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Engineering Fluid Mechanics Solution Manual Prof. T.T. Al-Shemmeri Download free books at Prof. T.T. Al-Shemmeri Engineering Fluid Mechanics Solution Manual Download free eBooks at bookboon.com 2 Engineering Fluid Mechanics Solution Manual © 2012 Prof. T.T. Al-Shemmeri & bookboon.com ISBN 978-87-403-0263-9 Download free eBooks at bookboon.com 3 Engineering Fluid Mechanics Solution Manual Contents Contents Book Description: 5 Author Details: 5 1 Chapter One Tutorial Problems 6 2 Chapter Two Tutorial Problems 13 3 Chapter Three Tutorial Problems 21 4 Chapter Four Tutorial Problems 28 5 Chapter Five Tutorial Problems 31 Sample Examination Paper 33 Class Test – Fluid Mechanics 34 Formulae Sheet 44 Download free eBooks at bookboon.com 4 Click on the ad to read more Engineering Fluid Mechanics Solution Manual Book Description Book Description: Title – Engineering Fluid Mechanics Solution Manual Author – Prof. T.T. Al-Shemmeri Fluid Mechanics is an essential subject in the study of the behaviour of fluids at rest and when in motion. The book is complimentary follow up for the book “Engineering Fluid Mechanics” also published on BOOKBOON, presenting the solutions to tutorial problems, to help students the option to see if they got the correct answers, and if not, where they went wrong, and change it to get the correct answers. Author Details: Prof Tarik Al-Shemmeri – BSc, MSc, PhD, CEng Professor of Renewable Energy Technology at Staffordshire University. Current research interests in Renewable Energy and Environmental Technology. Lecturing topics include: Energy management and Power generation. Download free eBooks at bookboon.com 5 Engineering Fluid Mechanics Solution Manual Chapter One Tutorial Problems 1 Chapter One Tutorial Problems 1.1 Show that the kinematic viscosity has the primary dimensions of L2T-1. Solution: The kinematic viscosity is defined as the ratio of the dynamic viscosity by the density of the fluid. The density has units of mass (kg) divided by volume (m3); whereas the dynamic viscosity has the units of mass (kg) per meter (m) per time (s). Hence: (cid:80) (cid:48)(cid:47)(cid:16)(cid:20)(cid:55)(cid:16)(cid:20) (cid:88)(cid:32) (cid:32) (cid:32)(cid:47)(cid:21)(cid:55)(cid:16)(cid:20) (cid:85) (cid:48)(cid:47)(cid:16)(cid:22) 1.2 In a fluid the velocity measured at a distance of 75mm from the boundary is 1.125m/s. The fluid has absolute viscosity 0.048 Pa s and relative density 0.913. What is the velocity gradient and shear stress at the boundary assuming a linear velocity distribution? Determine its kinematic viscosity. [Ans: 15 s-1, 0.72Pa.s; 5.257x10-5 m2/s] Solution: Download free eBooks at bookboon.com 6 Engineering Fluid Mechanics Solution Manual Chapter One Tutorial Problems (cid:71)(cid:57) (cid:20)(cid:17)(cid:20)(cid:21)(cid:24) (cid:42)(cid:85)(cid:68)(cid:71)(cid:76)(cid:72)(cid:81)(cid:87) (cid:32) (cid:32) (cid:32)(cid:20)(cid:24)(cid:86)(cid:16)(cid:20) (cid:71)(cid:92) (cid:19)(cid:17)(cid:19)(cid:26)(cid:24) (cid:71)(cid:57) (cid:87)(cid:32)(cid:80) (cid:32)(cid:19)(cid:17)(cid:19)(cid:23)(cid:27)(cid:91)(cid:20)(cid:24)(cid:32)(cid:19)(cid:17)(cid:26)(cid:21)(cid:19)(cid:51)(cid:68)(cid:17)(cid:86) (cid:71)(cid:92) (cid:80) (cid:19)(cid:17)(cid:19)(cid:23)(cid:27) (cid:88)(cid:32) (cid:32) (cid:32)(cid:24)(cid:17)(cid:21)(cid:24)(cid:26)(cid:91)(cid:20)(cid:19)(cid:16)(cid:24)(cid:80)(cid:21) (cid:18)(cid:86) (cid:85) (cid:28)(cid:20)(cid:22) 1.3 A dead-weight tester is used to calibrate a pressure transducer by the use of known weights placed on a piston hence pressurizing the hydraulic oil contained. If the diameter of the piston is 10 mm, determine the required weight to create a pressure of 2 bars. [Ans: 1.6 kg] Solution: (a) P = F/A (cid:83) (cid:83) (cid:36)(cid:32) (cid:39)(cid:21) (cid:32) (cid:91)(cid:19)(cid:17)(cid:19)(cid:20)(cid:19)(cid:21) (cid:32)(cid:26)(cid:17)(cid:27)(cid:24)(cid:23)(cid:91)(cid:20)(cid:19)(cid:16)(cid:24) (cid:80)(cid:21) (cid:23) (cid:23) Hence the weight = P x A / g = 2 x 105 x7.854x10-5 / 9.81 = 1.60 kg Download free eBooks at bookboon.com 7 Engineering Fluid Mechanics Solution Manual Chapter One Tutorial Problems 1.4 How deep can a diver descend in ocean water without damaging his watch, which will withstand an absolute pressure of 5.5 bar? Take the density of ocean water, r = 1025 kg/m3. [Ans: 44.75 m] Solution: Use the static equation: (cid:83)(cid:3)(cid:32)(cid:3)(cid:85)(cid:3)(cid:74)(cid:3)(cid:75)(cid:3) Hence the depth can be calculated as: (cid:51) (cid:11)(cid:24)(cid:17)(cid:24)(cid:16)(cid:20)(cid:12)(cid:91)(cid:20)(cid:19)(cid:24) (cid:75)(cid:32) (cid:32) (cid:32)(cid:23)(cid:23)(cid:17)(cid:26)(cid:24)(cid:80)(cid:58)(cid:68)(cid:87)(cid:72)(cid:85) (cid:85)(cid:17)(cid:74) (cid:20)(cid:19)(cid:21)(cid:24)(cid:91)(cid:28)(cid:17)(cid:27)(cid:20) 1.5 The U-tube manometer shown below, prove that the difference in pressure is given by:  2  d  P −P =ρ.g.z 1+   1 2 2 D  Download free eBooks at bookboon.com 8 Engineering Fluid Mechanics Solution Manual Chapter One Tutorial Problems Solution: The relationship between liquid columns and the area of cross section is based on the conservation of matter, ie continuity equation, hence: volume 1 = volume 2 (cid:93) (cid:91)(cid:36) (cid:32) (cid:93) (cid:91)(cid:36) (cid:20) (cid:20) (cid:21) (cid:21) (cid:93) (cid:91)(cid:11)(cid:83)(cid:18)(cid:23)(cid:12)(cid:91)(cid:71)(cid:21) (cid:71) (cid:75)(cid:72)(cid:81)(cid:70)(cid:72) (cid:111) (cid:93) (cid:32) (cid:21) (cid:32) (cid:93) (cid:91)(cid:11) (cid:12)(cid:21) (cid:20) (cid:11)(cid:83)(cid:18)(cid:23)(cid:12)(cid:91)(cid:39)(cid:21) (cid:21) (cid:39) For the “U” tube manometer that the height different in the two columns gives the pressure difference, therefore: (cid:41) (cid:20)(cid:32) (cid:41) (cid:21) (cid:51) (cid:14)(cid:85)(cid:17)(cid:74)(cid:17)(cid:93) (cid:32) (cid:51) (cid:14)(cid:85)(cid:17)(cid:74)(cid:17)(cid:93) (cid:20) (cid:20) (cid:21) (cid:21) hence (cid:51) (cid:16)(cid:51) (cid:32)(cid:85)(cid:17)(cid:74)(cid:17)(cid:11)(cid:93) (cid:16)(cid:93) (cid:12) (cid:20) (cid:21) (cid:21) (cid:20) (cid:32)(cid:85)(cid:17)(cid:74)(cid:17)(cid:93) (cid:91)(cid:62)(cid:20)(cid:14)(cid:11)(cid:71) (cid:18)(cid:39)(cid:12)(cid:21)(cid:64) (cid:21) Clearly if D is very much larger than d then (d/D)2 is very small so (cid:51) (cid:16)(cid:51) (cid:32)(cid:85)(cid:17)(cid:74)(cid:17)(cid:93) (cid:20) (cid:21) (cid:21) 1.6 A flat circular plate, 1.25 m diameter is immersed in sewage water (density 1200 kg/m3) such that its greatest and least depths are 1.50 m and 0.60 m respectively. Determine the force exerted on one face by the water pressure, [Ans: 15180 N] (cid:68)(cid:3) (cid:20)(cid:17)(cid:24)(cid:80)(cid:3) (cid:19)(cid:17)(cid:25)(cid:80)(cid:3) Download free eBooks at bookboon.com 9 Engineering Fluid Mechanics Solution Manual Chapter One Tutorial Problems Solution: Area of laminar (cid:20) (cid:36)(cid:3)(cid:3)(cid:3)(cid:3) (cid:32)(cid:3) (cid:83)(cid:11)(cid:20)(cid:17)(cid:21)(cid:24)(cid:12)(cid:21)(cid:3)(cid:32)(cid:3)(cid:20)(cid:17)(cid:21)(cid:21)(cid:27)(cid:3)(cid:80)(cid:21)(cid:3) (cid:23) Depth to centroid (cid:20) (cid:75) (cid:3)(cid:3) (cid:32)(cid:3) (cid:11)(cid:19)(cid:17)(cid:25)(cid:19)(cid:3)(cid:14)(cid:3)(cid:20)(cid:17)(cid:24)(cid:19)(cid:12)(cid:3)(cid:32)(cid:3)(cid:20)(cid:17)(cid:19)(cid:24)(cid:3)(cid:80)(cid:3) 360° (cid:70) (cid:21) . Resultant Force thinking 360° F = r g A h = 9.81 x 1200 x 1.228 x 1.05 c = 15180 N . thinking 360° . thinking 360° . thinking Discover the truth at www.deloitte.ca/careers Discover the truth at www.deloitte.ca/careers © Deloitte & Touche LLP and affiliated entities. Discover the truth at www.deloitte.ca/careers © Deloitte & Touche LLP and affiliated entities. Download free eBooks at bookboon.com © Deloitte & Touche LLP and affiliated entities. Discover the tru10th at www.deloitte.caC/cliacrke eorns the ad to read more © Deloitte & Touche LLP and affiliated entities.