(x ,t)|τ andobtain 0 the Lyapunov exponent by differentiation 1dtrLt λ= lim τ| . (8) τ=0 t→∞ t dτ The problem to find the appropriate weighted operator in more dimensions is nontrivial and the problem was recently solved [9]. But for our purposes it will suffice to insert the weight w aboveintothe operatorLt justdefined. Themodificationin[9]tomakew exactlymultiplicative w is complicated but minor and we don¡t expect it to affect the leading zero of the zeta function, and its vicinity, in which we are interested. The leading zero k (τ) = −i·h(τ) is always on the negative imaginary axis, if τ > 0. It 0 provides the leading asymptotic behaviour of the trace provided that there is a gap until next zero or singularity. Then we have d λ= h(τ) . (9) dτ Generalized Lyapunov exponents [10] λ(τ) are defined by considering the scaling behaviour of <|Λ(x ,t)|τ >: 0 <|Λ(x ,t)|τ >= lim trLt =eλ(τ)τt , (10) 0 τ t→∞ so that h(τ) λ(τ)= , (11) τ provided again that the leading zero is isolated. The ordinary Lyapunov exponent is recognized as the limit λ=lim λ(τ). τ→0 2.2 Diffusion coefficients and zeta functions We will consider the Lorentz gas obtained by unfolding the Sinai billiard. The coordinate in the unfolded systemis called xˆ. The correspondingvectorin the billiard(or the unit cell) is x. They arerelatedby translationxˆ−x∈T where T is the groupoftranslationsbuilding up the Lorentz gas from the unit cell. The diffusive properties can be extracted from the average <eβ·(fˆt(x0)−x0) > . (12) x0 The average is taken over one unit cell. Again we must perform the trick to introduce a multi- plicative weight and then by differentiation extract the averagein which we are interested Itwasdemonstratedinref[11]thatthisaveragecanbecomputedbyconsideringthedynamics in the unit cell only. This is obtained by inserting the weight w(x,t)=eβ·(fˆt(x)−x) (13) into the evolution operator (3). The diffusion constant is now given by 1 ν 1 ν ∂2 D = lim <(fˆ(x )−x )2 > = lim trLt . (14) t→∞νt 0 0 x0 t→∞νt ∂β2 β Xi=1 Xi=1 i where the sum is taken over spatial components of the 2ν dimensional phase space. Lyapunov exponents and anomalous diffusion ... 4 2.3 Approximate zeta functions In some recent publications we have investigated a way of approximating zeta functions for intermittent systems [7, 12, 13]. We call it the BER-approximation after the authors of ref [14]. In an intermittent system laminar intervals are interrupted by chaotic outbursts. Let ∆ i be the time elapsed between two successive entries into the laminar phase. The index i labels the i’th interval. Provided the chaotic phase is chaotic enough, the lengths of the intervals ∆ i are presumed uncorrelated, and ∆ may be considered as a stochastic variable with probability distributionp(∆). The zeta functions (unit weightw=1)may then be expressedinterms ofthe Fourier transform of p(∆) ∞ Z(k)≈Zˆ(k)≡1− e−ik∆p(∆)d∆ . (15) Z 0 Duetothenormalizationofp(∆)weseethatleadingzerok =0isbyconstructionexactbecause 0 of probability conservation. Inordertocomputetheprobabilitydistributionweintroduceasurfaceofsection(SOS).This should,accordingto the BERprescriptionbe put onthe borderbetweenthe laminarandchaotic phase. We call the phase space of the SOS Ω and its coordinates x . The flight time to the next s intersection is then a function of x : ∆ (x ). The probability distribution then reads s s s p(∆)= δ(∆−∆ (x ))µ(dx ) , (16) s s s Z Ω where µ(dx ) is the invariant density, which is uniform µ(dx ) = dx / dx for Hamiltonian s s s Ω s ergodic system, assuming of course that the SOS coordinates are canonicRally conjugate. It is straightforward to include weights in this formalism, like e.g. w = |Λ(x )|τ. The local 0 expansionfactorΛ (x )isalsoafunctionofx . Thezetafunctionisthenrelatedtoageneralized s s s distribution p (∆)= |Λ (x )|τδ(∆−∆ (x ))dx . (17) τ s s s s s Z Ω The zeta function Zˆ (k) is obtained by inserting p (∆) into (15). τ τ 3 Application to the Lorentz gas We now begin our study of the Lorentz gas on a square lattice. The lattice spacing is unity, the disk circular with radius R<1/2, and the point particle bouncing around in this array has unit velocity. Itistheunitcellofthissystem,theSinaibilliard[15]whosedynamicswewillstudyand this is indeed an intermittent system; there exist periodic orbits with arbitrary small Lyapunov exponents logΛ /T . The disk will define our SOS. We use the two angles φ and α defined in p p fig 1a as coordinates. The normalized measure is then dx = dφ d(sinα)/4π. Consider now a s segment of the trajectory between two disk collisions. This segment can be labeled according to the disk that would be hit in the unfolded system, the label q=(n ,n ) is the associatedlattice x y vector[12]. It is easy to realize that only disks associatedwith coprime lattice vectormay occur. The purpose is now to apply the BER approximationto this system and compute Lyapunov exponents and diffusion constants, cf refs [12, 13]. 3.1 Calculation of pτ(∆) In this section we will derive the following approximate expression for p (∆) τ 4Γ(2−2τ)2R1−τ∆τ ∆≤1/2R pτ(∆)≈ 43ΓΓ((22−2−ττ))22τ/2−3R−τ/2−2 ∆>1/2R . (18) 3 Γ(2−τ) ∆3−3τ/2  Lyapunov exponents and anomalous diffusion ... 5 Figure1: a)TheSinaibilliardwithdefinitionsof thevariables φandα. b)Theunfolded system with free directions (corridors) indicated. c) The region of integration. Lyapunov exponents and anomalous diffusion ... 6 This expressionwasused alreadyin ref[13] but asit plays a centralrolein this paper wepresent its derivation in some detail. Complementary details may be found in refs [12, 13]. We start from expression (17) for p (∆). First we partition the SOS into subsets Ω where τ q Ω is the part of Ω for which the trajectory hits disk q. Then we smear the distribution, that is, q wereplacethedeltafunctionwithsomeextendeddistributionδ . Theexactformofthisfunction σ is irrelevant, the only thing we assume is that the width is big: σ ≫1. We will be interested in the behaviour of the leading zero of Zˆ (k) for small τ. This zero is then close to the origin and τ it is evident that smearing of p (∆) will only have minor effect on this zero. τ We now have p (∆)= |Λ (x )|τδ (∆−∆ (x ))dx . (19) τ s s σ s s s Z Xq Ωq The large width σ allow us to move the smeared delta function to the left of the integral sign because the variation of ∆ (x ) over Ω is of the order ∼R and we have σ ≫1>R. s s q p (∆)= δ (∆−q) |Λ (x )|τdx ≡ δ (∆−q)a (τ) . (20) τ σ s s s σ q Z Xq Ωq Xq We have chosen the length of the lattice vector |q| ≡ q as a mean value of ∆ (x ). The local s s expansion factor is |Λ (x )|=2∆ (x )/Rcos(α). s s s s It is easily shown that the phase space area taken up by disk q is given by the inequality q | sin(φ−θ −α)+sin(α)|<1 , (21) q R where θ is the polar angle of the lattice vector q. Generally parts of this region are eclipsed by q disks closer to the origin. So in order to find Ω one has to subtract these. We will focus on the q limit of small R which gives the more easily handled inequality q | (φ−θ −α)+sin(α)|<1 . (22) q R Let us begin with the limit of small ∆. In ref [12] it is shown that if disk q lies within a certain radius: q < 1/2R, there are no eclipsing disks in front of it, and expression (22) may be used directly, and the integral is easily calculated: 2q 1 1 Γ(2−τ)2 R a (τ)=( )τ cosτ+1(α)dαdφ≈ 2 ( )1−τ . (23) q R 4π Z 4πΓ(2−τ) q Ωq Inordertofindanapproximateexpressionforp (∆)wemustknowthedensityofcoprimelattice τ points, i.e. the average number d (r)dr of such points having a distance between r and r+dr c from the origin. In ref [13] this was, to leading order, found to be d (r)≈ 16πr. This yields c 13 16Γ(2−τ)2 p (∆)= δ (∆−q)a (τ)= 2 R1−τ∆τ . (24) τ σ q 13Γ(2−τ) Xq Obviously the disk radius has to be small for this to apply. Nextweconsiderthe oppositelimit∆≫1/2R. Foreach(coprime)diskqfulfilling q <1/2R therearetwo(orone,dependingonsymmetry)transparentcorridorinthedirectionq[12,16],see fig 1b. Far beyond this critical radius the accessible disks will be those adjacent to the corridors. (They still have to coprime so they will lie on one side of the corridor only, see fig 1b). We will discover that this will lead to a power law decay of p(∆). We will be interested in the particular power (as a function of τ) and not the prefactor. For that reason we perform our calculation in the corridor having direction vector (1,0) as all corridors provide the same power. In this corridor the accessible disks are the ones being labeled (n,1). Disk (n,1) is shadowed by (1,0) and (n−1,1). We need to evaluate the integral (cf eq (23)) j ≡ cosτ+1(α)dαdφ . (25) n Z Ωq=(n,1) Lyapunov exponents and anomalous diffusion ... 7 ’Numerical’ 2 Theory 1.5 1 0.5 0 0 0.05 0.1 0.15 0.2 0.25 Figure 2: Lyapunov exponent versus disk radius according to numerical simulation and eq (32). It is more convenient to consider the sum ∞ J ≡ j = cosτ+1(α)dαdφ , (26) n i Z ∞ Xi=n i=nΩq=(n,1) S because this integral has support from the triangular region in fig 1c (it is a triangle only in the limit n→∞ of course). From eq (22) one can deduce that the base length (in the φ direction) of this triangle scales as ∼ 1/n and the height ( in the α direction) as 1/ (n). A short calculation now yields that Jn ∼1/n2−τ/2. Differentiation gives jn ∼1/n3−τ/2. pThe fact that lq ∼n together with eq. (23) impliesthatthe a ’sdecayas∼1/n3−3τ/2. The densityofaccessibledisksisuniformin∆(since q they lie along the corridors)so our final result is p(∆)∼ 1 ∆≫ 1 . (27) ∆3−3τ/2 2R This power law does not depend on the small R limit. The prefactor of eq (27) is determined by demanding that p (∆) is continous at ∆ =1/2R. τ In order to get correct normalization for τ = 0 we multiply the entire p (∆) by 13/12. This τ approximation means a rather crude neglect of the of the transitional behaviour at ∆ ≈ 1/2R. In the following we must be very cautious when using it since some results may be more sensible to our approximation than other. 3.2 Lyapunov exponents The approximate zeta function we are going to work with is obtained from (18) Zˆ (k)≈ 1− ∞e−ik∆p (∆)= τ 1−R40Γ(2−2τ)2R−τ2τ(z−1−τγ(τ +1,z)+z2−3τ/2Γ(2+3τ/2,z)) , (28) 3 Γ(2−τ) 21+τ Lyapunov exponents and anomalous diffusion ... 8 wherez = ik. Thefunctionsγ(a,z)andΓ(a,z)areincompletegammafunctions[17]. Expanding 2R this to first order in τ gives Z = z+ z2(logz+γ− 11)... + 3 6 (29) n o (− 7 +log(2R2))+(11 +log(2R2))z... τ ... 12 6 (cid:8) (cid:9) The derivation of this expansion is rather lengthy but the only step that is slightly tricky is the expansion of the incomplete gamma function Γ(a,z) near an integral power a. We have for conveniencethrownawayallindices ofthe zetafunction anduse strict equalitysignbut we must not forget that we work with an approximationof an approximation of the exact zeta function. We must now proceed with some care since the leading zero is not isolated, a branch cut along the negative real z-axis reaches all the way up to it (we have choosen the principal branch of the logarithm). We are interested in the following derivative of the trace, cf eq (8) d trLt = d 1 ezt′ d logZ dz | = 1 ezt′ d d logZ | dz , (30) τ=0 τ=0 dτ dτ 2πiZ dz 2πiZ dτ dz where we have differentiated inside the integral sign. We have now formulated eq (6) in the rescaled and rotated z−plane using rescaled time t′ = 2Rt. The function to be Fourier trans- formed is d d 7 1+ z(2logz+2γ− 5)... 7 1 1 logZ | =( −log(2R2)) 3 6 =( −log(2R2))( + ...) , dτ dz τ=0 12 z+ z2(logz+γ− 11)2... 12 z2 3z 3 6 (31) wherewehavekeptonlythosetermsyieldingtheleadingtermandthefirstcorrection. Collecting it all together yields 7 1 7 λ= lim2R( −log(2R2))(1+ ...)=2R( −log(2R2)) . (32) t→0 12 6Rt 12 Thelimitingvalueisduetothebehaviourofthezerobutthepowerlawcorrectionaredue tothe factthat it sits on a branchpoint. The particularsize ofthe firstcorrectionis not veryaccurate, aswewillrealizeafterreadingsection3.4and3.5,buttheimportantthingtobearinmindisthat there exist slowly decaying corrections indicating slow convergence of the Lyapunov exponent in numerical computations. In fig 2 we compare numerical results on the Lyapunov exponent with our expression λ = 2R( 7 −log(2R2)). The numerical values, from [18], are calculated for rather large disk radii, 12 whereweshouldnotexpectmuchagreementapriori. Neverthelessourestimateisonly5%wrong whenR=0.1. ThereasonwhythethenumericalvaluesexceedourestimatesforlargeRiseasily understood. This is because the disk faces (in the unfolded system) come closer to each other so that taking the length of the relevant lattice vector (as we did) overestimates the time of flight between them. The Lyapunov exponent of the corresponding Poincar´e map with the disk defining the SOS is related to the Lyapunov exponent of the flow according to [19] λ = λ < ∆ >≈ λ/2R ≈ map s ( 7 −log(2R2)) where < ∆ > is computed by means of expression (18). We see that λ → 12 s −2log(R)+7/12−log2 when R → 0 which agrees with the conjectured limit [20, 21]: λ → −2log(R) + C + O(R). Indeed we have analytically found an estimate of the constant C ≈ 7/12−log2 ≈ −0.110. This is very close to the numerical value found by [20], as far as we can extract it from fig 2 in ref [20]). In fig 3 we plot the generalized Lyapunov exponents for different disk radii. Note that when τ >0theleadingzeroisindeedisolatedandwedonothavetoworryaboutthecut. Theposition of the zero is computed numerically. λ(1) is the topological entropy which tend to a finite limit when R → 0 [12], whereas λ(0) → 0 as R → 0. When τ < 0 the branch cut itself will provide the leadingbehaviourofthe trace -a powerlaw[12,13], andthe generalizedLyapunovexponent will be zero. This means that λ(τ) cannot be analytic at τ = 0. This is referred to as a phase transition [10, 22]. Lyapunov exponents and anomalous diffusion ... 9 ’R=0.01’ ’R=0.1’ 2 1.5 1 0.5 0 0 0.2 0.4 0.6 0.8 1 Figure 3: Generalized Lyapunov exponents λ(τ) versus τ for two disk radii. 3.3 A first calculation of the diffusion constant In order to study diffusion we calculate the generalized probability distribution p (∆) using w appropriate weight (13). However, we only keep the spatial components of β yielding the two dimensional vector β. As we study smeared p (∆) it suffices to approximate the spatial part β of (fˆt(x)−x) with the lattice vector q. So, we must now compute the generalized probability distribution pβ(∆) a la section 3.1 but using the weight exp(β·q)=exp(βqcos(φβ −φq) where we have written q = q(cos(φ ),sin(φ )) and β = β(cos(φ ),sin(φ )). We can use the result q q β β of section 3.1 to some extent, since we realize, after inspecting eq (17), that we can make the following factorization e∆βcos(φq−φβ)dφq pβ(∆)=p0(∆)R dφ (33) q R To know the support of this integral we need to know about the angular distribution of access- able disks for a particular value of q = ∆. To this end we introduce the following simplifying assumptions 1. the coprime lattice points are distributed isotropically. 2. if q >1/2R we assume only four corridors with φ equal to one of 0, π/2, π or 3π/2. q Assumption 2 means a rather brute neglect of the transitional behaviour at ∆ ≈ 1/2R. We neglect the important fact the number of corridors grows when R → 0. We comment on this in section 3.5. The important thing now is that we preserve the symmetry in order to prevent net drift. We first consider the case q <1/2R. Using assumption 1 above gives 4 1 2π 4 4 β2∆2 pβ(∆)= 3R2π Z eβ∆cosφdφ= 3RI0(β∆)= 3R(1+ 4 ...) ∆< 21R , (34) 0 Lyapunov exponents and anomalous diffusion ... 10 whereI is a modified Besselfunction Inorderto calculatethe zeta functionwe needthe Fourier 0 transform of this 1/2R 2 β′2 pβ(∆)e−ik∆d∆= (1−z/2+z2/6...)+ (1/3−z/4+z2/10...) ,... (35) Z 3 6 0 where we have used rescaled variables z =ik/2R and β′ =β/2R. Next we consider the limit q >1/2R. We find, using the second assumption above pβ(∆)= 3(22R)2∆13(eβx′∆+e−βx′∆+eβy′∆+e−βy′∆) ∆> 21R . (36) Fourier transforming this gives ∞ 1 Z pβ(∆)e−ik∆d∆= 6(E3(z−βx′)+E3(z+βx′)+E3(z−βy′)+E3(z+βy′)) . (37) 1/2R The resulting zeta function can now be expanded Zβ =1− 0∞pβ(∆)e−ik∆d∆= 61(γ− 161)β′2+z(1− 81β′2)+z213(γ− 161)+ R 1 [(z−β′)2log(z−β′)+(z+β′)2log(z+β′)+ 12 x x x x (38) (z−β′)2log(z−β′)+(z+β′)2log(z+β′)] y y y y ... According to sec 2.2, we are interested in the following quantity (∂∂β22 + ∂∂β22)trL|β′=0= (∂∂β22 + ∂∂β22)21πi ezt′ddz logZ dz |β=0 x y x y (39) = 1 1 ezt′(R∂2 + ∂2 ) d logZ | dz . (2R)22πi ∂β′2 ∂β′2 dz β=0 R x y We now proceed in the same way as in sec 3.2. We want to determine the asymptotic behaviour of the fourier transform of ∂2 ∂2 d 2 4 (∂β′2 + ∂β′2)dz logZ |β=0∼ 3z2(3 −logz−γ) . (40) x y To this end we now need the following integral 1 logzezt′dz =t′(1−γ−logt′) . (41) 2πiZ z2 Inderivingthisitisconvenienttousecontourintegrationandletthecontourencirclethenegative real z axis. We thus find the following diverging diffusion constant (D =lim D(t)) t→∞ 1 ∂2 ∂2 1 D(t)= 2t(∂β2 + ∂β2)trLt |β′=0= 18R(1+3log(2Rt)) . (42) x y This logarithmic divergence of the diffusion constant agrees with ref [16] but the prefactor is not correct. The computation will be refined in the section 3.5. The important thing to learn from this section is that the Laplacian exposes the logarithm in the series expansion of the zeta function. So we now know where to focus our attention, namely at the tail of pβ(∆). 3.4 A closer look at the tail Attheendofsection3.1weaimedatfindingagoodapproximationforp (∆)forthewholerange τ 1/2R< ∆< ∞. In this section we will make a more careful investigation of the ∆ → ∞ tail of p (∆). We restrict ourselves to the case τ = 0 and will compute the limit lim ∆3p (∆) for τ ∆→∞ 0 small disk radii.

See more

The list of books you might like

Most books are stored in the elastic cloud where traffic is expensive. For this reason, we have a limit on daily download.