classroom contact programme

36 Pages·2012·1.7 MB·English

Hindi
 TM PAPER CODE 0 0 C M 3 1 4 0 0 2
CAREER INSTITUTE
FORM NUMBER
Path to Success KOTA (RAJASTHAN)
CLASSROOM CONTACT PROGRAMME
(ACADEMIC SESSION 2014-2015)
ENTHUSIAST, LEADER & ACHIEVER COURSE
TARGET : PRE-MEDICAL 2015
ALL INDIA OPEN TEST # 02 DATE : 19 - 04 - 2015
Test Type : Major Test Pattern : AIPMT
INSTRUCTIONS 
1. A seat marked with Reg. No. will be allotted to each student. The student should ensure that he/she occupies the correct seat only.
If any student is found to have occupied the seat of another student, both the students shall be removed from the examination and
shall have to accept any other penalty imposed upon them.
 

2. Duration of Test is 3 Hours and Questions Paper Contains 180 Questions. The Max. Marks are 720.
3180720
3. Student can not use log tables and calculators or any other material in the examination hall.

4. Student must abide by the instructions issued during the examination, by the invigilators or the centre incharge.

5. Before attempting the question paper ensure that it contains all the pages and that no question is missing.

6. Each correct answer carries 4 marks, while 1 mark will be deducted for every wrong answer. Guessing of answer is harmful.
1
7. A candidate has to write his / her answers in the OMR sheet by darkening the appropriate bubble with the help of Blue / Black Ball
Point Pen only as the correct answer(s) of the question attempted.
OMR 

8. Use of Pencil is strictly prohibited.

Note : In case of any Correction in the test paper, please mail to [email protected] within 2 days along with Your Form
No. & Complete Test Details.
Correction Form No. Test Details 
[email protected] mail
Do not open this Test Booklet until you are asked to do so / 
Corporate Office
 CAREER INSTITUTE
“SANKALP”, CP-6, Indra Vihar, Kota (Rajasthan)-324005
[phone] [email protected]
www.allen.ac.in
Your Target is to secure Good Rank in Pre-Medical 2015
ALL INDIA OPEN TEST/Pre-Medical /AIPMT/19-04-2015
HAVE CONTROL  HAVE PATIENCE  HAVE CONFIDENCE  100% SUCCESS
BEWARE OF NEGATIVE MARKING
1 The ratio of the difference in energy of electron 1. 
between the first and second Bohr’s orbits to that 
between second and third Bohr’s orbit is : 
1 27 9 4 1 27 9 4
(1) (2) (3) (4) (1) (2) (3) (4)
3 5 4 9 3 5 4 9
2. Work for the following process ABCD on a 2. ABCD W
monoatomic gas is : 
P P
A B A B
P P
0 0
Isotherm Isotherm
C C
D D
V 2V 4V V V 2V 4V V
0 0 0 0 0 0
(1) w = – 2 P V ln 2, (2) w = – 2 P V (1) w = – 2 P V ln 2, (2) w = – 2 P V
0 0 0 0 0 0 0 0
(3) w = – P V (1+ ln 2)(4) w = – P V ln 2, (3) w = – P V (1+ ln 2)(4) w = – P V ln 2,
0 0 0 0 0 0 0 0
3. Which of the following compounds has 3. Z- ?
Z-configuration ?
H C CHCH
3 2 3
C = C
H C CHCH (i)
3 C = C 2 3 H I
(i)
H I
BrCH CH–OH
2 2
C = C
BrCH CH–OH (ii)
2 C = C 2 H C CHCH
(ii) 3 2 3
H C CHCH
3 2 3 Br CH(CH)
3 2
C = C
Br CH(CH) (iii)
C = C 3 2 HOCH CHCHCH
(iii) 2 2 2 3
HOCH CHCHCH
2 2 2 3 H CHCl
2
C = C
H CHCl (iv)
C = C 2 CHCH COOH
(iv) 3 2
CHCH COOH
3 2 (1) i, iii (2) ii, iv
(1) i, iii (2) ii, iv (3) i, iv (4) ii, iii (3) i, iv (4) ii, iii
4. Which of the following vitamins is water soluble? 4.  ?
(1) Vitamin E (2) Vitamin K (1) E (2)  K
(3) Vitamin A (4) Vitamin B (3) A (4) B
5. Singlet :CF is more stable than singlet :CH :- 5. : CH  : CF  :-
2 2 2 2
(1) Due to more E.N. difference (1) 
(2) Due to p -d back bonding (2) p -d 
   
(3) Due to p -p back bonding (3) p -p 
   
(4) Due to one lone pair e– (4)  e– 
00CM314002 1/35
ALL INDIA OPEN TEST/Pre-Medical /AIPMT/19-04-2015
6. The volume of a gas increases by a factor of 2 6. 2  3
while the pressure decreases by a factor of 3.  
Given that the number of moles is unaffected, the  
factor by which the temperature changes is : 
3 2 1 3 2 1
(1) (2) 3 × 2 (3) (4) × 3 (1) (2) 3 × 2 (3) (4) × 3
2 3 2 2 3 2
7. The heat evolved in neturalizing a solution of 7. HCN 
HCN with a strong alkali is 3.0 kcal. The enthalpy 3.0 kcal  HCN 
of dissociation of HCN is 
(H of (SA + SB) = –13.7 kcal/eq) (H (SA + SB) = –13.7 kcal/eq)
neutralization neutralization
(1) 10.2 kcal (2) 13.7 kcal (1) 10.2 kcal (2) 13.7 kcal
(3) 10.7 kcal (4) 16.7 kcal (3) 10.7 kcal (4) 16.7 kcal
8. Al C , Mg C , and CaC are hydrolyzed separately. 8. Al C , Mg C ,  CaC 
4 3 2 3 2 4 3 2 3 2
The hydrocarbons formed are ____ respectively 
(1) acetylene, methane, methylacetylene (1)  ,  ,  
(2) methylacetylene, methane, acetylene (2)  ,  ,  
(3) methane, methylacetylene, acetylene (3)  ,  ,  
(4) methylacetylene, acetylene, methane (4)  ,  ,  
9. The carboxyl functional group (–COOH) is present in:- 9. (–COOH)  :-
(1) Picric acid (1) 
(2) Barbituric acid (2) 
(3) Ascorbic acid (3) 
(4) Aspirin (4) 
10. In which of the following change, change in bond 10.  
angle is maximum ?   ?
(1) NH H NH (2) BF F BF (1) NH H NH (2) BF F BF
3 4 3 4 3 4 3 4
(3) H OH H O (4) PH H PH (3) H OH H O (4) PH H PH
2 3 3 4 2 3 3 4
11. The strength of 10– 2 M Na CO solution in terms of 11. 10– 2 M Na CO 
2 3 2 3
molality will be (density of solution = 1.10 gmL–1).  (   = 1.10 g mL–1).
(Molecular weight of Na CO = 106 g mol) (Na CO = 106 g mol)
2 3 2 3
(1) 9.00 × 10 – 3 (2) 1.5 × 10–2 (1) 9.00 × 10 – 3 (2) 1.5 × 10–2
(3) 5.1 × 10–3 (4) 11.2 × 10– 3 (3) 5.1 × 10–3 (4) 11.2 × 10– 3
12. 50 mL of 5.6% KOH (w/v) is added to 50 mL 12. 5.6% KOH (w/v) 50 mL 5.6% HCl (w/v)
of a 5.6% HCl (w/v) solution. The resulting 50 mL 
solution will be 
(1) neutral (2) alkaline (1)  (2) 
(3) strongly alkaline (4) acidic (3)  (4) 
Take it Easy and Make it Easy
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13. Which of the following methods would you consider 13.  n-
to be the best for preparing n-propylbenzene ?  ?
(1) C H Br + CH CH CH Br Na  (1) C H Br + CH CH CH Br Na 
6 5 3 2 2 Et2O, 6 5 3 2 2 Br2O,
(2) C H + CH CH = CH H3PO4 (2) C H + CH CH = CH H3PO4
6 6 3 2 250C 6 6 3 2 250C
(3) C H + CH CH CH ClAlCl3 (3) C H + CH CH CH ClAlCl3
6 6 3 2 2 Heat 6 6 3 2 2 Heat
(4) C H + (1)CH3CH2COCl/AlCl3 (4) C H + (1)CH3CH2COCl/AlCl3
6 6 6 6
(2)ZnHg,HCl,heat (2)ZnHg,HCl,heat
14. Markovnikov's rule is best applicable to :- 14.  :-
(1) C H + HCl (2) C H + Br (1) C H + HCl (2) C H + Br
2 4 3 6 2 2 4 3 6 2
(3) C H + HBr (4) C H + Cl (3) C H + HBr (4) C H + Cl
3 6 3 6 2 3 6 3 6 2
15. Which of the has minimum melting point :- 15.   :-
(1) Cu Cl (2) CrO (1) Cu Cl (2) CrO
2 2 2 2
(3) CaCl (4) KCl (3) CaCl (4) KCl
2 2
16. For the complex 16. 
Ag+ + 2NH [Ag(NH ) +] Ag+ + 2NH [Ag(NH ) +]
3 3 2 3 3 2
dx dx
  = 2 × 107 L2 mol–2 s–1 [Ag+] [NH]2 – 1 × 10–2 s–1 [Ag(NH)+]   = 2 × 107 L2 mol–2 s–1 [Ag+] [NH]2 – 1 × 10–2 s–1 [Ag(NH)+]
 dt 3 32  dt 3 32
Hence, ratio of rate constants of the forward and 
backward reactions is : 
(1) 2 × 107 L2 mol–2 (1) 2 × 107 L2 mol–2
(2) 2 × 109 L2 mol–2 (2) 2 × 109 L2 mol–2
(3) 1 × 10–2 L2 mol–2 (3) 1 × 10–2 L2 mol–2
(4) 0.5 × 10–9 L2 mol–2 (4) 0.5 × 10–9 L2 mol–2
17. In diamond, carbon atom occupy FCC lattice 17. FCC
points as well as alternate tetrahedral voids. If edge 
length of the unit cell is 356 pm, then radius of 356 pm
carbon atom is 
(1) 77.07 pm (2) 154.14 pm (1) 77.07 pm (2) 154.14 pm
(3) 251.7 pm (4) 89 pm (3) 251.7 pm (4) 89 pm
18. Among the compounds :- 18. :-
CH OCH CF CH OCH CF
3 3 3 3 3 3

II
I III IV I II III IV
the order of decreasing reactivity towards 
electrophilic substitution is :-   :-
(1) II > I > III > IV (2) III > I > II > IV (1) II > I > III > IV (2) III > I > II > IV
(3) IV > I > II > III (4) I > II > III > IV (3) IV > I > II > III (4) I > II > III > IV
19. The ease of dehydrohalogenation of alkyl halides 19.      KOH
with alcoholic KOH is :-  :-
(1) 3º < 2º < 1º (2) 3º > 2º > 1º (1) 3º < 2º < 1º (2) 3º > 2º > 1º
(3) 3º < 2º > 1º (4) 3º > 2º < 1º (3) 3º < 2º > 1º (4) 3º > 2º < 1º
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20. During the formation of a molecular orbital form 20.  
atomic orbitals, probability of electron density is:- :-
(1) Minimum in the nodal plane (1) 
(2) Maximum in the nodal plane (2) 
(3) Zero in the nodal plane (3) 
(4) Zero on the surface of the node (4) 
21. Acid catalysed hydrolysis of ester is first-order 21. 
reaction and rate constant is given by 
2.303 V V 2.303 V V
 0  0
k = log k = log
t V V t V V
 t  t
where V , V and V are the volume of standard V , V V 
0 t  0 t 
NaOH required to neutralise acid present at a NaOH 
given time ; if ester is 50% hydrolysed then : 50%  
(1) V = V (2) V = (V – V ) (1) V = V (2) V = (V – V )
 t t 0  t t 0
(3) V = 2V – V (4) V = 2V + V (3) V = 2V – V (4) V = 2V + V
 t 0  t 0  t 0  t 0
22. Which of the following statement(s) is/are correct ? 22. 
(A) the pH of 1.0 × 10–8 M solution of HCl is 8 (1) 1.0 × 10–8 M HCl pH8 
(B) the conjugate base of H PO– is HPO2– (2) H PO–  HPO2–
2 4 4 2 4 4
(C) autoprotolysis constant of water increases with (3) (autoprotolysis)
temperature 
(D) when a solution of a weak monoprotic acid (4) 
is titrated against a strong base, at half - 
neutralization point pH = pK . pH = pK 
a a
(1) BCD (2) ABC (3) ACD (4) AC (1) BCD (2) ABC (3) ACD (4) AC
23. When m-chlorobenzaldehyde is treated with 50% 23. m-50% KOH 
KOH solution the product(s) obtained is(are) : :
(1) m-OHC H COO¯ + m-OHC H CH OH (1) m-OHC H COO¯ + m-OHC H CH OH
6 4 6 4 2 6 4 6 4 2
(2) m-ClC H COO¯ + m-ClC H CH OH (2) m-ClC H COO¯ + m-ClC H CH OH
6 4 6 4 2 6 4 6 4 2
(3) m-ClC H CHOH¯ + m-CH OH –C H Cl (3) m-ClC H CH O¯ + m-CH OH –C H Cl
6 4 2 6 4 6 4 2 2 6 4
(4) m-OHC H CHOH¯ + m-CH OH –C H OH (4) m-OHC H CH O¯ + m-CH OH –C H OH
6 4 2 6 4 6 4 2 2 6 4
24. Find the order of stability of carbocation :- 24.  :-
CH CH
3 3
   
(A)CH – C – CH (B) CH OCH (A)CH – C – CH (B) CH OCH
3 2 2 3 3 2 2 3
CH CH
3 3
A A
   
(C) CH – CH (D) Ph – CH (C) CH – CH (D) Ph – CH
3 2 2 3 2 2
(1) B > D > C > A (2) A > C > D > B (1) B > D > C > A (2) A > C > D > B
(3) D > A > C > B (4) D > C > A > B (3) D > A > C > B (4) D > C > A > B

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25. Which of the following pair contain structurally 25.    :-
dissimilar substances :- (1) 
(1) Borazine and Benzene
(2) 
(2) Diborane and Hydrazine
(3) NaCl  NiO
(3) NaCl and NiO
(4) Graphite and Cadmium iodide (4) 
26. The solubility of Calcium phosphate in water is 26. 25°C  x mol L–1 
x mol L–1 at 25ºC. Its solubility product is equal to (solubility product)
(1) 108 x2 (2) 36 x3 (1) 108 x2 (2) 36 x3
(3) 36 x5 (4) 108 x5 (3) 36 x5 (4) 108 x5
27. Among the electrolytes Na SO , CaCl , Al (SO ) 27. Na SO , CaCl , Al (SO )  NH Cl, Sb S
2 4 2 2 4 3 2 4 2 2 4 3 4 2 3
and NH Cl, the most effective coagulation agent  coagulation 
4
for Sb S sol is 
2 3
(1) Na SO (2) CaCl (1) Na SO (2) CaCl
2 4 2 2 4 2
(3) Al (SO ) (4) NH Cl (3) Al (SO ) (4) NH Cl
2 4 3 4 2 4 3 4
28. The dipole moment is the highest for :- 28.   :-
(1) trans-2-butene (1) -2-
(2) 1, 3-dimethylbenzene (2) 1, 3 
(3) acetophenone (3)  
(4) ethanol (4) 
29. Determine the correct order of Bond angle in 29. SO F  :-
2 2
SO F Molecule:-
2 2 O
O

  S

S
   F

F
(1)    (2)   (1)    (2)  
           
(3)    (4)   (3)    (4)  
           
30. The hybrid state of B-atom in boron-hydride is 30. B- sp2 
sp2 while in its dimer, it has sp3 hybrid state  sp3 
because :-
 :-
(1) One of the empty orbitals of boron take part
(1) 
in hybridization.
(2) H  B s & p 
(2) Overlapping between s & p orbitals of H and
 
B forms a  bond.
(3) B H is a electron rich compound. (3) B H 
2 6 2 6
(4) B H is less stable than BH . (4) B H , BH 
2 6 3 2 6 3
31. A complex containing K+, Pt(IV) and Cl¯ is 100% 31.  K+, Pt(IV)  Cl¯ 100% 
ionised giving i = 3. Thus, complex is :  i = 3  
(1) K [PtCl ] (2) K [PtCl ] (1) K [PtCl ] (2) K [PtCl ]
2 4 2 6 2 4 2 6
(3) K [PtCl ] (4) K[PtCl ] (3) K [PtCl ] (4) K[PtCl ]
3 5 3 3 5 3
32. At – 50ºC autoprotolysis of NH gives 32. – 50ºC 
3
[NH+ ] = 1 × 10–15 M hence, autoprotolysis [NH+ ] = 1 × 10–15 M  
4 4
constant of NH is: 
3
(1) 11015 (2) 1 × 10 –30 (1) 11015 (2) 1 × 10 –30
(3) 1 × 10–15 (4) 2 × 10–15 (3) 1 × 10–15 (4) 2 × 10–15
00CM314002 5/35
ALL INDIA OPEN TEST/Pre-Medical /AIPMT/19-04-2015
33. The strongest acid amongst the following 33.  :-
compounds is :-
(1) HCOOH
(1) HCOOH
(2) CH CH CH(Cl)CO H
(2) CH CH CH(Cl)CO H 3 2 2
3 2 2
(3) ClCH CH CH COOH
(3) ClCH CH CH COOH 2 2 2
2 2 2
(4) CH COOH (4) CH COOH
3 3
34. If violation of Hund's rule is possible then the 34.  
magnetic nature of B & O (According to MOT) B & O  
2 2 2 2
respectively will be :-   :-
(1) Paramagnetic, Diamagnetic (1)  , 
(2) Diamagnetic, Paramagnetic (2) ,  
(3) Both are Diamagnetic (3) 
(4) Both are Paramagnetic (4)  
35. Fluorine does not form any polyhalide as other 35.   
halogens because :-  :-
(1) It has maximum ionic character (1) 
(2) It has low F-F bond energy (2) F-F 
(3) Due to absence of d-orbitals in valence shell (3) d-
of fluorine 
(4) It has maximum co-ordination no. in other (4)  
elements. 
36. The standard oxidation potentials, E°, for the 36.  E°
half-reaction are as 
Zn = Zn2+ + 2e– ; E° = + 0.76 V Zn = Zn2+ + 2e– ; E° = + 0.76 V
Fe = Fe2+ + 2e– ; E° = + 0.41 V Fe = Fe2+ + 2e– ; E° = + 0.41 V
the E° is - E°  
cell 
Fe+2 + Zn Zn2+ + Fe is - Fe+2 + Zn Zn2+ + Fe is -
(1) –0.35 V (2) + 0.35 V (1) –0.35 V (2) + 0.35 V
(3) +1.17 V (4) – 1.17 V (3) +1.17 V (4) – 1.17 V
37. A vessel contains 100 litres of a liquid x. Heat is 37. 100  x  
supplied to the liquid in such a fashion that, Heat  = 
given = change in enthalpy. The volume of the
 1 atm
liquid increases by 2 litres. If the external pres-
 202.6 [U - 
sure is one atm, and 202.6 Joules of heat were
]
supplied then, [U - total internal energy]
(1) U = 0 , H = 0
(1) U = 0 , H = 0
(2) U = + 202. 6J , H = + 202.6 J (2) U = + 202. 6J , H = + 202.6 J
(3) U = – 202.6J, H = – 202.6J (3) U = – 202.6J, H = – 202.6J
(4) U = 0, H = + 202.6J (4) U = 0, H = + 202.6J
38. C H CONHCH can be converted into 38. C H CONHCH C H CH NHCH 
6 5 3 6 5 3 6 5 2 3
C H CH NHCH by :-   :-
6 5 2 3
(1) NaBH (2) H -Pd/C (1) NaBH (2) H -Pd/C
4 2 4 2
(3) LiAlH (4) Zn-Hg/HCl (3) LiAlH (4) Zn-Hg/HCl
4 4
6/35 00CM314002
ALL INDIA OPEN TEST/Pre-Medical /AIPMT/19-04-2015
39. In zieses salt, (C=C) bond length is :- 39. , (C=C)  :-
Note : C–C bond length in ethane is 1.54Å Note :  C–C   1.54Å
C=C bond length in ethene is 1.34Å  C=C   1.34Å
CCbond length in ethyne is 1.20Å  CC   1.20Å
(1) 1.37 Å (2) 1.19 Å (1) 1.37 Å (2) 1.19 Å
(3) 1.87Å (4) 1.34Å (3) 1.87Å (4) 1.34Å
40. K (CN) Co–O–OCo(CN) Oxidises 40. K (CN) Co–O–OCo(CN) Oxidises
6 5 5 6 5 5
(x) (x)
K (CN) Co–O–OCo(CN)  K (CN) Co–O–OCo(CN) 
5 5 5 5 5 5
(y) (y)
In both complexes Co have t g6eg0 configuration Co t g6eg0  x  y
2 2
the bond energy (B.E.) in x and y is- -
(1) B.E. of (O–O) in y < B.E. of (O–O) in x (1) B.E. of (O–O) in y < B.E. of (O–O) in x
(2) B.E. of (O–O) in x < B.E. of (O–O) in y (2) B.E. of (O–O) in x < B.E. of (O–O) in y
(3) B.E. of (O–O) in x = B.E. of (O–O) in y (3) B.E. of (O–O) in x = B.E. of (O–O) in y
(4) B.E. of (O–O) in x and B.E. of (O–O) in y (4) B.E. of (O–O) in x and B.E. of (O–O) in y
can't be predicted. can't be predicted.
41. In the electrolysis of an aqueous nickel(II) sulphate 41. (II) 
solution, the process 2H O = 2O + 4H+ + 4e-
2 2  2H O = 2O + 4H+ + 4e– 
2 2
occurs at the anode. The material of construction
  
of the anode is
(1)  (2) 
(1) nickel (2) gold
(3) copper (4) none of these (3)  (4) 
42. Propene reacts with HOCl to give :- 42. HOCl :-
(1) CH CHClCH OH (1) CH CHClCH OH
3 2 3 2
(2) CH CH(OCl)CH (2) CH CH(OCl)CH
3 3 3 3
(3) CH CHOHCH Cl (3) CH CHOHCH Cl
3 2 3 2
(4) CH CH CH OCl (4) CH CH CH OCl
3 2 2 3 2 2
43. Which of the following will not give a primary 43.  ?
amine ?
(1) CH CN LiAlH4
3
(1) CH CN LiAlH4
3
(2) CH NC LiAlH4
(2) CH NC LiAlH4 3
3
(3) CH CONH LiAlH4 (3) CH3CONH2 LiAlH4
3 2
(4) CH CONH Br2,NaOH (4) CH CONH Br2,NaOH
3 2 3 2
44. Select the correct order for bond angle :- 44.  :-
(1) CF = CCl = CBr = CI (1) CF = CCl = CBr = CI
4 4 4 4 4 4 4 4
(2) BeCl > BCl > CCl (2) BeCl > BCl > CCl
2 3 4 2 3 4
(3) SiF = SiCl = SiBr (3) SiF = SiCl = SiBr
4 4 4 4 4 4
(4) All are correct (4) 
45. Which one is least basic :- 45.  :-
(1) NF (2) NCl (3) NH (4) NBr (1) NF (2) NCl (3) NH (4) NBr
3 3 3 3 3 3 3 3

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46. 46.
A A
D D
C C
B B
Identify A, B, C and D in the given diagram A, B, C D 
of male reproductive system and find out the  
option which show its correct correlation :-   :-
Column-I Column-II Column-III -I -II -III
(1) A Ureter Urinogenital (1) A  
passage
(2) B  
(2) B Prostate Paired gland around

urethra which

secrete alkaline

fluid
(3) C  
(3) C Ejaculatory Formed by union of

duct vas deference and

duct of epididymis
(4) D  
(4) D Vas deference Join with duct of

seminal vesicle to
form ejaculatory 
duct 
47. The -----A------ labyrinth is a series of channels. 47. -----A------  
Inside these channels lies the -----B------ ------B-----  
labyrinth, which is surrounded by a fluid called
------C-----   -----D------ -
C The D labyrinth is filled with
----------- -----------
----E------  :-
a fluid called E :-
-----------
A B C D E A B C D E
Memb- Memb- Endo- (1)    
(1) Bony Perilymph
ramous ramous lymph
Endo- Memb- (2)     
(2) Bony Bony Perilymph
lymph ramous
Memb- Memb- Endo-
(3) Bony Perilymph (3)     
ramous ramous lymph
Memb- Memb- Endo-
(4) Bony Perilymph (4)     
ranous ramous lymph

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48. Signet ring shaped cartilage found in larynx is:- 48. 
(1) Thyroid (1) 
(2) Cricoid (2) 
(3) Corniculate (3) 
(4) Arytenoid (4)  
49. Given gene A at frequency 0.2 and gene B at 49. A  0.2  B 
frequency 0.6, find the equlibrium frequencies 0.6 equlibrium
of the gametes :-
frequencies 
AB, Ab, aB, and ab
AB, Ab, aB, and ab
I II III IV I II III IV
AB Ab aB ab AB Ab aB ab
(1) 0.32 0.48 0.08 0.12 (1) 0.32 0.48 0.08 0.12
(2) 0.12 0.08 0.48 0.32 (2) 0.12 0.08 0.48 0.32
(3) 0.48 0.08 0.12 0.08 (3) 0.48 0.08 0.12 0.08
(4) 0.08 0.12 0.48 0.32 (4) 0.08 0.12 0.48 0.32
50. Find the group of bacteria in which all are 50. 
nitrogen fixing :-  :-
(1) Nitrosomonas, Streptococus, Lactobacillus (1) 
(2) Rhizobium, Azotobacter, Nostoc (2) 
(3) Nitrobacter, Streptobacillus, Lactobacillus (3) 
(4) Clostridium, Rhizobium, Lactobacillus (4) 
51. Which type of homology exists between hand 51.  
of man and foot of horse ? 
(1) Phylogenetic ( 2) Sexual (1)  (2) 
(3) Serial (4) Molecular homology
(3)  (4) 
52. 52.
Above shown plant doesn’t give 
(1) Morphine (2) Marijuana (1)  (2)  
(3) Cocaine (4) 2 & 3 both (3)  (4) 2 3 
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