A class of transversal polymatroids with Gorenstein base ring Alin S¸tefan ”Petroleum and Gas” University of Ploie¸sti, Romania Abstract 8 0 Inthispaper,theprincipaltooltodescribetransversalpolymatroidswithGorensteinbase 0 ringispolyhedralgeometry,especiallytheDanilov−Stanley theoremforthecharacterization 2 of canonical module. Also, we compute the a−invariant and theHilbert series of base ring n associated to this class of transversal polymatroids. a J 1 Introduction 5 1 In this paper we determine the facets of the polyhedral cone generated by the exponent set of ] C the monomials defining the base ring associated to a transversal polymatroid. The importance of knowing those facets comes from the fact that the canonical module of the base ring can A be expressed in terms of the relative interior of the cone. This would allow to compute the . h a−invariant of those base rings. The results presented were discovered by extensive computer t algebra experiments performed with Normaliz [4]. a m TheauthorwouldliketothankProfessorDorinPopescuforvaluablesuggestionsandcomments during the preparation of this paper. [ 1 v 2 Preliminaries 9 2 3 2 Let n ∈ N, n ≥ 3, σ ∈ Sn, σ = (1,2,...,n) the cycle of length n, [n] := {1,2,...,n} and 1. {ei}1≤i≤n be the canonicalbase of Rn. For a vector x∈Rn, x=(x1,...,xn) we will denote by 0 | x |, | x |:=x +...+x . If xa is a monomial in K[x ,...,x ] we set log(xa)=a. Given a set 1 n 1 n 8 A of monomials, the log set of A, denoted log(A), consists of all log(xa) with xa ∈A. 0 We consider the following set of integer vectors of Nn: : v Xi ↓ithcolumn r ν := −(n−i−1), −(n−i−1), ... ,−(n−i−1), (i+1), ... ,(i+1) , a σ0[i] (cid:0) (cid:1) ↓(2)thcolumn ↓(i+1)thcolumn ν := (i+1), −(n−i−1), ... ,−(n−i−1), (i+1), ... ,(i+1) , σ1[i] (cid:0) (cid:1) ↓(3)thcolumn ↓(i+2)thcolumn ν := (i+1), (i+1) ,−(n−i−1), ... ,−(n−i−1), (i+1), ... ,(i+1) , σ2[i] (cid:0) (cid:1) .......................................................................................... ↓(i−2)thcolumn ↓(n−2)thcolumn νσn−2[i] := −(n−i−1),...,−(n−i−1),(i+1), ... ,(i+1),−(n−i−1),−(n−i−1) , (cid:0) (cid:1) 1 ↓(i−1)thcolumn ↓(n−1)thcolumn νσn−1[i] := −(n−i−1), ... ,−(n−i−1),(i+1), ... ,(i+1),−(n−i−1) , (cid:0) (cid:1) where σk[i]:={σk(1),...,σk(i)} for all 1≤i≤n−1 and 0≤k ≤n−1. Remark: ν =n e for all 0≤k ≤n. σk[n−1] [n]\σk[n−1] For example, if n=4, σ =(1,2,3,4)∈S then we have the following set of integer vectors: 4 ν =ν =(−2,2,2,2), ν =ν =(−1,−1,3,3), ν =ν =(0,0,0,4), σ0[1] {1} σ0[2] {1,2} σ0[3] {1,2,3} ν =ν =(2,−2,2,2), ν =ν =(3,−1,−1,3), ν =ν =(4,0,0,0), σ1[1] {2} σ1[2] {2,3} σ1[3] {2,3,4} ν =ν =(2,2,−2,2), ν =ν =(3,3,−1,−1), ν =ν =(0,4,0,0), σ2[1] {3} σ2[2] {3,4} σ2[3] {1,3,4} ν =ν =(2,2,2,−2), ν =ν =(−1,3,3,−1), ν =ν =(0,0,0,4). σ3[1] {4} σ3[2] {1,4} σ3[3] {1,2,4} If06=a∈Rn,thenHa willdenotethehyperplaneofRn throughtheoriginwithnormalvector a, that is, Ha ={x∈Rn | <x,a>=0}, where <,> is the usual inner product in Rn. The two closed halfspaces bounded by Ha are: H+ ={x∈Rn | <x,a>≥0} and H− ={x∈Rn | <x,a>≤0}. a a We will denote by H the hyperplane of Rn through the origin with normal vector ν , σk[i] σk[i] that is, Hνσk[i] ={x∈Rn | <x,νσk[i] >=0}, for all 1≤i≤n−1 and 0≤k ≤n−1. Recallthatapolyhedral coneQ⊂Rn istheintersectionofafinitenumberofclosedsubspaces of the form Ha+. If A = {γ1,..., γr} is a finite set of points in Rn the cone generated by A, denoted by R A, is defined as + r R+A={ aiγi | ai ∈R+, with 1≤i≤n}. Xi=1 An important fact is that Q is a polyhedral cone in Rn if and only if there exists a finite set A⊂Rn such that Q=R A, see ([3] [10],Theorem 4.1.1.). + Next we give some important definitions and results.(see [1], [2], [3], [8], [9].) Definition 2.1. A proper face of a polyhedral cone is a subset F ⊂ Q such that there is a supporting hyperplane H satisfying: a 1) F =Q∩H 6=∅. a 2) Q*Ha and Q⊂Ha+. Definition 2.2. AconeC is apointedif0isa faceofC. Equivalentlywecanrequirethatx∈C and −x∈C ⇒ x=0. Definition 2.3. The 1-dimensional faces of a pointed cone are called extremal rays. Definition 2.4. If a polyhedral cone Q is written as Q=H+ ∩...∩H+ a1 ar such that no one of the H+ canbe omitted, then we saythat this is anirreducible representation ai of Q. 2 Definition 2.5. AproperfaceF ofapolyhedralconeQ⊂ Rn iscalledafacetofQifdim(F)= dim(Q)−1. Definition 2.6. Let Q be a polyhedralcone in Rn withdim Q=n andsuchthat Q6=Rn. Let Q=H+ ∩...∩H+ a1 ar be the irreducible representation of Q. If a =(a ,...,a ), then we call i i1 in H (x):=a x +...+a x =0, ai i1 1 in n i∈[r], the equations of the cone Q. The following result gives us the description of the relative interior of a polyhedral cone when we know the irreducible representation of it. Theorem 2.7. Let Q⊂Rn, Q6=Rn be a polyhedral cone with dim(Q)=n and let (∗) Q=H+ ∩...∩H+ a1 an be a irreducible representation of Q with Ha+1,...,Ha+n distinct, where ai ∈ Rn\{0} for all i. Set F =Q∩H for i∈[r]. Then : i ai a) ri(Q)={x∈Rn | <x,a1 > >0,...,<x,ar > >0}, where ri(Q) is the relative interior of Q, which in this case is just the interior. b) Each facet F of Q is of the form F =F for some i. i c) Each F is a facet of Q if and only if (∗) is irreducible. i Proof. See [1] Theorem 8.2.15, Theorem 3.2.1. Theorem 2.8. (Danilov, Stanley) Let R = K[x ,...,x ] be a polynomial ring over a field K 1 n andF afinitesetof monomials inR.IfK[F]is normal, thenthecanonicalmoduleω ofK[F], K[F] with respect to standard grading, can be expressed as an ideal of K[F] generated by monomials ω =({xa| a∈NA∩ri(R A)}), K[F] + where A=log(F) and ri(R A) denotes the relative interior of R A. + + The formula above represents the canonical module of K[F] as an ideal of K[F] generated by monomials. For a comprehensive treatment of the Danilov−Stanley formula see [2], [8] [9]. 3 Polymatroids Let K be a infinite field, n and m be positive integers, [n] = {1,2,...,n}. A nonempty finite set B of Nn is the base set of a discrete polymatroid P if for every u = (u ,u ,...,u ), 1 2 n v = (v ,v ,...,v ) ∈ B one has u +u +...+u = v +v +...+v and for all i such that 1 2 n 1 2 n 1 2 n u >v thereexistsj suchthatu <v andu+e −e ∈B,wheree denotesthe kth vectorofthe i i j j j i k standardbasisofNn. Thenotionofdiscretepolymatroidisageneralizationoftheclassicalnotion of matroid, see [5] [6] [7] [11]. Associated with the base B of a discret polymatroid P one has a K−algebra K[B], called the base ring of P, defined to be the K−subalgebra of the polynomial ring in n indeterminates K[x ,x ,...,x ] generated by the monomials xu with u ∈ B. From [7] 1 2 n the algebra K[B] is known to be normal and hence Cohen-Macaulay. If A are some non-empty subsets of [n] for 1 ≤ i ≤ m, A = {A ,...,A }, then the set of i 1 m m the vectors e with i ∈ A , is the base of a polymatroid, called transversal polymatroid k=1 ik k k presented byPA. The base ring of a transversal polymatroid presented by A denoted by K[A] is the ring : K[A]:=K[x ···x :i ∈A ,1≤j ≤m]. i1 im j j 3 4 Cones of dimension n with n + 1 facets. Lemma 4.1. Let 1 ≤ i ≤ n−2, A := {log(xj1 ···xjn) | jk ∈ Ak, for all 1 ≤ k ≤ n} ⊂ Nn the exponent set of generators of K−algebra K[A], where A = {A = [n],...,A = [n],A = [n]\ 1 i i+1 [i],...,A =[n]\[i],A =[n]}. Then theconegeneratedbyAhastheirreduciblerepresentation: n−1 n R A= H+, + a a\∈N where N ={ν ,ν | 0≤k ≤n−1}. σ0[i] σk[n−1] (i+1) e +(n−i−1) e , if 1≤k ≤i Proof. WedenotebyJ = k i+1 andbyJ =ne . k (cid:26) (i+1) e1+(n−i−1) ek , if i+2≤k ≤n n Since A =[n] for any t∈{1,...,i}∪{n} and A =[n]\[i] for any r ∈{i+1,...,n−1} it is t r easy to see that for any k ∈{1,...,i} and r ∈{i+2,...,n} the set of monomials xi+1 xn−i−1, k i+1 xi+1 xn−i−1, xn are a subset of the generators of K−algebra K[A]. Thus the set 1 r n {J ,...,J ,J ,...,J ,J}⊂A. 1 i i+2 n If we denote by C the matrix with the rows the coordinates of the {J ,...,J ,J ,...,J ,J}, 1 i i+2 n then by a simple computationwe get|det (C)|=n (i+1)i (n−i−1)n−i−1 for any1≤i≤n−2 and 1≤j ≤n−1. Thus, we get that the set {J ,...,J ,J ,...,J ,J} 1 i i+2 n islinearyindependentanditfollowsthatdimR+A=n. Since{J1,...,Ji,Ji+2,...,Jn}islinearly independent and lie on the hyperplane H we have that dim(H ∩R A)=n−1. σ0[i] σ0[i] + Now we will provethat R A⊂H+ for all a∈N. It is enoughto show that for all vectorsP ∈A, + a <P,a >≥0 for all a∈N. Since ν =n e , where {e } is the canonical base σk[n−1] [n]\σk[n−1] i 1≤i≤n ofRn,we getthat <P,νσk[n−1] >≥0. LetP ∈A, P =log(xj1···xjixji+1···xjn−1xjn) andlet t to be the number of j , such that 1≤k ≤i and j ∈[i]. Thus 1≤t≤i. Now we have only ks s ks two cases to consider: 1) If j ∈[i], then <P,ν >=−t(n−i−1)+(i−t)(i+1)+(n−i−1)(i+1)−(n−i−1)= n σ0[i] n(i−t)≥0. 2) If j ∈[n]\[i], then <P,ν >=−t(n−i−1)+(i−t)(i+1)+(n−i−1)(i+1)+(i+1)= n σ0[i] n(i−t+1)>0. Thus R A⊆ H+. + a a\∈N Now we will prove the converse inclusion: R A⊇ H+. + a∈N a It is clearly enough to prove that the extremal raTys of the cone a∈NHa+ are in R+A. Any extremal ray of the cone a∈NHa+ can be written as the intersectTion of n−1 hyperplanes Ha , witha∈N. TherearetwoTpossibilitiestoobtainextremalraysbyintersectionofn−1hyperplanes. First case. Let 1≤i <...<i ≤n beasequenceand{t}=[n]\{i ,...,i }. Thesystemofequations: 1 n−1 1 n−1 zi1 =0, x1 (∗) ... admits the solution x∈Zn+, x= ... with | x |=n, xk =n·δkt for all zin−1 =0 xn 1≤k ≤n, where δkt is Kronecker symbol. There are two possibilities: 1) If 1≤t≤i, then H (x) < 0 and thus x ∈/ H+. σ0[i] a∈N a 2) If i+1≤t≤n, then Hσ0[i](x) > 0 and thus xT∈ a∈NHa+ and is an extremal ray. T 4 Thus, there exist n−i sequences 1≤i <...<i ≤n such that the system of equations (∗) 1 n−1 has a solution x∈Zn+ with | x |=n and Hσ0[i](x) > 0. The extremal rays are: {ne | i+1≤k ≤n}. k Second case. Let 1 ≤ i < ... < i ≤ n be a sequence and {j, k} = [n]\{i ,...,i }, with j < k and 1 n−2 1 n−2 z =0, i1 . . (∗∗) .z =0, in−2 −(n−i−1)z −...−(n−i−1)z +(i+1)z +...+(i+1)z =0 be the system of line1ar equations associateid to this sei+q1uence. n There are two possibilities: 1) If 1 ≤ j ≤ i and i + 1 ≤ k ≤ n, then the system of equations (∗∗) admits the solution x 1 x= ... ∈Zn+, with | x |=n, with xt =(i+1)δjt+(n−i−1)δkt for all 1≤t≤n. xn 2) If 1≤j,k ≤i or i+1≤j,k ≤n, then there exist no solution x∈Zn with | x | = n for the + system of equations (∗∗) because otherwise H (x) > 0 or H (x)<0. σ0[i] σ0[i] Thus, there exist i(n−i) sequences 1 ≤ i < ... < i ≤ n such that the system of equations 1 n−2 (∗∗) hasasolutionx∈Zn+ with|x|=n andtheextremalraysare: {(i+1)ej+(n−i−1)ek|1≤ j ≤i and i+1≤k ≤n}. In conclusion, there exist (i+1)(n−i) extremal rays of the cone H+: a∈N a T R:={ne | i+1≤k ≤n}∪{(i+1)e +(n−i−1)e | 1≤j ≤i and i+1≤k ≤n}. k j k Since R⊂A we have R A= H+. + a∈N a It is easy to see that the repTresentation is irreducible because if we delete, for some k, the hyperplanewith the normalν ,then a coordinateofa log(x ···x x ···x x )could σk[n−1] j1 ji ji+1 jn−1 jn be negative, which is impossible; and if we delete the hyperplane with the normal ν , then the σ0[i] cone R+A would be generated by A = {log(xj1 ···xjn) | jk ∈ [n], for all 1 ≤ k ≤ n} which is impossible. Thus the representation R A= H+ is irreducible. + a∈N a T Lemma 4.2. Let 1 ≤ i ≤ n−2, 1 ≤ t ≤ n−1, A := {log(x ···x ) | j ∈ A ,1 ≤ j1 jn σt(k) σt(k) k ≤ n} ⊂ Nn the exponent set of generators of K−algebra K[A], where A = {Aσt(k) | Aσt(k) = [n], for 1≤k ≤i and A =[n]\σt[i], for i+1≤k ≤n−1, A =[n]}. Then the cone σt(k) σt(n) generated by A has the irreducible representation: R A= H+, + a a\∈N where N ={ν , ν | 0≤k ≤n−1}. σt[i] σk[n−1] Proof. The proof goes as in Lemma 4.1. since the algebras from Lemmas 4.1. and 4.2. are isomorphic. 5 The a-invariant and the canonical module Lemma5.1. TheK−algebraK[A],whereA={A |A =[n], for1≤k ≤i, andA = σt(k) σt(k) σt(k) [n]\σt[i], for i+1 ≤ k ≤ n−1, A = [n]}, is Gorenstein ring for all 0 ≤ t ≤ n−1 and σt(n) 1≤i≤n−2. Proof. Since the algebras from Lemmas 4.1 and 4.2 are isomorphic it is enough to prove the case t=0. 5 We will show that the canonical module ω is generated by (x ···x )K[A]. Since K− K[A] 1 n algebra K[A] is normal, using the Danilov−Stanley theorem we get that the canonical module ω is K[A] ω ={xα | α∈NA∩ri(R A)}. K[A] + Let d be the greatest common divizor of n and i+1, d=gcd(n, i+1), then the equation of the facet H is νσ0[i] i n (n−i−1) (i+1) H : − x + x =0. νσ0[i] d k d k kX=1 k=Xi+1 The relative interior of the cone R A is: + i n (n−i−1) (i+1) ri(R+A)={x∈Rn | xk > 0, for all 1≤k ≤n, − xk+ xk > 0}. d d Xk=1 k=Xi+1 We will show that NA∩ri(R A)= (1,...,1) + (NA∩R A). + + It is clear that ri(R A) ⊃ (1,...,1) +R A. + + If (α1,α2,...,αn)∈NA∩ri(R+A), then αk ≥1,for all 1≤k ≤n and i n n (n−i−1) (i+1) − α + α ≥1 and α =t n for some t≥1. k k k d d kX=1 k=Xi+1 kX=1 We claim that there exist (β1,β2,...,βn) ∈ NA∩R+A such that (α1,α2,...,αn) = (β1 + 1,β +1,...,β +1). Let β =α −1 for all 1≤k ≤n. It is clear that β ≥0 and 2 n k k k i n i n (n−i−1) (i+1) (n−i−1) (i+1) n − β + β =− α + α − . k k k k d d d d d kX=1 k=Xi+1 kX=1 k=Xi+1 i n (n−i−1) (i+1) n If− α + α =j with1≤j ≤ −1, thenwewillgetacontadiction. k k d d d Xk=1 k=Xi+1 Indeed, since n divides n α , it follows n divides j which is false. k=1 k d So we have P i n i n (n−i−1) (i+1) (n−i−1) (i+1) n − β + β =− α + α − ≥0. k k k k d d d d d kX=1 k=Xi+1 kX=1 k=Xi+1 Thus (β1,β2,...,βn)∈NA∩R+A and (α1,α2,...,αn)∈NA∩ri(R+A). Since NA∩ri(R+A)= (1,...,1) + (NA∩R+A), we get that ωK[A] = (x1···xn)K[A]. Let S be a standard graded K −algebra over a field K. Recall that the a−invariant of S, denoted a(S), is the degree as a rational function of the Hilbert series of S, see for instance ([9], p. 99). If S is Cohen−Macaulay and ω is the canonical module of S, then S a(S)= − min {i | (ω ) 6=0}, S i see ([2], p. 141) and ([9], Proposition 4.2.3). In our situation S = K[A] is normal [7] and consequently Cohen−Macaulay, thus this formula applies. As consequence of Lemma 5.1. we have the following: Corollary 5.2. The a−invariant of K[A] is a(K[A])= −1. Proof. Let {xα1,...,xαq} the generators of K−algebra K[A]. K[A] is standard graded algebra with the grading K[A]i = K(xα1)c1 ···(xαq)cq, where |c|=c1+...+cq. |Xc|=i Sinceω = (x ···x )K[A]itfollowsthatmin{i|(ω ) 6=0}=1,thusa(K[A])= −1. K[A] 1 n K[A] i 6 6 Ehrhart function We consider a fixed set of distinct monomials F = {xα1,...,xαr} in a polynomial ring R = K[x ,...,x ] over a field K. 1 n Let P =conv(log(F)) be the convex hull of the set log(F)={α ,...,α }. 1 r The normalized Ehrhart ring of P is the graded algebra ∞ A = (A ) ⊂R[T] P P j Mj=0 where the j−th component is given by (A ) = K xα Tj. P j α∈Z loXg(F)∩ jP The normalized Ehrhart function of P is defined as EP(j)=dimK(AP)j =| Z log(F)∩jP |. From [9], Proposition7.2.39 and Corollary 7.2.45 we have the following important result: Theorem 6.1. If K[F] is a standard graded subalgebra of R and h is the Hilbert function of K[F], then: a) h(j)≤E (j) for all j ≥0, and P b) h(j)=E (j) for all j ≥0 if and only if K[F] is normal. P In this section we will compute the Hilbert function and the Hilbert series for K− algebra K[A], where A satisfied the hypothesis of Lemma 4.1. Proposition 6.2. In the hypothesis of Lemma 4.1., the Hilbert function of K− algebra K[A] is : (i+1)t k+i−1 nt−k+n−i−1 h(t)= . (cid:18) k (cid:19)(cid:18) nt−k (cid:19) Xk=0 Proof. From [7] we know that the K− algebra K[A] is normal. Thus, to compute the Hilbert function of K[A] it is equivalent to compute the Ehrhart function of P, where P = conv(A). ItisclearenoughthatP istheintersectionoftheconeR+Awiththehyperplanex1+...+xn =n, thus P ={α∈Rn | αk ≥0 for any k ∈[n], 0≤α1+...+αi ≤i+1 and α1+...+αn =n} and t P ={α∈Rn | αk ≥0 for any k∈[n], 0≤α1+...+αi ≤(i+1) t and α1+...+αn =n t}. Since for any 0 ≤ k ≤ (i + 1) t the equation α + ...+ α = k has k+i−1 nonnegative 1 i k integersolutionsandthe equationα +...+α =n t−k has nt−k+n−i−1(cid:0)nonne(cid:1)gativeinteger i+1 n nt−k solutions, we get that (cid:0) (cid:1) (i+1)t k+i−1 nt−k+n−i−1 E (t)=| Z A ∩ t P |= . P (cid:18) k (cid:19)(cid:18) nt−k (cid:19) kX=0 7 Corollary 6.3. The Hilbert series of K− algebra K[A], where A satisfied the hypothesis of Lemma 4.1. is : 1+h t+...+h tn−1 1 n−1 H (t) = , K[A] (1−t)n where j n h = (−1)s h(j−s) , j (cid:18)s(cid:19) Xs=0 h(s) is the Hilbert function of K[A]. Proof. Since the a−invariant of K[A] is a(K[A])= −1, it follows that to compute the Hilbert series of K[A] is necessary to know the first n values of the Hilbert function of K[A], h(i) for 0 ≤ i ≤ n−1. Since dim(K[A]) = n, apllying n times the difference operator ∆ (see [2]) on the Hilbert function of K[A] we get the conclusion. Let ∆0(h) :=h(j) for any 0≤j ≤n−1. j For k ≥1 let ∆k(h) :=1 and ∆k(h) :=∆k−1(h) −∆k−1(h) for any 1≤j ≤n−1. 0 j j j−1 We claim that: k k ∆k(h) = (−1)sh(j−s) j (cid:18)s(cid:19) Xs=0 for any k ≥1 and 0≤j ≤n−1. We proceed by induction on k. If k =1, then 1 1 ∆1(h) =∆0(h) −∆0(h) =h(j)−h(j−1)= (−1)sh(j−s) j j j−1 (cid:18)s(cid:19) Xs=0 for any 1≤j ≤n−1. If k >1, then k−1 k−1 k−1 k−1 ∆k(h) =∆k−1(h) −∆k−1(h) = (−1)sh(j−s) − (−1)sh(j−1−s) = j j j−1 (cid:18) s (cid:19) (cid:18) s (cid:19) Xs=0 Xs=0 k−1 k−2 k−1 k−1 k−1 k−1 =h(j) + (−1)sh(j−s) − (−1)sh(j−1−s) +(−1)kh(j−k) = (cid:18) 0 (cid:19) (cid:18) s (cid:19) (cid:18) s (cid:19) (cid:18)k−1(cid:19) Xs=1 Xs=0 k−1 k−1 k−1 k−1 =h(j)+ (−1)sh(j−s) + +(−1)kh(j−k) = (cid:20)(cid:18) s (cid:19) (cid:18)s−1(cid:19)(cid:21) (cid:18)k−1(cid:19) Xs=1 k−1 k k k−1 k =h(j)+ (−1)sh(j−s) +(−1)kh(j−k) = (−1)sh(j−s) . (cid:18)s(cid:19) (cid:18)k−1(cid:19) (cid:18)s(cid:19) Xs=1 Xs=0 Thus, if k =n it follows that: n j n n h =∆n(h) = (−1)sh(j−s) = (−1)sh(j−s) j j (cid:18)s(cid:19) (cid:18)s(cid:19) Xs=0 Xs=0 for any 1≤j ≤n−1. 8 References [1] A.Brøndsted,IntroductiontoConvexPolytopes,GraduateTextsinMathematics90,Springer- Verlag, 1983. [2] W. Bruns, J. Herzog, Cohen-Macaulay rings, Revised Edition, Cambridge, 1997. [3] W.Bruns, J.Gubeladze, Polytopes, rings and K-theory, preprint. [4] W. Bruns, R. Koch, Normaliz -a program for computing normalizations of affine semigroups, 1998. Available via anonymous ftp from: ftp.mathematik.Uni- Osnabrueck.DE/pub/osm/kommalg/software. [5] J Edmonds, Submodular functions, matroids, and certain polyedra, in Combinatorial Struc- tures and Their Applications, R Guy, H.Hanani, N. Sauer and J. Schonheim (Eds.), Gordon and Breach, New York, 1970. [6] J. Oxley, Matroid Theory, Oxford University Press, Oxford, 1992. [7] J.Herzog and T.Hibi, Discrete polymatroids. J. Algebraic Combin. 16(2002),no. 3, 239-268. [8] E.MillerandBSturmfels,Combinatorial commutative algebra, GraduateTextsinMathemat- ics, 227, Springer-Verlag, New-York 2005. [9] R. Villarreal, Monomial Algebras, Marcel Dekker, 2001. [10] R. Webster, Convexity, Oxford University Press, Oxford, 1994. [11] D. Welsh, Matroid Theory, Academic Press, London, 1976. AlinS¸tefan,AssistantProfessor ”PetroleumandGas”UniversityofPloie¸sti Ploie¸sti,Romania E-mail:[email protected] 9