ebook img

Delta-Isobar Magnetic Form Factor in QCD PDF

14 Pages·0.15 MB·English
Save to my drive
Quick download
Download
Most books are stored in the elastic cloud where traffic is expensive. For this reason, we have a limit on daily download.

Preview Delta-Isobar Magnetic Form Factor in QCD

CEBAF-TH-93-02 January 1993 Delta-Isobar Magnetic Form Factor in QCD 3 9 9 1 V.M.Belyaev n a J Institute of Theoretical and Experimental Physics 1 B.Cheremushkinskaya 25, 2 117259, Moscow, USSR 1 and v Continuous Electron Beam Accelerator Facility 7 12000 Jefferson Ave, Newport News, Virginia 23606, USA 5 2 1 0 3 9 h/ Abstract p - We consider the QCD sum rules approach for ∆-isobar magnetic p e form factor in the infrared region 0 ≤ Q2 < 1GeV2. The QCD sum h rules in external variable field are used. The obtained form factor is : v in agreement with quark model predictions for the ∆-isobar magnetic Xi moment. r a 1 Introduction The QCD sum rule method suggested by Shifman, Vainshtein and Zakharov (SVZ)inthepioneeringpaper[1]becomesnowauniversaltoolforcalculating different properties of low-lying hadronic states. Using the original version of this method, the meson [1] and baryon [2] masses were found from the sum rules for two-point correlation functions. Using the three-point correlation functions, hadron form factors at intermediate Q2 can be obtained [3]. Un- fortunately, this method does not work if one tries to calculate form factors in the infrared region 0 < Q2 < 1GeV2 due to power corrections 1/Q2n at Q = 0. The new method - QCD sum rules in external field was suggested in [4], and using this method nucleon magnetic moments were found [5] as well as baryon axial couplings [6]. Then this method was formulated for a variable external field [7] which gives a possibility to calculate form factors at Q2 6= 0. In [7] we have formulated a new method for calculating hadronic form factors in the infrared region. To study a form factor at nonzero Q2, it is necessary to introduce a variable external field. The calculation of a polar- ization operator in this field encounters a number of difficulties as compared with the case of a constant external field. The arising problems and methods to avoid them were discussed in detail in the paper [7]. Let us note that in the papers [8] and [9], the pion and nucleon charge radiiwereconsidered, using themethodssimilartoours. However, theresults obtained in [8] are connected not with the calculation of the total form factor F(Q2), but only the first derivative at zero momentum transfer < r2 >∼ F′(Q2)| . In [9] pion form factor was considered. The aim of the paper is Q=0 to use the general method for calculating ∆-isobar magnetic form factor in the infrared region. 2 Polarization Operator in Variable External Field To compute ∆-isobar magnetic form factor we shall consider the following correlator in an external variable electromagnetic field: ΠV∗(p,k) = i 2πδ(kx)eipxd4x < T{η (x),η¯ (0)} > (1) µν µ ν V Z 1 +∞ = dzi ei(p+kz)xd4x < T{η (x),η¯ (0)} > µ ν V Z−∞ Z +∞ = dzΠV (p+kz,k) µν Z−∞ where ΠV (p,k) = i eipxd4x < T{η (x),η¯ (0)} > (2) µν µ ν V Z η (x) = ǫabc(uaCγ ub)uc (3) µ µ is the quark current with the ∆-isobar quantum numbers suggested in the first paper in Ref.[2], u is the u-quark operator; a , b and c are the color indeces, ǫabc is the antisymmetric tensor and C = −CT is the charge conju- gation matrix; index V means the vacuum average in the presence of weak external electromagnetic field that is responsible for adding to Lagrangian of the following term ∆L = −V eikx e q¯ (x)γ q (x) = −V j (x)eikx (4) µ f f µ f µ µ f X where e is the charge of the quark with flavor f, V and k are the ampli- f µ µ tude and the momentum of the classical external field. This correlator was suggested in [7]. Now let us discuss the reason why we need to introduce the δ-function in the correlator (1). To calculate the correlator (2) atp2 ∼ −1GeV2, (p+q)2 ∼ −1GeV2, k2 = −Q2 < 0) we use operator product expansion in the presence of external variable field (4). So we need to know nonperturbative quark propagator in the field <: T{qa(x),qb(0)} :> (5) α β V =< T{qa(x),qb(0)} > − < T{qa(x),qb(0)} >(pert.) α β V α β V Where :: denotes a subtraction of perturbative contribution. It is possible to find perturbative part of this propagator in the form of expansion over the coupling constant. To take into account nonperturbative interaction of the quark with the external field, we expand eq.(5) over x µ <: T{qa(x),qb(0)} :> =<: qa(0),qb(0) :> (6) α β V α β V 2 1 +x <: D qa(0),qb(0) :> + x x <: D D qa(0),qb(0) :> +... µ µ α β V 2 µ ν µ ν α β V Itisclearthatthen’thtermofexpansion(6)cangivedimensionless factor (kx)n. Effectively it means that highest terms contribution of expansion (6) into a polarization operator (2) is not suppressed because this factor (kx)n corresponds to the factor (kp)/p2 ∼ 1. To kill the dangerous contributions of the terms ∼ (kx)n we insert δ(kx) into the correlator (1). This correlator (1) can be calculated in a form of series over 1/p2. Therefore at respectively large −p2 this correlator can be calculated with a good accuracy using only the first few terms in expansion (6). The nonperturbative quark propagator in the external field has the fol- lowing form: δab <: ua(x),u¯b(0) :>= e {Vˆ k2Π (k2) α β u 12 αβ 1 1 +(σ ) k V Π (k2)+(Vx)[i <: ψ¯ψ :> + k2Π (k2)]δ (7) ρλ αβ ρ λ 2 0 2 αβ 2 i i + Vˆ (kx)k2Π (k2)+ (σ ) k V (kx)Π (k2) αβ 1 ρλ αβ ρ λ 2 2 2 1 − x ε (γ γ ) k V k2Π (k2) µ µνρλ λ 5 αβ ν ρ 1 4 i + x2(σ ) k V [<: ψ¯ψ :> −iΠG(k2)−2ΠG(k2)+ik2Π (k2)] 12 ρλ αβ ρ λ 0 1 2 4 (kx)2 +(Vx)(kx)k2Π (k2)δ + (σ ) k V Π (k2) 3 αβ ρλ αβ ρ λ 4 2 (kx) 5 + x (σ ) V [ i <: ψ¯ψ :> +ΠG(k2)+3ik2Π (k2)+iΠG(k2) 12 µ µν αβ ν 2 0 1 3 2 5 (Vx) i − k2Π (k2)]+ x (σ ) k [ <: ψ¯ψ :> −ΠG(k2) 2 4 12 µ µν αβ ν 2 0 1 k2 −iΠG(k2)+3ik2Π (k2)− Π (k2)] 2 3 2 4 + (terms with an odd number of γ −matrices)}+O(x3) 3 The correlators Π (k2) are defined as follows: i e Π (k2)(k2g −k k ) = u 1 µν µ ν i eikxd4x <: T{ q¯ γ q (x),u¯γ u(0)} :> f µ f ν 0 Z f X e Π (k2)(k g −k g ) = (8) u 1 µ νρ ν µρ i eikxd4x <: T{ q¯ γ q (x),u¯σ u(0)} :> f ρ f µν 0 Z f X e Π (k2)(k2(g k +g k )−2k k k ) = u 3 µρ ν νρ µ µ ν ρ → i eikxd4x <: T{ e q¯ γ q (x),u¯ D D u(0)} :> f f ρ f {µ ν} 0 Z f X e Π (k2)k k (g k −g k )+... = u 4 µ ν ρr p ρp r → i eikxd4x <: T{ e q¯ γ q (x),u¯σ D D u(0)} :> f f ρ f pr {µ ν} 0 Z f X e ΠG(k2)(k g −k g ) = u 1 µ ρν ν ρµ i eikxd4x <: T{ e q¯ γ q (x),g u¯Gn tnu(0)} :> f f ρ f s µν 0 Z f X e ΠG(k2)(k g −k g ) = u 2 µ ρν ν ρµ i eikxd4x <: T{ e q¯ γ q (x),g u¯G˜n tnγ u(0)} :> f f ρ f s µν 5 0 Z f X Perturbative contributions are subtracted in correlators (8). These expres- sions were obtained in [7]. In this paper we neglect operators ΠG(k2) because their contribution into a sum rule is small (see [7]). 3 The Sum Rules In this Section, we obtain a sum rule for the ∆-isobar magnetic form factor. First, we should choose a tensor structure which has a contribution from the magnetic transition between baryon states with quantum numbers J = 3/2. To this end, we consider the contribution of two baryons with masses m and 1 4 m into the polarization operator ΠV(p,k) (2) 2 V < 0 | η | ∆ >< ∆ | jem | ∆ >< ∆ | η¯ | 0 > ρ µ 1 1 ρ 2 2 ν , (9) (p2 −m2)((p+k)2 −m2) 1 2 where∆ and∆ arebaryonstateswithmasses m andm respectively. Here 1 2 1 2 we consider the case when only spinor parts of the Rarita-Shwinger fields in- teract with a photon. In such case, thematrix element of theelectromagnetic current has the following form: < N | jem | N >= 1 ρ 2 v¯(1)(p)g [f (k2)γ + ϕ12(k2)σ k +ψ (k2)k ]v(2)(p+k) = µ µν 12 ρ m1+m2 ρλ λ 12 ρ ν v¯(1)(p)g [(f (k2)+ϕ (k2))γ +P ϕ12(k2) +ψ (k2)k ]v(2)(p+k) (10) µ µν 12 12 ρ ρm1+m2 12 ρ ν < 0 | η | N,JP = 3/2+ >= λv (p) µ µ P = p +(p+k) , µ µ µ where v (p) is a Rarita-Shwinger spin-vector satisfying the Dirac equation: µ (pˆ−m)v (p) = 0, γ v = 0, p v = 0. µ µ µ µ µ Using (10) we can transform (9) to the following form: λ λ 1 2 V [g pˆ γ pˆ G (k2)/3 (11) (p2 −m2)((p+k)2 −m2) µ µν 1 ρ 2 M 1 2 +(other structures with γ placed at the beginning and γ at the end of them)] µ ν where G is the magnetic form factor. M It is important to note that there is no spin-1/2 baryon contribution in the structure g pˆ γ pˆ which has the following amplitude: µν 1 ρ 2 < 0 | η | J = 1/2 >= (Ap +Bγ )u(p) ρ µ µ where (pˆ−m)u(p) = 0 and Am+4B = 0. From (11), it is obvious that the structure g pˆ γ pˆ (where p = p and µν 1 ρ 2 1 p = p+k)containsmagnetictransitiononly, sinceG12/3 = f (k2)+ϕ (k2), 2 M 12 12 where G12 is the magnetic form factor. So, we shall further consider only the M structure g pˆ γ pˆ . µν 1 ρ 2 Now let us discuss the factor 1/3 which have appeared in eq.(11). Con- sider interaction of spin-3/2 particle with the electromagnetic field: a(Ψ (P )g (P +P ) Ψ (P )+ibΨ (σ g /2+2g g )Ψ F (12) µ 1 µν 1 2 ρ ν 2 µ ρλ µν µρ νλ ν ρλ 5 where 1σ = [γ γ ], Ψ is Rarita-Shwinger spin-vector field ( (Pˆ − m) = 2 ρλ ρ λ µ 0,γ Ψ = 0), F = ∂ A −∂ A . The first term of eq.(12) corresponds to µ µ ρλ ρ λ λ ρ the spin-independent part of electromagnetic interaction of 3-spin particle 2 and the second one describes the spin-dependent interaction. To express the value of the magnetic moment (at Q2 = 0) let us consider the case when A = 0,P = m,F = δ δ ǫ H , where H is magnetic field. Then we 0 0 ρλ ρi λj ijk k k have ibΨ (g σ ǫ /2+2ǫ )Ψ H = bΨ (g Σ +2iǫ )Ψ H (13) m mn ij ijk mnk n k m mn k mnk n k where Σ = diag(σ ,σ ) Now we see that the operator (Σ g + 2iǫ ) is k k k k mn mnk equal to 2S where S is spin operator for the Rarita-Shwinger field. So, the k k maximal energy of the particle in the magnetic field is equal to E = 3bH = µH, (14) int. where µ, by definition, is magnetic moment or magnetic form factor at Q2 = 0. Thus, we have µ = 3b (15) Now let us consider the double dispersional relation for the function at tensor structure g pˆ γ pˆ V : µν 1 ρ 2 ρ 1 ∞ ∞ ρ(s ,s ,Q2) f(P2,P2,Q2) = 1 2 , (16) 1 2 π2 (P2 +s )(P2 +s ) Z0 Z0 1 1 2 2 where P2 = −p2, P2 = −p2, Q2 = −k2 ≥ 0 and ρ(s ,s ,Q2) is the spectral 1 1 2 2 1 2 density. Due to reasons mentioned above, we cannot calculate ρ(p ,p ,Q2) 1 2 directly, but we can consider the double Borel transformed structure function of correlator (1). Notice, that under replacement p → p +kz, p → p +kz 1 1 2 2 the structure pˆ γ pˆ V transforms to 1 µ 2 µ ˆ ˆ ˆ ˆ pˆ γ pˆ V → (pˆ +kz)V(pˆ +kz) = pˆ Vpˆ −2(Vp )pˆ z − (17) 1 µ 2 µ 1 2 1 2 1 1 2(Vp )pˆ z +(p2 +p2)zVˆ +z2(2(Vk)kˆ−Vˆk2) 2 2 1 2 and all other structures in (11) with smaller number of γ−matrices near ˆ ˆ g , could not be transformed into pˆ Vpˆ . So we can extract g pˆ Vpˆ µν 1 2 µν 1 2 in the integral (1). Then the integral representation for the double Borel 6 transformed structure function under consideration is obtained from (16) by applying the operator Oˆ: +∞ Oˆf(P2,P2) = dzBˆ Bˆ f((P +kz)2,(P +kz)2) (18) 1 2 P2 P2 1 2 Z−∞ 1 2 where (P2)n+1 ∂ n Bˆ= lim − n→∞ n! ∂P2! P2/n = M2 M2 is the Borel parameter. Applying the operator Oˆ to the left-hand and right-hand sides of double dispersion relation (16) we get 1 +1/2 Q2z2 f(M2,Q2) = exp( )× π2 M2 Z−1/2 ∞ ∞ s +s (s −s )z ds ds exp(− 1 2 + 1 2 )ρ(s ,s ,Q2) (19) 1 2 2M2 M2 1 2 Z0 Z0 where M2 = M2 = 2M2. 1 2 We shall use the sum rules (19) to calculate the nucleon form factor. The function f(M2,Q2) is calculated using operator expansion in the external field, and thespectral density ρ(s ,s ,Q2) issaturated by intermediate states 1 2 with quantum numbers of the current (3). Therearetwodifferent typesofintermediatestatecontributionsinto(19). The first is responsible for the diagonal transitions between the states with equal masses. The second is responsible for nondiagonal transitions between the states with different masses. In the first case the right-hand side of (19) obviously has the form λ2GM(Q2)e−m2/M2 +1/2eQM2z22dz (20) 3 Z−1/2 where λ2 is the square of the residue of the state with mass m into the current η defined by formula (10), G (Q2) is the corresponding magnetic µ M form factor. 7 In the second case for the transition between states with masses m and 1 m we get: 2 λ1λ2G(M12)(Q2)e−m221M+m222 +1/2eQ2z2+(Mm221−m22)zdz (21) 3 Z−1/2 Now, to investigate the properties of (20) and (21) let us expand them in the series on Q2/M2 G (Q2) 1 Q2 1 q2 λ2 M e−m2/M2(1+ + ( )2 +... ) (22) 3 12M2 5·25 M2 β1β2G1M2(Q2)e−m221M+m222 m22M−2m2 sinh(m212M−2m22)× (23) 1 2 Q2 1 M2 m2 −m2 2M4 {1+ [ − coth( 1 2)+ ]+...} M2 4 m2 −m2 2M2 (m2 −m2)2 1 2 1 2 From (22) and (23) we see that diagonal transitions of the excited states are exponentially suppressed compared to the ∆-isobar contribution in (22). Let us write the non-suppressed part of the contribution from the nondiagonal transition between the nucleon with mass m and anexcited state with mass N m∆∗ G∆∆∗(Q2) e−mM2∆2M2 λλ∆∗ M 3 m2 −m2 {1 + ∆∗ ∆ Q2 1 M2 m2 −m2 2M4 [ − coth( ∆∗ ∆) + ]+...} (24) M2 4 m2 −m2 2M2 (m2 −m2 )2 ∆∗ ∆ ∆∗ ∆ where m∆, m∆∗, λ and λ∆∗ are masses and residues of ∆-isobar and its resonance ∆∗ respectively. Expression (24) isanalogoustothecontribution fromthesingle-poleterm appearing in QCD sum rules for correlators in constant external field (see [4]). It is easy to see that the function multiplied by Q2/M2 in (24) changes from 1/12 at m2 −m2 → 0 to 1/4 at m2 −m2 → ∞. However, taking into 2 ∆ 2 ∆ account the continuum, only contributions from the states with m2 −m2 ∼ 2 ∆ s −m2 (s is the continuum threshold) are to be considered. In the region 0 ∆ 0 8 s ≫ s , our model of continuum is quite correct, but when s ∼ s it is not 0 0 so. Then we see, that nonexponentially suppressed terms will be determined by the states with m2 ∼ s . Taking m2 − m2 ≃ s − m2 ≃ 1.5GeV2, 2 0 2 ∆ 0 ∆ M2 ∼ 1GeV2, expression (24) can be written in the form λ λ G∆M∆∗(Q2) e−mM2∆2M2 (1+ Q2 (1+ǫ)+... ) (25) ∆ ∆∗ 3 m2 −m2 12M2 ∆∗ ∆ where ǫ < 0.1. Thus, from (22) and (25) it is seen that when Q2/M2 ≤ 1, and M2 ∼ 1GeV2, the right-hand side of (19) is 31λ2∆e−m2∆/M2(GM(Q2)+C(Q2)M2) +1/2eQM2z22dz (26) Z−1/2 The accuracy of (26) is of an order of a few percents (it depends on the numerical value of ǫ from (25)). It can be shown, that the next terms in the expansion (23) in powers of Q2/M2 do not change the situation. So, in the region Q2/M2 ≤ 1, M2 ∼ 1GeV2, the right side of the sum rule (19) is indeed represented by expression (26). Let us note that when Q2/M2 > 1, the expression (26) is invalid and we cannot separate the contribution of the single-pole terms from the contribu- tion of the us double-pole term ∼ G (Q2) which we are interested in. Thus, M our sum rule is expected to be valid in the region 0 ≤ Q2 < 1GeV2. Here we have constructed the right-hand ”phenomenological” side of the sum rule (19) and discussed the region of its applicability. Now, let us pass to the calculation of the left, ”theoretical” part of our sum rule. Using eq.(7) and dispersion integral (19) we have obtained the following sum rule for G : M +1/2eQ2z2/M2dz s0ds1 s0ds2e−s21M+s22+zs1M−2s2 ρ∆(s1π,s22,Q2) Z−1/2 Z0 Z0 2 +1/2 + a2 dzeQ2z2/M2 (27) 3 Z−1/2 +2(2π)2a(iΠ2(Q2))M2e4QM22 3 9

See more

The list of books you might like

Most books are stored in the elastic cloud where traffic is expensive. For this reason, we have a limit on daily download.