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AN APPLICATION OF SCATTERING THEORY TO THE SPECTRUM 3 OF THE LAPLACE-BELTRAMI OPERATOR 0 0 2 FRANCESCA ANTOCI n a J Abstract. Applying a theorem due to Belopol’ski and Birman, we 0 show that the Laplace-Beltrami operator on 1-forms on Rn endowed 1 withanasymptoticallyEuclideanmetrichasabsolutelycontinuousspec- trum equalto [0,+∞). ] P S . h t a m 1. Introduction [ The relationships between the geometric properties of a complete non- 1 compact Riemannian manifold and the spectrum of the Laplace-Beltrami v 9 operator have been intensively investigated by many authors. 9 Among them, H. Donnelly since the late seventies studied the spectra of 0 the Laplacian and of the Laplace-Beltrami operators on particular mani- 1 0 folds, such as the hyperbolic space ([1]), manifolds with negative sectional 3 curvature ([3]), asymptotically euclidean manifolds ([2]). However, to our 0 knowledge, the case of the Laplace-Beltrami operator acting on p-forms on / h asymptotically euclidean manifolds has been left aside up to now. t a The purpose of this paper is to contribute to the investigation of this m case. We study the absolutely continuous spectrum of the Laplace-Beltrami : operator on Rn endowed with an asymptotically euclidean metric, that is v i with a Riemannian metric satisfying conditions (2.5), (2.6) and (2.7). The X tool employed is classical scattering theory in the wave operators approach. r In this case, the problem is reduced to a problem of scattering for vector- a valued operators. Aninherentrestrictionoftheproof,however, thatmakesitdifficultanex- tension to more general cases, is the use of the Fourier transform, which has a crucial role in our considerations, particularly in connection with Lemma 3.2. The lack of this tool in the more general case of manifolds with an asymptotically controlled Riemannian metric is a major obstacle to the ex- tension of the theorem. 1991 Mathematics Subject Classification. 58G25, 35P25. Key words and phrases. Scattering theory;differential forms. 1 2 FRANCESCAANTOCI 2. Preliminaries Let(Rn,e)betheeuclideann-dimensionalspace,and(Rn,g)bethesame space, endowed with a complete Riemannian metric g. We will denote by Λ1(Rn) the vector space of all smooth, compactly c supported 1-forms on Rn, and by L2(Rn,e) the completion of Λ1(Rn) with 1 c respect to the norm (2.1) ω 2 = < ω,ω > dx, k kL21(Rn,e) ZRn e where dx denotes the Euclidean volume element and < ω(x),ω(x) > = ω2(x) e i Xi is the fiber norm for 1-forms induced by the Euclidean metric. L2(Rn,e) is the Hilbert space direct sum of n copies of L2(Rn). The 1 Laplace-Beltrami operator ∆ on 1-forms ω Λ1(Rn) acts componentwise e ∈ c as: ∂2ω k (∆ ω) = . e k − ∂x2 Xj j It is well-known that ∆ is essentially selfadjoint on Λ1(Rn), and its closure e c H has purely absolutely continuous spectrum equal to 0 σ(H )= [0,+ ), 0 ∞ with constant multiplicity. We will denote by h [ω] the quadratic form associated to ∆ on Λ1(Rn): 0 e c n ∂ω 2 (2.2) h [ω] = < ∆ ω,ω > dx = i dx. 0 ZRn e e ZRniX,j=1(cid:18)∂xj(cid:19) L2(Rn,g) will stand for the completion of Λ1(Rn) with respect to the 1 c norm: (2.3) kωk2L21(Rn,g) = ZRn <ω,ω >g √gdx, where√gdx,asusual,denotesthevolumeelementinducedbytheRiemann- ian metric g and < ω(x),ω(x) > = gij(x)ω (x)ω (x) g i j is the fibernorm for 1-forms inducedby g. (Here, as everywhere throughout the paper, the repeated indices convention is adopted.) The action of the Laplace-Beltrami operator ∆ = dδ + δd on 1-forms g ω Λ1(Rn) is given in local coordinates by the Weitzenbo¨ck formula: ∈ c (∆ ω) = (gij ω) +Riω , g k − ∇i∇j k k i where is the covariant derivative with respect to the connection induced i ∇ by the the metric g, and Ri is the Ricci tensor. k ON THE SPECTRUM OF THE LAPLACE-BELTRAMI OPERATOR 3 Since the Riemannian metric g is complete, ∆ is essentially selfadjoint g on Λ1(Rn). We will denote its closure by H . c 1 Moreover, we will denote by h [ω] the quadratic form associated to ∆ 1 g on Λ1(Rn) c (2.4) h [ω] = < ∆ ω,ω > √gdx = 1 g g ZRn = ω 2√gdx+ < Rω,ω > √gdx, ZRn|∇ |g ZRn g where ω 2 = gijgαβ ω ω |∇ |g ∇i α∇j β and < Rω,ω > = gαβRiω ω . g α i β In thenextsection we willshow how it is possible, undersuitable hypoth- esisontheasymptoticbehaviourofg,togetinformationaboutthespectrum of H from the knowledge of the spectrum of H , proving the following 1 0 Theorem 2.1. Let Rn be endowed with a Riemannian metric g such that ∂gil(x) is bounded and, for x >>0, there exists C >0 such that (cid:12)∂xj (cid:12) | | (cid:12) (1) (cid:12)for every i,j, (cid:12) (cid:12) C (2.5) gij(x) δij < | − | xk | | for some k > n; (2) for every i,j,k,l ∂g C (2.6) il < (cid:12)∂x (cid:12) xk (cid:12) j(cid:12) | | (cid:12) (cid:12) (cid:12) (cid:12) ∂2g C (2.7) il < (cid:12)∂x ∂x (cid:12) xk (cid:12) j k(cid:12) | | (cid:12) (cid:12) for some k > n. (cid:12) (cid:12) Then the Laplace-Beltrami operator ∆ acting on 1-forms has absolutely g continuous spectrum equal to [0,+ ): ∞ [0,+ ) = σ (H )= σ(H ). ac 1 1 ∞ In particular, it has no discrete spectrum. (There might be singularly con- tinuous spectrum or embedded eigenvalues.) The main tool for the proof is Belopol’ski-Birman theorem (see [5], [6]), which provides a sufficient condition so that two selfadjoint operators have the same absolutely continuous spectrum. We recall it briefly: 4 FRANCESCAANTOCI Theorem 2.2. Let H , H be selfadjoint operators acting respectively on 0 1 Hilbert spaces , , and let E (H ), E (H ), for Ω R, be the associ- 0 1 Ω 0 Ω 1 H H ⊂ ated spectral measures. If J ( , ) satisfies the conditions: 0 1 ∈ L H H (1) J has a bounded two-sided inverse; (2) for every bounded interval I R, ⊂ (2.8) E (H )(H J JH )E (H ) ( , ), I 1 1 0 I 0 1 0 1 − ∈ I H H where ( , ) = A ( , ) (A∗A)1/2 ( ) and 1 0 1 0 1 1 0 I H H { ∈ L H H | ∈ I H } ( ) denotes, as usual, the set of trace-class operators on ; 1 0 0 (3) fIorHevery bounded interval I R, (J∗J I)E (H ) is compaHct; I 0 ⊆ − (4) JQ(H ) = Q(H ), where Q(H ) is the form domain of the operator 0 1 i H , for i= 0,1, i then the wave operators W±(H ,H ;J) exist, are complete, and are partial 1 0 isometries with initial space P (H ) and final space P (H ), where P (H ) ac 0 ac 1 ac i denotes, as usual, the absolutely continuous space of H , for i= 0,1. i As a consequence, the absolutely continuous spectra of H and H do 0 1 coincide. Remark 2.3. We recall (see [4]) that if H is a densely defined, essentially selfadjoint, positive operator on a Hilbert space and h is the associated H quadratic form, the form domain Q(H) of the selfadjoint operator H is the domain of the closure h˜ of the form h, that is to say: Q(H) is the set of those u such that there exists a sequence u D(H) converging to u n ∈ H { }⊂ in such that H h[u u ] 0 n m − −→ as n,m + . → ∞ 3. Proof of Theorem 2.1 We will prove that, for a suitable J : L2(Rn,e) L2(Rn,g), H = ∆ , 1 → 1 1 g H = ∆ and J satisfy the conditions of Theorem 2.2, for = L2(Rn,e) 0 e 0 and = L2(Rn,g). H 1 H We begin with the following Lemma 3.1. Let g be as in Theorem 2.1. Then there exist C,C > 0, 1 D,D > 0 such that 1 (1) for every x Rn ∈ (3.1) C g(x) C ; 1 ≤ ≤ p (2) for every x Rn, v in the cotangent space at x, T∗(Rn) ∈ x (3.2) D v2 gij(x)v v D v2. i ≤ i j ≤ 1 i Xi Xi ON THE SPECTRUM OF THE LAPLACE-BELTRAMI OPERATOR 5 Proof. (3.1) follows immediately observing that, for every x, g(x) is strictly positive and g(x) 1 as x + . p → | | → ∞ As for (3.2), sincepthe matrix gij(x), which expresses the Riemannian metric g in contravariant form, is a continuous function of x and is positive, its eigenvalues λ (x),...,λ (x) depend continuously on x and are strictly 1 n positive. Hence, the functions f and h defined by f(x) := infλ (x) i i and h(x) := supλ (x), i i are continuous and strictly positive. Moreover, since the metric g is asymp- totically euclidean, f(x) 1andh(x) 1as x + . Asaconsequence, there exist D,D > 0 suc→h that, for ev→ery x |R|n→, ∞ 1 ∈ D f(x) h(x) D , 1 ≤ ≤ ≤ which yields (3.2). (cid:3) Lemma 3.1 implies that there is a natural identification between L2(Rn,g) 1 and L2(Rn,e), and, moreover, (2.1) and (2.3) are equivalent norms. As 1 a consequence, the identity map on Λ1(Rn) extends to a bounded linear c operator J :L2(Rn,e) L2(Rn,g), 1 −→ 1 with boundedtwo-sided inverse, and condition 1 of Theorem 2.2 is satisfied. In order to prove (2.8), we need two Lemmas: Lemma 3.2. Let A:ξ A be a n n-matrix-valued function on Rn, and ξ 7→ × let be the linear operator A : D( ) L2(Rn) ... L2(Rn) L2(Rn) ... L2(Rn) A A ⊂ ⊕ ⊕ −→ ⊕ ⊕ of the form f(x)A( i ), x − ∇ where f(x) is a function on Rn and A( i ) is the operator x − ∇ A( i ) = Aˆ −1, x ξ − ∇ F ◦ ◦F being the Fourier transform and Aˆ the multiplication operator ξ F v Aˆ v ξ 7−→ (Aˆ v)(ξ) = A(ξ)v(ξ). ξ Let L2(Rn) be the space of functions h such that δ khk2δ = k(1+|x|2)δ2h(x)kL2 < ∞. If, for some δ > n, f(x) L2(Rn) and, for every pair of indices (α,β), 2 ∈ δ Aβ(ξ) L2(Rn), then is a trace-class operator. α ∈ δ A 6 FRANCESCAANTOCI Proof of Lemma 3.2. It suffices to show that, for every fixed (α,β), the operator α Aβ α : D( α) L2(Rn) ... L2(Rn) L2(Rn) ... L2(Rn) Aβ Aβ ⊂ ⊕ ⊕ −→ ⊕ ⊕ ω = (ω1,...,ωn) 7−→ 0,...,0,f(x)Aβα(−i∇x)ωβ,0,...0  α  is trace-class. But this latter op|erator coinc{idzes with the}composition I f(x)Aβ ( i ) P , α◦ α − ∇x ◦ β (cid:16) (cid:17) where P is the projection β P : L2(Rn) ... L2(Rn) L2(Rn) β ⊕ ⊕ −→ ω = (ω ,...,ω ,...,ω ) ω , 1 β n β 7−→ I is the immersion α I : L2(Rn) L2(Rn) ... L2(Rn) α −→ ⊕ ⊕ ω (0,...,0,ω,...,0), 7−→ α and Aα( i ) is the operator | {z } β − ∇x D(Aα( i )) L2(Rn) L2(Rn) β − ∇x ⊂ −→ Aα( i ) = (Aˆ )α −1, β − ∇x F ◦ ξ β ◦F where is the Fourier transform and (Aˆ )α is the multiplication operator F ξ β associated to the scalar function (A )α. ξ β TheconclusionfollowsfromthefactthatP andI areboundedoperators β α and (see [5], Theorem XI.21) any operator L2(Rn) L2(Rn) −→ of the form f(x)h( i ) is trace-class if f(x) and h(ξ) belong to L2(Rn). − ∇x δ (cid:3) Lemma 3.3. If f : Rn R is continuous and such that for some k > n −→ C (3.3) f(x) < | | xk | | when x >>0, then f L2(Rn) for some δ > n. | | ∈ δ 2 Proof. Choosing ǫ > 0 such that k > n+ǫ, then C f(x) < | | xk | | ON THE SPECTRUM OF THE LAPLACE-BELTRAMI OPERATOR 7 for x >>0; as a consequence, a straighforward computation in polar coor- | | dinates shows that, for δ = n +ǫ, 2 f(x)2(1+ x2)δdx < + . ZRn| | | | ∞ (cid:3) Now, to prove (2.8), it suffices to see that for every bounded interval I R, ⊂ (H H )E (H ) (L2(Rn) ... L2(Rn)). 1 0 I 0 1 − ∈ I ⊕ ⊕ Let Γα betheChristoffel symbols of the Riemannian connection inducedby ik g; then the difference H H is given by 1 0 − δ2ω δω δω (3.4) ((H H )ω) = ( gij +δij) k +gijΓα α +gijΓα k 1− 0 k − δxiδxj jk δxi ijδxα δω δΓα +gijΓα α +gij jkω gijΓαΓβ ω gijΓαΓβ ω +Riω . ikδxj δxi α− ij αk β − ik jα β k i A direct computation shows that conditions (2.5), (2.6), (2.7), and hy- ∂Γα pothesis 3 in Theorem 2.1 imply that gijΓα , gijΓα , gijΓα , gij jk , | jk| | ij| | ik| (cid:12) ∂xi (cid:12) gijΓαΓβ , gijΓαΓβ , Ri are all bounded from above by C (cid:12)for som(cid:12)e | ij αk| | ik αj| | k| |x|k (cid:12) (cid:12) constant C > 0 and some k > n. (H H )(E (H )) is a sum of operators of type f(x)A( i ), with 1 0 I 0 x f(x) −L2(Rn) in view of Lemma 3.3, and A(ξ) smooth an−d c∇ompactly ∈ δ supported. Thus, thanks to Lemma 3.2, (H H )(E (H )) is trace-class and condi- 1 0 I 0 − tion 2 is fulfilled. As for condition 3, first of all we observe that the adjoint of J J∗ :L2(Rn,g) L2(Rn,e) 1 −→ 1 satisfies the equation gijω φ √gdx = δijω (J∗φ) dx, i j i j ZRn ZRn and therefore (J∗φ) = δ gijφ √g. k ik j As a consequence, in local coordinates ((J∗J I)φ) = (√ggjk δjk)φ ; k j − − now, √ggjk δjk √g gjk δjk + (√g 1) δij. (cid:12) − (cid:12)≤ | |(cid:12) − (cid:12) | − | By (2.5), ther(cid:12)e exists C >(cid:12)0 such th(cid:12)at (cid:12) (cid:12) (cid:12) (cid:12) (cid:12) C gjk δjk (cid:12) − (cid:12)≤ xk (cid:12) (cid:12) | | (cid:12) (cid:12) 8 FRANCESCAANTOCI for some k > n for x >>0; moreover, | | 1 1 K (√g 1) = 1 g +o | − | 2| − | (cid:18) xk(cid:19) ≤ xk | | | | for some K > 0 and some k > n as x + . Thus,√ggjk−δjk belongstoL2δ(Rn)|. |H→ence∞(J∗J−I)EI(H0)isanoperator of type f(x)A( i ), with f(x) in L2(R2) and A(ξ) smooth and compactly − ∇x δ supported; by Lemma 3.2, it is trace-class, and therefore it is compact. As for condition 4, thanks to Remark 2.3, Q(H ) and Q(H ) can be charac- 0 1 terized as follows: Lemma 3.4. Q(H ) is the set of those ω L2(Rn,e) for which there exists 0 ∈ 1 a sequence ω(n) Λ1(Rn) such that { } ⊂ c (3.5) ω(n) ω in L2(Rn,e) −→ 1 and (3.6) h [ω(n) ω(m)] 0 0 − −→ as n,m + . Analo→gousl∞y, Q(H ) is the set of those ω L2(Rn,g) such that there 1 ∈ 1 exists ψ(n) Λ1(Rn) for which { } ⊂ c (3.7) ψ(n) ω inL2(Rn,g) −→ and (3.8) h [ψ(n) ψ(m)] 0 1 − −→ as n,m + . → ∞ We prove now that (3.9) Q(H ) Q(H ). 0 1 ⊆ For ω Q(H ), there exists a sequence ω(n) Λ1(Rn) satisfying (3.5) ∈ 0 { } ⊂ c and (3.6). Due to the equivalence of the norms (2.1) and (2.3), ω(n) ω in L2(Rn,g); −→ 1 hence, in order to see that ω Q(H ) it suffices to prove that 1 ∈ h [ω(n) ω(m)] 0 1 − −→ as m,n + . → ∞ To establish this fact, we consider first the curvature part of h [ω(n) 1 − ω(m)], (3.10) < R(ω(n) ω(m)),(ω(n) ω(m)) > √gdx. g ZRn − − The following Lemma holds: ON THE SPECTRUM OF THE LAPLACE-BELTRAMI OPERATOR 9 Lemma 3.5. There exists C > 0 such that (3.11) |ZRn < Rω,ω >g √gdx|≤ Ckωk2L21(Rn,e) for every ω L2(Rn,e). ∈ 1 Proof. Consider for every x Rn the quadratic form on T∗(Rn) ∈ x ω gαβ(x)Ri(x)ω ω = Riβ(x)ω ω . 7−→ α i β i β Sincethe matrix Riβ(x) dependscontinuously on x, its eigenvalues λ (x),..., 1 λ (x) are continuous functions of x. Hence the function n f(x):= supλ (x), i i is continuous. Moreover, since the metric g is asymptotically euclidean, f(x) 0 as x + . As a consequence, there exists C > 0 such that f(x)→ C for|e|ve→ry x∞ Rn. This in turn implies | |≤ ∈ Riβ(x)ω ω C ω 2 (cid:12) i β(cid:12)≤ k kTx∗(Rn) (cid:12) (cid:12) for every x Rn and fo(cid:12)r every ω (cid:12)T∗(Rn), which yields (3.11). (cid:3) ∈ ∈ x Since ω(n) is a Cauchy sequence, the preceding Lemma implies that { } (3.12) < R(ω(n) ω(m)),(ω(n) ω(m)) > √gdx 0 g ZRn − − 7−→ as n,m + . → ∞ As for the gradient part of h [ω(n) ω(m)], 1 − (3.13) (ω(n) ω(m))2√gdx, ZRn|∇ − |g we begin by proving Lemma 3.6. There exist C,D > 0 such that (3.14) C η 2dx η 2√gdx D η 2dx ZRn| |e ≤ ZRn| |g ≤ ZRn| |e for every smooth, compactly supported tensor η = η of rank 2, where ij n η 2 = η2 | |e ij iX,j=1 and η 2 = gij(x)gkl(x)η η . | |g ik jl 10 FRANCESCAANTOCI Proof. Consider, for every x Rn, the quadratic form ∈ Rn2 Rn2 R × −→ defined by η = η a(x)[η] = gij(x)gkl(x)η η . ij ik jl 7−→ Since this quadratic form is positive and depends continuously on x, its eigenvalues λ (x), for k = 1,...,n2, are continuous, positive functions of x. k Moreover, n a(x)[η] η2 −→ ij iX,j=1 as x + ,implyingthatλ (x) 1,foreveryk = 1,...,n2,as x + . k | |→ ∞ → | |→ ∞ As a consequence, there exist C,D > 0 such that C η 2 a(x)[η] D η 2 | |e ≤ ≤ | |e for every x Rn, η Rn2, which implies (3.14). (cid:3) ∈ ∈ Setting (n) (m) η = (ω ω ), ik ∇i k − k (3.14) yields 1 (3.15) (ω(n) ω(m))2dx (ω(n) ω(m))2√gdx ZRn|∇ − |e ≤ C ZRn|∇ − |g and (3.16) (ω(n) ω(m))2√gdx D (ω(n) ω(m))2dx. ZRn|∇ − |g ≤ ZRn|∇ − |e Now, ∂ω ω = k Γαω , ∇i k ∂x − ik α i whence an easy computation shows that for every i,k = 1,...,n (n) (m) ∂(ω ω ) ω(n) ω(m) k − k + (cid:13)(cid:13)∇i(cid:16) k − k (cid:17)(cid:13)(cid:13)L2(Rn,e) ≤ (cid:13)(cid:13)(cid:13) ∂xi (cid:13)(cid:13)(cid:13)L2(Rn,e) (cid:13) (cid:13) (cid:13) (cid:13) (cid:13) (cid:13) +K ω(n) ω(m) . (cid:13) − (cid:13)L21(Rn,e) (cid:13) (cid:13) As a consequence, (cid:13) (cid:13) h [ω(n) ω(m)] 0 1 − −→ as n,m 0. Thus, Q(H ) Q(H ). 0 1 → ⊆ We complete the proof of Theorem 2.1 showing that Q(H ) Q(H ). 1 0 ⊆ For any ω Q(H ) there exists a sequence ψ(n) Λ1(Rn) such that (3.7) ∈ 1 { } ⊂ c and (3.8) hold.

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