ebook img

Elementary Algebra Textbook Solutions Manual PDF

517 Pages·2012·2.75 MB·English
by  
Save to my drive
Quick download
Download
Most books are stored in the elastic cloud where traffic is expensive. For this reason, we have a limit on daily download.

Preview Elementary Algebra Textbook Solutions Manual

Elementary Algebra Textbook Solutions Manual Second Edition Department of Mathematics College of the Redwoods 2012-2013 ii Copyright All parts of this prealgebra textbook are copyrighted (cid:2)c 2011 in the nameoftheDepartmentofMathematics,CollegeoftheRedwoods. They are not in the public domain. However, they are being made available freeforuseineducationalinstitutions. Thisofferdoesnotextendtoany application that is made for profit. Users who have such applications in mind should contact David Arnold at [email protected] or Bruce Wagner at [email protected]. ThisworkislicensedundertheCreativeCommonsAttribution-Non- Commercial-NoDerivs 3.0 Unported License. To view a copy of this li- cense, visit http://creativecommons.org/licenses/by-nc-nd/3.0/ or send a letter to Creative Commons, 171 Second Street, Suite 300, San Fran- cisco, California, 94105, USA. Second Edition: 2012-2013 Contents 1 The Arithmetic of Numbers 1 1.1 An Introduction to the Integers . . . . . . . . . . . . . . . . . . 1 1.2 Order of Operations . . . . . . . . . . . . . . . . . . . . . . . . 7 1.3 The Rational Numbers . . . . . . . . . . . . . . . . . . . . . . . 18 1.4 Decimal Notation . . . . . . . . . . . . . . . . . . . . . . . . . . 33 1.5 Algebraic Expressions . . . . . . . . . . . . . . . . . . . . . . . 47 2 Solving Linear Equations 53 2.1 Solving Equations: One Step . . . . . . . . . . . . . . . . . . . 53 2.2 Solving Equations: Multiple Steps . . . . . . . . . . . . . . . . 60 2.3 Solving Equations: Clearing Frations and Decimals . . . . . . . 73 2.4 Formulae . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 81 2.5 Applications . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 91 2.6 Inequalities . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 108 3 Introduction to Graphing 127 3.1 Graphing Equations by Hand . . . . . . . . . . . . . . . . . . . 127 3.2 The Graphing Calculator . . . . . . . . . . . . . . . . . . . . . 140 3.3 Rates and Slope . . . . . . . . . . . . . . . . . . . . . . . . . . 149 3.4 Slope-Intercept Form of a Line . . . . . . . . . . . . . . . . . . 157 3.5 Point-Slope Form of a Line . . . . . . . . . . . . . . . . . . . . 168 3.6 Standard Form of a Line . . . . . . . . . . . . . . . . . . . . . . 183 4 Systems 205 4.1 Solving Systems by Graphing . . . . . . . . . . . . . . . . . . . 205 4.2 Solving Systems by Substitution . . . . . . . . . . . . . . . . . 226 4.3 Solving Systems by Elimination . . . . . . . . . . . . . . . . . . 243 4.4 Applications of Linear Systems . . . . . . . . . . . . . . . . . . 259 5 Polynomials 269 5.1 Functions . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 269 iii iv CONTENTS 5.2 Polynomials . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 280 5.3 Applications of Polynomials . . . . . . . . . . . . . . . . . . . . 290 5.4 Adding and Subtracting Polynomials . . . . . . . . . . . . . . . 298 5.5 Laws of Exponents . . . . . . . . . . . . . . . . . . . . . . . . . 303 5.6 Multiplying Polynomials . . . . . . . . . . . . . . . . . . . . . . 309 5.7 Special Products . . . . . . . . . . . . . . . . . . . . . . . . . . 317 6 Factoring 335 6.1 The Greatest Common Factor . . . . . . . . . . . . . . . . . . . 335 6.2 Solving Nonlinear Equations. . . . . . . . . . . . . . . . . . . . 347 6.3 Factoring Trinomials I . . . . . . . . . . . . . . . . . . . . . . . 362 6.4 Factoring Trinomials II. . . . . . . . . . . . . . . . . . . . . . . 378 6.5 Special Forms . . . . . . . . . . . . . . . . . . . . . . . . . . . . 397 7 Rational Functions 413 7.1 Negative Exponents . . . . . . . . . . . . . . . . . . . . . . . . 413 7.2 Scientific Notation . . . . . . . . . . . . . . . . . . . . . . . . . 425 7.3 Simplifying Rational Expressions . . . . . . . . . . . . . . . . . 433 7.4 Solving Rational Equations . . . . . . . . . . . . . . . . . . . . 441 7.5 Direct and Inverse Variation . . . . . . . . . . . . . . . . . . . . 456 8 Quadratic Functions 465 8.1 Introduction to Radical Notation . . . . . . . . . . . . . . . . . 465 8.2 Simplifying Radical Expressions. . . . . . . . . . . . . . . . . . 471 8.3 Completing the Square . . . . . . . . . . . . . . . . . . . . . . . 479 8.4 The Quadratic Formula . . . . . . . . . . . . . . . . . . . . . . 494 Second Edition: 2012-2013 1 Chapter The Arithmetic of Numbers 1.1 An Introduction to the Integers 1. The number 5 is 5 units from the origin. 5 units (cid:0) −10 0 5 10 Hence, |5|=5. 3. The number −2 is 2 units from the origin. 2 units (cid:0) −10 −2 0 10 Hence, |−2|=2. 5. The number 2 is 2 units from the origin. 2 units (cid:0) −10 0 2 10 Hence, |2|=2. 1 2 CHAPTER 1. THE ARITHMETIC OF NUMBERS 7. The number −4 is 4 units from the origin. 4 units (cid:0) −10 −4 0 10 Hence, |−4|=4. 9. We have like signs. The magnitudes (absolute values) of −91 and −147 are 91 and 147, respectively. If we add the magnitudes, we get 238. If we prefix the common negative sign, we get −238. That is: −91+(−147)=−238 11. We have like signs. The magnitudes (absolute values) of 96 and 145 are 96 and 145, respectively. If we add the magnitudes, we get 241. If we prefix the common positive sign, we get 241. That is: 96+145=241 13. To add a negative and a positive integer, subtract the smaller magnitude from the larger magnitude (76−46 = 30), then prefix the sign of the integer with the larger magnitude. Thus, −76+46=−30. 15. We havelike signs. The magnitudes (absolute values) of−59 and−12 are 59 and 12, respectively. If we add the magnitudes, we get 71. If we prefix the common negative sign, we get −71. That is: −59+(−12)=−71 17. To add a positive and a negative integer, subtract the smaller magnitude from the larger magnitude (86−37 = 49), then prefix the sign of the integer with the larger magnitude. Thus, 37+(−86)=−49. Second Edition: 2012-2013 1.1. AN INTRODUCTION TO THE INTEGERS 3 19. To add a positive and a negative integer, subtract the smaller magnitude from the larger magnitude (85−66 = 19), then prefix the sign of the integer with the larger magnitude. Thus, 66+(−85)=−19. 21. We have like signs. The magnitudes (absolute values) of 57 and 20 are 57 and 20, respectively. If we add the magnitudes, we get 77. If we prefix the common positive sign, we get 77. That is: 57+20=77 23. To add a negative and a positive integer, subtract the smaller magnitude from the larger magnitude (127−48=79), then prefix the sign of the integer with the larger magnitude. Thus, −48+127=79. 25. Subtraction means “add the opposite,” so change the difference into a sum. −20−(−10)=−20+10 Subtracting −10 is the same as adding 10. =−10 Subtract the magnitudes, and prefix with sign of larger number. 27. Subtraction means “add the opposite,” so change the difference into a sum. −62−7=−62+(−7) Subtracting 7 is the same as adding −7. =−69 Add the magnitudes, and prefix the common negative sign. 29. Subtraction means “add the opposite,” so change the difference into a sum. −77−26=−77+(−26) Subtracting 26 is the same as adding −26. =−103 Add the magnitudes, and prefix the common negative sign. Second Edition: 2012-2013 4 CHAPTER 1. THE ARITHMETIC OF NUMBERS 31. Subtraction means “add the opposite,” so change the difference into a sum. −7−(−16)=−7+16 Subtracting −16 is the same as adding 16. =9 Subtract the magnitudes, and prefix with sign of larger number. 33. In the expression (−8)6, the exponent 6 tells us to write the base −8 six times as a factor. Thus, (−8)6 =(−8)(−8)(−8)(−8)(−8)(−8). Now, the product of an even number of negative factors is positive. (−8)6 =262144 35. In the expression (−7)5, the exponent 5 tells us to write the base −7 five times as a factor. Thus, (−7)5 =(−7)(−7)(−7)(−7)(−7). Now, the product of an odd number of negative factors is negative. (−7)5 =−16807 37. In the expression (−9)2, the exponent 2 tells us to write the base −9 two times as a factor. Thus, (−9)2 =(−9)(−9). Now, the product of an even number of negative factors is positive. (−9)2 =81 39. In the expression (−4)4, the exponent 4 tells us to write the base −4 four times as a factor. Thus, (−4)4 =(−4)(−4)(−4)(−4). Now, the product of an even number of negative factors is positive. (−4)4 =256 Second Edition: 2012-2013 1.1. AN INTRODUCTION TO THE INTEGERS 5 41. To calculate the expression −562−1728, enter the expression -562-1728 using the following keystrokes. (-) 5 6 2 − 1 7 2 8 ENTER The result is shown in the following figure. Hence, −562−1728=−2290. 43. Tocalculatetheexpression−400−(−8225),entertheexpression-400-(-8225) using the following keystrokes. (-) 4 0 0 − ( (-) 8 2 2 5 ) ENTER The result is shown in the following figure. Hence, −400−(−8225)=7825. 45. To calculate the expression (−856)(232), enter the expression -856*232 using the following keystrokes. (-) 8 5 6 × 2 3 2 ENTER The result is shown in the following figure. Hence, (−856)(232)=−198592. Second Edition: 2012-2013 6 CHAPTER 1. THE ARITHMETIC OF NUMBERS 47. Tocalculatetheexpression(−815)(−3579),entertheexpression-815*-3579 using the following keystrokes. (-) 8 1 5 × (-) 3 5 7 9 ENTER The result is shown in the following figure. Hence, (−815)(−3579)=2916885. 49. To calculate the expression (−18)3, enter the expression (-18)∧3 using the following keystrokes. ( (-) 1 8 ) ∧ 3 ENTER The result is shown in the following figure. Hence, (−18)3 =−5832. 51. To calculate the expression (−13)5, enter the expression (-13)∧5 using the following keystrokes. ( (-) 1 3 ) ∧ 5 ENTER The result is shown in the following figure. Hence, (−13)5 =−371293. Second Edition: 2012-2013

See more

The list of books you might like

Most books are stored in the elastic cloud where traffic is expensive. For this reason, we have a limit on daily download.