INTEGRABILITY OF THE FOURIER TRANSFORM: FUNCTIONS OF BOUNDED VARIATION E. LIFLYAND Abstract. CertainrelationsbetweentheFouriertransformofafunctionofboundedvariationand 2 the Hilbert transform of its derivative are revealed. The widest subspaces of the space of functions 1 of bounded variation are indicated in which the cosine and sine Fourier transforms are integrable. 0 2 n a J 1. Introduction 6 We aregoingto comparethe Fouriertransformof afunction ofbounded variationandthe Hilbert 2 transformof a related function. For this, let us start with some known results. The first one is given ] in [7, Thm.2] (see also [2]). We define the following T-transform of a function g : R = [0,∞) → C: A C . t/2 g(t+s)−g(t−s) h Tg(t) = ds, t Z s a 0 m where the integral is understood in the improper (principal value) sense, that is, as lim . [ δ→0+ δ R 1 Theorem 1. Let f : R → C be locally absolutely continuous, of bounded variation and lim f(t) = v + t→∞ 8 0. Let also Tf′ ∈ L1(R ). Then the cosine Fourier transform of f + 5 5 5 ∞ . (1) f (x) = f(t)cosxtdt 1 c Z 0 0 b 2 is Lebesgue integrable on R , with + 1 : v i (2) kf k . kf′k +kTf′k , X c L1(R+) L1(R+) L1(R+) r and for the sine Fourier transbform, we have, with x > 0, a ∞ 1 π (3) f (x) = f(t)sinxtdt = f +F(x), s Z x (cid:16)2x(cid:17) 0 b where (4) kFk . kf′k +kTf′k . L1(R+) L1(R+) L1(R+) Here and in what follows we use the notation “.” and “&” as abbreviations for “≤ C” and “≥ C”, with C being an absolute positive constant. Let us now turn to the Hilbert transform of an integrable function g 1991 Mathematics Subject Classification. Primary 42A38; Secondary 42A50. Key words and phrases. Fourier transform, integrability, Hilbert transform, Hardy space. 1 2 E. LIFLYAND 1 g(t) (5) Hg(x) = dt, π Z t−x R where the integral is also understood in the improper (principal value) sense, now as lim . |t−x|>δ δ→0+ R It is not necessarily integrable, and when it is, we say that g is in the (real) Hardy space H1(R). If g ∈ H1(R), then (6) g(t)dt = 0. Z R It was apparently first mentioned in [6]. An odd function always satisfies (6). However, not every odd integrable function belongs to H1(R), for a counterexample see, e.g., [8]. When in the definition of the Hilbert transform (5) the function g is odd, we will denote this transform by H , and it is equal to 0 2 ∞ tg(t) (7) H g(x) = dt. 0 π Z t2 −x2 0 If it is integrable, we will denote the corresponding Hardy space by H1(R). 0 Since H g(x) = Tg(x)+Γ(x), 0 where Γ is such that ∞ ∞ |Γ(x)|dx . |g(t)|dt, Z Z 0 0 the right-hand sides of (2) and (4) can be treated as kf′k . This has been observed in [7] and H01(R+) later on in [2]. The space of integrable functions g with integrable Tg, or just H1(R ), is one of the widest 0 + spaces the belonging of the derivative f′ to which ensures the integrability of the cosine Fourier transform of f. However, the possibility of existence (or non-existence) of a wider space of such type is of considerable interest. Let us show that such a space does exist, moreover, it is the widest possible, at least provides a necessary and sufficient condition for the integrability of the cosine Fourier transform. In fact, it has in essence been introduced (for different purposes) in [4] as |g(x)| (8) Q = {g : g ∈ L1(R), dx < ∞}. Z |x| R b With the obvious norm |g(x)| kgk + dx L1(R) Z |x| R b it is a Banach space and ideal in L1(R). What we will actually use is the space Q of the odd 0 functions from Q INTEGRABILITY OF THE FOURIER TRANSFORM: FUNCTIONS OF BOUNDED VARIATION 3 ∞ |g (x)| (9) Q = {g : g ∈ L1(R),g(−t) = −g(t), s dx < ∞}; 0 Z x 0 b such functions naturally satisfy (6). Theorem 2. Let f : R → C be locally absolutely continuous, of bounded variation and lim f(t) = + t→∞ 0. Then the cosine Fourier transform of f given by (1) is Lebesgue integrable on R if and only if + f′ ∈ Q . 0 The situationismoredelicate withthesine Fouriertransform, where asort ofasymptotic relation can be obtained. In what follows we shall denote g (x) (10) T (x) = s . g x b Theorem 3. Let f : R → C be locally absolutely continuous, of bounded variation and lim f(t) = + t→∞ 0. Then for the sine Fourier transform of f given in (3) there holds for any x > 0 ∞ 1 π (11) fs(x) = Z f(t)sinxtdt = xf (cid:16)2x(cid:17)+H0Tf′(x)+G(x), 0 b where (12) kGk . kf′k . L1(R+) L1(R+) This theorem makes it natural to consider a Hardy type space H1(R ) which consists of Q Q + 0 functions g with integrable H T . 0 g Corollary 4. Let a function f satisfy the assumptions of Theorem 3 and such that f′ ∈ H1(R ). Q + Then 1 π (13) f (x) = f +G(x), s x (cid:16)2x(cid:17) b where (14) kGk . kf′k . L1(R+) HQ1(R+) Technically, this is an obvious corollary of Theorem 3. We shall discuss it in Section 3. 2. Proofs Proof of Theorem 2. The assumptions of the theorem give a possibility to integrate by parts. This yields 1 ∞ 1 f (x) = − f′(t)sinxtdt = − f′(x). c x Z x s 0 Integrating both sides overbR completes the proof. b (cid:3) + 4 E. LIFLYAND Proof of Theorem 3. Let us start with integration by parts in π π 2x 1−cosxt π 1 2x f(t)sinxtdt = f(t) |2x + f′(t)[cosxt−1]dt Z x 0 x Z 0 0 π 1 π 1 2x = f + f′(t)[cosxt−1]dt. x (cid:16)2x(cid:17) x Z 0 π The last value is bounded by 2x t|f′(t)|dt, and 0 R ∞ 2πx π ∞ (15) t|f′(t)|dtdx = |f′(t)|dt. Z Z 2 Z 0 0 0 Let us now consider ∞ (16) I = I(x) = f(t)sinxtdt. Z π 2x We will start with the following statement. Lemma 1. There holds 2 ∞ ∞ cosv 2 ∞ xt sinv H0Tf′(x) = xπ Z f′(t)sinxt Z v dvdt+ xπ Z f′(t)cosxt Z v dvdt. 0 xt 0 0 Proof of Lemma 1. We have 2 ∞ 1 (17) H0Tf′(x) = π Z fs′(u) u2 −x2 du 0 2 ∞ b ∞ 1 (18) = f′(t) sinutdudt. π Z Z u2 −x2 0 0 Denoting, as usual, ∞ cost Ci(u) = − dt Z t u and u sint π ∞ sint Si(u) = dt = − dt, Z t 2 Z t 0 u we will make use of the formula (see [1, Ch.II, (18)]) ∞ 1 1 sinyxdx = [sinayCi(ay)−cosaySi(ay)], Z a2 −x2 a 0 where the integrals is understood in the principal value sense and a,y > 0. We apply this formula to the inner integral on the right-hand side of (17), with a = x and y = t. Using the expressions for Ci and Si, we complete the proof of the lemma. (cid:3) With this in hand, we are going to prove that INTEGRABILITY OF THE FOURIER TRANSFORM: FUNCTIONS OF BOUNDED VARIATION 5 (19) I(x) = H0Tf′(x)+G(x), where (20) kGk . kf′k . L1(R+) L1(R+) We denote the two summands in the expression obtained in the lemma by I and I . For both, we 1 2 make use of the fact that ∞ cosv 1 dv = O( ). Z v xt xt The same true when cosv is replaced by sinv. When t ≥ 1 we have x ∞ 1 ∞ 1 ∞ ∞ 1 ∞ (21) |f′(t)| dtdx = |f′(t)|t dx = |f′(t)|dt. Z x Z xt Z Z x2 Z 0 1 0 1 0 x t When t ≤ 1 we split the inner integral into two. First, x ∞ cosv dv = O(1), Z v 1 and using sinxt ≤ t, we arrive at the estimate similar to (15). Further, we have (cid:12) x (cid:12) (cid:12) (cid:12) (cid:12) (cid:12) (cid:12) (cid:12) 1 cosv 1 dv = O(ln ). Z (cid:12) v (cid:12) xt xt(cid:12) (cid:12) (cid:12) (cid:12) By this, integrating in x over (0,∞), w(cid:12)e hav(cid:12)e to estimate ∞ 1/t 1 ∞ |f′(t)|t ln dxdt = |f′(t)|dt. Z Z xt Z 0 0 0 Here we use that 1/t 1 1 ln dx = . Z xt t 0 In conclusion, I can be treated as G. 1 Let us proceed to I . Using that 2 1 xt sinv dv = O(t), x(cid:12)Z v (cid:12) (cid:12) 0 (cid:12) (cid:12) (cid:12) we arrive for t ≤ π at (15). Let now(cid:12)t ≤ π . We h(cid:12)ave 2x 2x xt sinv π ∞ sinv dv = − dv. Z v 2 Z v 0 xt Now 6 E. LIFLYAND 2 ∞ π f′(t)cosxtdt = I. xπ Z 2 0 For the integral ∞ sinv dv, the estimates are exactly like those in (21). xt v Combining (19R) and estimates before Lemma 1, we complete the proof of the theorem. (cid:3) 3. Discussion Discussion and comments are in order. At first sight, Theorem 2 does not seem to be a result at all, at most a technical reformulation of (1). This could be so but not after the appearance of the analysis of Q in [4]. Indeed, the well-known extension of Hardy’s inequality (see, e.g., [3, (7.24)]) |g(x)| (22) dx . kgk Z |x| H1(R) R b implies (23) H1(R) ⊆ Q ⊆ L1(R), 0 where the latter is the subspace of g in L1(R) which satisfy the cancelation property (6). It is worth noting that (23) immediately proves (2) from Theorem 1. The initial proof in [7] is essentially more complicated. It is doubtful that Q (or Q ) may be defined in terms of f itself rather than its Fourier transform, 0 therefore it is of interest to find certain proper subspaces of Q wider than H1 belonging to which 0 is easily verifiable. We mention the paper [9] in which a family of subspaces between H1 and L1 is introduced and duality properties of that family are studied. However, it is not clear how to compare that family with Q . 0 Back to Theorem 3, let us analyze (19). On the one hand, we have ∞ ∞ Z |I(x)|dx = Z |H0Tf′(x)|dx+O(kf′kH01(R+)). 0 0 On the other hand, it is proved in [7] that ∞ |I(x)|dx = O(kf′k ). Z H01(R+) 0 This leads to Proposition 1. If g is an integrable odd function, then kH T k . kgk . 0 g L1(R+) H01(R+) The above proof of Proposition 1 looks ”artificial”. A direct proof, preferable simple enough will be very desirable. In any case, this implies an updated chain of embeddings (24) H1(R ) ⊆ H1(R ) ⊆ Q ⊆ L1(R ). 0 + Q + 0 0 + INTEGRABILITY OF THE FOURIER TRANSFORM: FUNCTIONS OF BOUNDED VARIATION 7 It is very interesting to figure out which of these embeddings are proper. Correspondingly, inter- mediate spaces are of interest, both theoretical and practical. References [1] G. Bateman, A. Erd´elyi, Tables of Integral Transforms, I, McGraw Hill Book Company, New York, 1954. [2] S. Fridli, Hardy Spaces Generated by an Integrability Condition, J. Approx. Theory, 113 (2001), 91–109. [3] J. Garcia-Cuerva and J.L. Rubio de Francia, Weighted Norm Inequalities and Related Topics, North-Holland, 1985. [4] R.L. Johnson and C.R. Warner, The convolution algebra H1(R), J. Function Spaces Appl. 8 (2010), 167–179. [5] F.W. King, Hilbert transforms, Vol.1, Enc. Math/ Appl., Cambridge Univ. Press, Cambridge, 2009. [6] H. Kober, A note on Hilberts operator, Bull. Amer. Math. Soc., 48:1 (1942), 421–426. [7] E. Liflyand, Fourier transforms of functions from certain classes, Anal. Math. 19 (1993), 151–168. [8] E. Liflyand and S. Tikhonov, Weighted Paley-Wiener theorem on the Hilbert transform, C.R. Acad. Sci. Paris, Ser.I 348 (2010), 1253–1258. [9] C. Sweezy, Subspaces of L1(Rd), Proc. Amer. Math. Soc., 132 (2004), 3599–3606. Department of Mathematics, Bar-Ilan University, 52900 Ramat-Gan, Israel E-mail address: [email protected]