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Isoperimetry between exponential and Gaussian PDF

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Isoperimetry between exponential and Gaussian 7 0 0 F. Barthe, P. Cattiaux and C. Roberto 2 n February 2, 2008 a J 9 2 Abstract Westudy theisoperimetric problem for product probability measures ] R withtailsbetweentheexponentialandtheGaussianregime. Inparticular we exhibit many examples where coordinate half-spaces are approximate P solutions of theisoperimetric problem. . h t a 1 Introduction m [ This paper establishes infinite dimensional isoperimetric inequalities for a wide 2 classofprobabilitymeasures. Weworkinthe settingofaRiemannianmanifold v (M,g). ThegeodesicdistanceonM isdenotedbyd. FurthermoreM isequipped 5 withaBorelprobabilitymeasureµwhichisassumedtobeabsolutelycontinuous 7 4 with respect to the volume measure. For h 0 the closed h-enlargement of a ≥ 1 set A M is ⊂ 0 A := x M; d(x,A) h , h 6 ∈ ≤ 0 where d(x,A) := inf d(x,a); a(cid:8) A is + by conv(cid:9)ention for A = . We may { ∈ } ∞ ∅ / define the boundary measure, in the sense of µ, of a Borel set A by h t a µ(A A) h m µs(∂A):=liminf \ h→0+ h · : v An isoperimetric inequality is a lower bound on the boundary measure of sets i X in terms of their measure. Their study is an important topic in geometry, see e.g. [37]. Finding sets of given measure and of minimal boundary measure is r a verydifficult. Inmanycasestheonlyhopeistoestimatetheisoperimetricfunc- tion (also called isoperimetric profile) of the metric measured space (M,d,µ), denoted by I µ I (a):=inf µ (∂A); µ(A)=a , a [0,1]. µ s ∈ (cid:8) (cid:9) For h > 0 one may also investigate the best function R such that µ(A ) h h ≥ R (µ(A)) holds for all Borel sets. The two questions are related, and even h equivalent in simple situations, see [17]. Since the function α(h)=1 R (1/2) h − istheso-calledconcentrationfunction,theisoperimetricproblemforprobability 1 measures is closely related to the concentration of measure phenomenon. We refer the reader to the book [32] for more details on this topic. The main probabilistic example where the isoperimetric problem is com- pletely solvedis the Euclideanspace(Rn, ) withthe standardGaussianmea- |·| sure, denoted γn in order to emphasize its product structure dx dγn(x)=e−|x|2/2 , x Rn. (2π)n/2 ∈ Sudakov-Tsirel’son[39]andBorell[19]haveshownthatamongsetsofprescribed measure, half-spaces have h-enlargements of minimal measure. Setting G(t) = γ(( ,t]), their result reads as follows: for A Rn set a=G−1(γn(A)), then −∞ ⊂ γn(A ) γ ( ,a+h] =G G−1 γn(A) +h , h ≥ −∞ (cid:0) (cid:1) (cid:16) (cid:0) (cid:1) (cid:17) and letting h go to zero (γn) (∂A) G′(a)=G′ G−1 γn(A) . s ≥ (cid:16) (cid:0) (cid:1)(cid:17) Theseinequalities arebestpossible,hence I =G′ G−1 isindependent ofthe γn ◦ dimension n. Such dimension free properties are crucial in the study of large random systems, see e.g. [31, 41]. Asking which measures enjoy such a dimen- sionfreeisoperimetricinequalityisthereforeafundamentalquestion. Letus be more specific about the products we are considering: if µ is a probability mea- sureon(M,g),weconsidertheproductµnontheproductRiemannianmanifold Mn where the geodesic distance is the ℓ combination of the distances on the 2 factors. Considering the ℓ combinationis easier andleads to different results, ∞ see [12, 16, 7]. In the rest of this paper we only consider the ℓ combination. 2 It can be shown that Gaussian measures are the only symmetric measures on the real line such that for any dimension n, the coordinate half-spaces x Rn; x t solvetheisoperimetricproblemforthecorrespondingproduct 1 {mea∈sure on R≤n.}See [14, 28, 34] for details and stronger statements. Therefore itisnaturaltoinvestigatemeasuresonthereallineforwhichhalf-linessolvethe isoperimetricproblem,andinanydimensioncoordinatehalf-spacesareapprox- imate solutions of the isoperimetric problemfor the products,up to a universal factor. Moregenerally,one looksformeasuresonthe line for whichthereexists c<1 with Iµ Iµ∞ cIµ, (1) ≥ ≥ where by definition Iµ∞ := infn≥1Iµn. Note that the first inequality is always true. Inequality (1) means that for any n, and ε > 0, among subsets of Rn with µn-measure equal to a (0,1) there are sets of the form A Rn−1 with ∈ × boundary measure at most c−1+ε times the minimal boundary measure. Dimension free isoperimetric inequalities as (1) are very restrictive. Heuris- tically one can say that they force µ to have a tail behaviour which is inter- mediate between exponential and Gaussian. More precisely, if Iµ∞ cIµ is ≥ 2 boundedfrombelow by a continuouspositive function on(0,1),standardargu- ments imply that the measures µn all satisfy a concentration inequality which isindependentofn. AsobservedbyTalagrandin[40],this propertyimplies the existenceofε>0suchthat eε|t|dµ(t)<+ ,see[16]formorepreciseresults. ∞ In particular, the central limit theorem applies to µ. Setting m = xdµ(x), it R allows to compute the limit of R n 1 µn x Rn; (x m) t . i ∈ √n − ≤ (cid:16)(cid:8) Xi=1 (cid:9)(cid:17) Under mild assumptions it follows that for some constant d, cIµ Iµ∞ dIγ. ≤ ≤ Thus the isoperimetric function of µ is at most a multiple of the Gaussian isoperimetricfunction. Inparticularifµissymmetricwithalog-concavedensity, this is known to imply that µ has at least Gaussian tails. For the symmetric exponential law dν(t) = e−|t|dt/2, t R, Bobkov and ∈ Houdr´e[15]actuallyshowedIν∞ Iν/(2√6). Theirargumentusesafunctional ≥ isoperimetric inequality with the tensorization property. In the earlier paper [40], Talagrand proved a different dimension free isoperimetric inequality for the exponential measure, where the enlargements involve mixtures of ℓ and 1 ℓ balls with different scales (this result does not provide lower bounds on the 2 boundary measure of sets). In a recent paper [8] we have studied in depth various types of inequalities allowingtheprecisedescriptionofconcentrationphenomenonandisoperimetric profileforprobabilitymeasures,intheintermediateregimebetweenexponential and Gaussian. Our approachof the isoperimetric inequalityfollowedthe one of Ledoux[30](whichwasimprovedin[4]): westudiedtheimprovingpropertiesof the underlying semigroups, but we had to replace Gross hypercontractivity by a notion of Orlicz hyperboundedness, closely related to F-Sobolev inequalities (seeEquation(7)inSection6foradefinition). Thisapproachyieldsadimension free description of the isoperimetric profile for the measures dν (t) = e−|t|αdt α for 1 α 2: there exists a universal constant K such that for all α [1,2] ≤ ≤ ∈ 1 Iνα ≥Iνα∞ ≥ KIνα. It is plain that the method in [8] allows to deal with more general measures,at the price of rather heavy technicalities. In this paper, we wish to point out a softer approach to isoperimetric in- equalities. It was recently developed by Wang and his coauthors [42, 25, 43] andreliesonsocalledsuper-Poincar´einequalities. Itcanbe combinedwithour techniquesinordertoprovidedimensionfreeisoperimetricinequalitiesforlarge classes of measures. Among them are the measures on the line with density e−Φ(|t|)dt/Z where Φ(0)=0, Φ is convex and √Φ is concave. This is achieved in the first part of the paper: Sections 2–5. The dimension free inequalities are stillvalid forslightmodifications ofthe aboveexamples. Other approachesand a few examples of perturbation results are developed in the last sections of the article. 3 Finally, let us present the super-Poincar´einequality as introduced by Wang inordertostudytheessentialspectrumofMarkovgenerators(actuallywehave foundit convenientto exchangethe rolesofs andβ(s) in the definition below). We shall say that a probability measure µ on (M,g) satisfies a super-Poincar´e inequality,if thereexists a nonnegativefunction β definedon[1,+ [suchthat for all smooth f :M R and all s 1, ∞ → ≥ 2 f2dµ s f dµ β(s) f 2dµ. − | | ≤ |∇ | Z (cid:18)Z (cid:19) Z This family of inequalities is equivalent to the following Nash type inequality: for all smooth f, 2 f 2dµ f2dµ f dµ Θ |∇ | , Z ≤(cid:18)Z | | (cid:19) R f dµ 2! | | where Θ(x) := inf β(s)x+s . But it is of(cid:0)teRn easie(cid:1)r to work with the first s≥1 { } form. Similar inequalities appear in the literature, see [10, 22]. Wang dis- covered that super-Poincar´e inequalities imply precise isoperimetric estimates, andarerelatedto Beckner-typeinequalitiesvia F-Sobolevinequalities. Infact, Beckner-typeinequalities,asdevelopedbyLata la-Oleszkiewicz[29]werecrucial inderivingdimension-freeconcentrationinourpaper[8]. Infullgeneralitythey read as follows: for all smooth f and all p [1,2), ∈ 2 p f2dµ f pdµ T(2 p) f 2dµ, − | | ≤ − |∇ | Z (cid:18)Z (cid:19) Z whereT :(0,1] R+ isanon-decreasingfunction. Following[9]wecouldchar- → acterize the measures on the line which enjoy this property, and then take ad- vantageofthetensorizationproperty. Asthereadernoticed,thesuper-Poincar´e and Beckner-type inequalities are formally very similar. It turns out that the tools of [9] apply to both, see for example Lemma 3 below. This remark al- lows us to present a rather concise proof of the dimension-free isoperimetric inequalities,sincethe twofunctionalinequalities involved(Becknertype forthe tensorization property, and super-Poincar´e for its isoperimetric implications) can be studied in one go. 2 A measure-Capacity sufficient condition for super-Poincar´e inequality This section provides a sufficient condition for the super Poincar´e inequality to hold, in terms of a comparison between capacity of sets and their measure. This point of view was put forward in [8] in order to give a natural unified presentation of the many functional inequalities appearing in the field. 4 Given A Ω, the capacity Cap (A,Ω), is defined as ⊂ µ Cap (A,Ω) = inf f 2dµ; f 1, f =0 µ |∇ | |A ≥ |Ωc (cid:26)Z (cid:27) = inf f 2dµ; 1 f 1 , A Ω |∇ | ≤ ≤ (cid:26)Z (cid:27) wheretheinfimumisoverlocallyLipschitzfunctions. RecallthatRademacher’s theorem (see e.g. [23, 3.1.6]) ensures that such functions are Lebesgue almost everywheredifferentiable,henceµ-almostsurelydifferentiable. Thelatterequal- ityfollowsfromaneasytruncationargument,reducingtofunctions withvalues in [0,1]. Finally we defined in [9] the capacity of A with respect to µ when µ(A)<1/2 as Cap (A):=inf Cap(A,Ω); A Ω, µ(Ω) 1/2 . µ { ⊂ ≤ } Theorem 1. Assume that for every measurable A M with µ(A) < 1/2, one ⊂ has 1 µ(A) Cap (A) sup . µ ≥ β(s) 1+(s 1)µ(A) s≥1 (cid:18) − (cid:19) for some function β defined on [1,+ [ . Then, for every smooth f :M ∞R and every s 1 one has → ≥ 2 f2dµ s f dµ 4β(s) f 2dµ. − | | ≤ |∇ | Z (cid:18)Z (cid:19) Z Proof. We use four results that we recall or prove just after this proof. Let s 1, f :M R be locally Lipschitz and m a median of the law of f under µ. ≥ → Define F =(f m) and F =(f m) . Setting + + − − − − 1 = g :M [0,1); (1 g)−1dµ 1+ , s G → − ≤ s 1 (cid:26) Z − (cid:27) it follows from Lemmas 2 and 3 (used with A=s 1 and a=1/2) that − 2 2 f2dµ s f dµ (f m)2dµ (s 1) f m dµ − | | ≤ − − − | − | Z (cid:18)Z (cid:19) Z (cid:18)Z (cid:19) sup (f m)2gdµ;g s ≤ − ∈G (cid:26)Z (cid:27) sup F2gdµ;g ≤ + ∈Gs (cid:26)Z (cid:27) +sup F2gdµ;g , − ∈Gs (cid:26)Z (cid:27) wherewehaveusedthefactthatthesupremumofasumislessthanthesumof the suprema. We deal with the first term of the right hand side. By Theorem 5 we have sup F2gdµ;g 4B F 2dµ + ∈Gs ≤ s |∇ +| (cid:26)Z (cid:27) Z 5 where B is the smallest constant so that for all A M with µ(A)<1/2 s ⊂ B Cap (A) sup 1I gdµ;g . s µ ≥ A ∈Gs (cid:26)Z (cid:27) On the other hand Lemma 4 insures that 1 −1 sup 1I gdµ;g = µ(A) 1 1+ A s ∈G − (s 1)µ(A) (cid:26)Z (cid:27) (cid:18) (cid:16) − (cid:17) (cid:19) µ(A) = . 1+(s 1)µ(A) − Thus, by our assumption, B β(s). We proceed in the same way for F . s − ≤ Summing up, we arrive at 2 f2dµ s f dµ 4β(s)( F 2dµ+ F 2dµ) + − − | | ≤ |∇ | |∇ | Z (cid:18)Z (cid:19) Z Z 4β(s) f 2dµ. ≤ |∇ | Z In the last bound we used the fact that since f is locally Lipschitz and µ is absolutely continuous, the set f = m f = 0 is µ-negligible. Indeed { } ∩{∇ 6 } f = m f = 0 x; f m is not differentiable at x has Lebesgue { }∩{∇ 6 } ⊂ { | − | } measure zero since x f(x) m is locally Lipschitz. 7→| − | Lemma 2. Let (X,P)bea probability space. Then for any function g L2(P), ∈ for any s 1, ≥ 2 2 g2dP s g dP (g m)2dP (s 1) g mdP − | | ≤ − − − | − | Z (cid:18)Z (cid:19) Z (cid:18)Z (cid:19) where m is a median of the law of g under P. Proof. We write 2 2 g2dP s g dP =Var (g ) (s 1) g dP . P − | | | | − − | | Z (cid:18)Z (cid:19) (cid:18)Z (cid:19) By the variational definition of the median and the variance respectively, we have Var (g ) Var (g) (g m)2dP and g mdP g dP. The P P | | ≤ ≤ − | − | ≤ | | result follows. R R R Lemma 3 ([9]). Let ϕ be a non-negative integrable function on a probability space (X,P). Let A 0 and a (0,1), then ≥ ∈ 1 a ϕdP A ϕadP − Z (cid:18)Z (cid:19) a a = sup ϕgdP;g :X ( ,1) and (1 g)a−1dP Aa−1 → −∞ − ≤ (cid:26)Z Z (cid:27) a a sup ϕgdP;g :X [0,1) and (1 g)a−1dP 1+Aa−1 . ≤ → − ≤ (cid:26)Z Z (cid:27) 6 Note that in [9] it is assumed that A>0. The case A=0 is easy. Lemma 4 ([9]). Let a (0,1). Let Q be a finite positive measure on a space ∈ X and let K >Q(X). Let A X be measurable with Q(A)>0. Then ⊂ a sup 1IAgdQ;g :X [0,1) and (1 g)a−1dQ K → − ≤ (cid:26)ZX ZX (cid:27) a−1 K Q(X) a = Q(A) 1 1+ − . −(cid:18) Q(A) (cid:19) ! Theorem 5. Let be a family of non-negative Borel functions on M, Ω M G ⊂ with µ(Ω) 1/2 and for any measurable function f vanishing on Ωc set ≤ Φ(f)=sup fgdµ. g∈GZΩ Let B denote the smallest constant such that for all A Ω with µ(A) < 1/2 ⊂ one has BCap (A) Φ(1I ). µ ≥ A Then for every smooth function f :M R vanishing on Ωc it holds → Φ(f2) 4B f 2dµ. ≤ |∇ | Z Proof. We start with a result of Maz’ja [33], also discussed in [8, Proposition 13]: given two absolutely continuous positive measures µ, ν on M, denote by B the smallest constant such that for all A Ω one has ν ⊂ B Cap (A,Ω) ν(A). ν µ ≥ Then for every smooth function f :M R vanishing on Ωc → f2dν 4B f 2dµ. ν ≤ |∇ | Z Z Followinganidea ofBobkovandG¨otze [13]we applythe previousinequalityto the measures dν =gdµ for g . Thus for f as above ∈G Φ(f)=sup fgdµ 4supB f 2dµ. gdµ ≤ |∇ | g∈GZΩ g∈G Z It remains to check that the constant B is at most sup B . This follows g∈G gdµ from the definition of Φ and the inequality Cap (A) Cap (A,Ω). µ ≤ µ Corollary 6. Assume that β : [1,+ ) R+ is non-increasing and that s ∞ → 7→ sβ(s) is non-decreasing on [2,+ ). Then, for every a (0,1/2), ∞ ∈ 1 a a 1 a sup 2 . (2) 2β(1/a) ≤ 1+(s 1)aβ(s) ≤ β(1/a) s≥1 − 7 In particular, if for every measurable A M with µ(A)<1/2, one has ⊂ µ(A) Cap (A) , µ ≥ β(1/µ(A)) then, for every f :M R and every s 1 one has → ≥ 2 f2dµ s f dµ 8β(s) f 2dµ. − | | ≤ |∇ | Z (cid:18)Z (cid:19) Z Proof. The choice s=1/a gives the first inequality in (2). For the second part of (2), we consider two cases: If a(s 1) 1/2 then s 1+ 1 1, where we have used a<1/2. Hence, − ≤ ≤ 2a ≤ a the monotonicity of β yields a 1 a a 1+(s 1)aβ(s) ≤ β(s) ≤ β(1/a)· − If a(s 1) > 1/2, note that a/(1+(s 1)a) 1/s. Thus by monotonicity − − ≤ of s sβ(s) and since s 1+1/2a= 1+2a 2, 7→ ≥ 2a ≥ a 1 1 2a 2a 1+(s 1)aβ(s) ≤ sβ(s) ≤ (1+2a)β(1+ 1 ) ≤ β(1/a)· − 2a The last step uses the inequality 1+ 1 1 and the monotonicity of β. 2a ≤ a The second part of the Corollary is a direct consequence of Theorem 1 and (2) (replacing β in Theorem 1 by 2β). 3 Beckner type versus super Poincar´e inequality In this section we use Corollary 6 to derive super Poincar´e inequality from Beckner type inequality. The following criterion was established in [8, Theorem 18 and Lemma 19] in the particular case of M = Rn. As mentioned in the introduction of [8] the extension to Riemannian manifolds is straightforward. Theorem 7 ([8]). Let T : [0,1] R+ be non-decreasing and such that x → 7→ T(x)/x is non-increasing. Let C be the optimal constant such that for every smooth f :M R one has (Beckner type inequality) → 2 f2dµ f pdµ p sup − | | C f 2dµ. T(2 p) ≤ |∇ | p∈(1,2)R (cid:0)−R (cid:1) Z Then 1B(T) C 20B(T), where B(T) is the smallest constant so that every 6 ≤ ≤ A M with µ(A)<1/2 satisfies ⊂ µ(A) B(T)Cap (A) . µ ≥ T 1/log 1+ 1 µ(A) (cid:16) (cid:0) (cid:1)(cid:17) 8 If M =R, m is a median of µ and ρ is its density, we have more explicitly µ 1 max(B (T),B (T)) C 20max(B (T),B (T)) − + − + 6 ≤ ≤ where 1 x 1 B (T) = sup µ([x,+ )) + x>m ∞ T 1/log 1+ µ([x,1+∞)) Zm ρµ (cid:16) (cid:0) 1 (cid:1)(cid:17) m 1 B (T) = sup µ(( ,x]) . − x<m −∞ T 1/log 1+ µ((−1∞,x]) Zx ρµ The relations between Beckner-typ(cid:16)e and(cid:0)super-Poincar(cid:1)´e(cid:17)inequalities have been explained by Wang, via F-Sobolev inequalities. Here we give an explicit connection under a natural condition on the rate function T. Corollary 8 (From Beckner to Super Poincar´e). Let T : [0,1] R+ be non- → decreasing and such that x T(x)/x is non-increasing. Assume that there exists a constant C such that7→for every smooth f :M R one has → 2 f2dµ f pdµ p sup − | | C f 2dµ. (3) T(2 p) ≤ |∇ | p∈(1,2)R (cid:0)−R (cid:1) Z Define β(s)=T (1/log(1+s)) for s e 1 and β(s)=T(1) for s [1,e 1]. Then, every smooth f :M R sa≥tisfi−es for every s 1, ∈ − → ≥ 2 f2dµ s f dµ 48Cβ(s) f 2dµ. − | | ≤ |∇ | Z (cid:18)Z (cid:19) Z Proof. ByTheorem7,Inequality(3)impliesthateveryA M withµ(A)<1/2 ⊂ satisfies µ(A) µ(A) 6CCap (A) = µ ≥ T 1/log 1+ 1 β 1 · µ(A) µ(A) (cid:16) (cid:16) (cid:17)(cid:17) (cid:16) (cid:17) SinceT isnon-decreasing,β isnon-increasingon[1, ). Ontheotherhand,for ∞ s e 1, we have ≥ − s sβ(s)=sT (1/log(1+s))=log(1+s)T (1/log(1+s)) log(1+s)· The map x T(x)/x is non-increasing and s s is non-decreasing. 7→ 7→ log(1+s) It follows that s sβ(s) is non-decreasing. Corollary 6 therefore applies and 7→ yields the claimed inequality. A remarkable feature of Beckner type inequalities (3) is the tensorization property: if µ and µ both satisfy (3) with constant C, then so does µ µ 1 2 1 2 ⊗ [29]. For this reason inequalities for measures on the real line are inherited by their infinite products. In dimension 1 the criterion given in Theorem 7 allows ustodealwithprobabilitymeasuresdµ (x)=Z−1e−Φ(|x|)dxwithquitegeneral Φ Φ potentials Φ: 9 Proposition9. LetΦ:R+ R+ beanincreasingconvexfunctionwithΦ(0)= 0 and consider the probabilit→y measure dµ (x) = Z−1e−Φ(|x|)dx. Assume that Φ Φ Φ is 2 on [Φ−1(1),+ ) and that √Φ is concave. Define T(x) = [1/Φ′ C ∞ ◦ Φ−1(1/x)]2 for x > 0 and β(s) = [1/Φ′ Φ−1(log(1+s))]2 for s e 1 and ◦ ≥ − β(s) = [1/Φ′ Φ−1(1)]2 for s [1,e 1]. Then there exists a constant C > 0 such that for ◦any n 1, every∈smooth−function f :Rn R satisfies ≥ → 2 f2dµn f pdµn p sup Φ− | | Φ C f 2dµn. T(2 p) ≤ |∇ | Φ p∈(1,2)R (cid:0)−R (cid:1) Z In turn, for any n 1, every smooth function f :Rn R and every s 1, ≥ → ≥ 2 f2dµn s f dµn 48Cβ(s) f 2dµn. φ− | | Φ ≤ |∇ | Φ Z (cid:18)Z (cid:19) Z Proof. The proof of the Beckner type inequality comes from [8, proof of Corol- lary 32]: the hypotheses on Φ allow to compute an equivalent of µ ([x,+ )) Φ ∞ when x tends to infinity (namely e−φ/φ′) and thus to bound from above the quantities B (T) and B (T) of Theorem 7. This yields the Beckner type in- + − equality in dimension 1. Next we use the tensorization property. The second part follows from Corollary 8 (the hypotheses on Φ ensure that T is non-decreasing and T(x)/x is non-increasing). Example 1. A first family of examples is given by the measures dµ (x) = p e−|x|pdx/(2Γ(1+1/p)),p [1,2]. The potentialx xp fulfills the hypotheses ∈ 7→| | ofProposition9withTp(x)= p12x2(1−p1). Thus,byProposition9,foranyn≥1, µnp satisfiesasuperPoincar´einequalitywithfunctionβ(s)=cp/log(1+s)2(1−p1) where c depends only on p and not on the dimension n. p Note that the corresponding Beckner type inequality 2 f2dµn f qdµn q sup p − | | p c˜ f 2dµn, q∈(1,2)R (2−q(cid:0))R2(1−p1) (cid:1) ≤ pZ |∇ | p goes back to Lata la and Oleszkiewicz [29] with a different proof, see also [9]. Example 2. Consider now the larger family of examples given by dµ (x) = p,α Z−1e−|x|p(log(γ+|x|))αdx, p [1,2], α 0 and γ = eα/(2−p). One can see that p,α ∈ ≥ µn satisfies a super Poincar´einequality with function p,α c p,α β(s)= , s 1. (log(1+s))2(1−p1)(loglog(e+s))2α/p ≥ 4 Isoperimetric inequalities In this section we collect results which relate super-Poincar´e inequalities with isoperimetry. They follow Ledoux approach of Buser’s inequality [30]. This method was developed by Bakry-Ledoux [4] and Wang [36, 42], see also [24, 8]. 10

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