7 Global Strong Solution of a 2D coupled 1 0 Parabolic-Hyperbolic Magnetohydrodynamic 2 System n a J 9 Ruikuan Liu∗ Jiayan Yang† 2 ∗,†Department of Mathematics, Sichuan University Chengdu, ] Sichuan 610064, P.R.China P †Department of Mathematics, Southwest Medical UniversityLuzhou, A Sichuan 646000, P.R.China . h t a m Abstract [ 1 Themainobjectiveofthispaperistostudytheglobalstrongsolu- v tionofthe parabolic-hyperbolicincompressiblemagnetohydrodynamic 3 (MHD)modelintwodimensionalspace. BasedonAgmon,Douglisand 5 3 Nirenberg’sestimatesforthestationaryStokesequationandtheSolon- 8 nikov’s theorem of Lp-Lq-estimates for the evolution Stokes equation, 0 it is shown that the mixed-type MHD equations exist a global strong . 1 solution. 0 7 keywords 1 : Global strong solution, Magnetohydrodynamics, Stokes equation, Lp- v Lq-estimates. i X r 1 Introduction a Weconsiderthefollowing2-Dincompressiblemagnetohydrodynamic(MHD) model,whichdescribestheinteractionbetweenmovingconductivefluidsand electromagnetic fields in [10], ∂u 1 ρ e +(u·∇)u= ν∆u− ∇p+ u×rotA+f(x), in Ω×[0,T), ∂t ρ0 ρ0 ∂2A 1 ρ = ∆A+ eu−∇Φ, in Ω×[0,T),(1.1) ∂t2 ǫ0µ0 ǫ0 ∇·u= 0, in Ω×[0,T), ∇·A= 0, in Ω×[0,T). ∗Email:[email protected]. Supportedby NSFC(11401479) †Corresponding author:jiayan [email protected]; 1 Here Ω ⊂ R2 is a bounded smooth domain, T is any fixed time. u(x,t), A(x,t), p(x,t) are the velocity field, the magnetic potential and the pressure function, respectively. Φ = ∂A0 represents the magnetic pressure with the ∂t scalar electromagnetic potential A . The constants ν, ρ , ρ , ǫ , µ denote 0 0 e 0 0 kinetic viscosity, mass density, equivalent charge density, electric permittiv- ity and magnetic permeability of free space. In this paper, we focus on the system (1.1) with the initial-boundary conditions u(0,x) = φ(x), A(0,x) = ψ(x), A (0,x) = η(x), in Ω, (1.2) t u(t,x) = 0, A(t,x) =0, on ∂Ω×[0,T). (1.3) Note that the MHD model (1.1) is established based on the the New- ton’s second law and the Maxwell equations for the electromagnetic fields in [10]. In addition, the global weak solutions of the corresponding 3-D MHD model(1.1) with (1.2)-(1.3) has been obtained by using the Galerkin technique and standard energy estimates in [10]. In this paper, what we are concerned is the global strong solution of the 2-D MHD model (1.1) with the initial-boundary conditions (1.2)−(1.3). It is known that there have been huge mathematical studies on the ex- istence of solutions to the N-dimension(N ≥ 2) classical MHD model estab- lishedbyChandrasekhar[4]. Inparticular,DuvautandLions[5]constructed aglobalweaksolutionandthelocalstrongsolutiontothe3-DclassicalMHD equations the initial boundary value problem, and properties of such solu- tions have been investigated by Sermange and Temam in [15]. Furthermore, some sufficient conditions for smoothness were presented for the weak solu- tion to the 3-D classical MHD equations in [7] andsome sufficient conditions oflocalregularityofsuitableweaksolutionstothe3-DclassicalMHDsystem for the points belonging to a C3-smooth part of the boundarywere obtained in [18]. Also, the global strong solutions for heat conducting 3-D classical magnetohydrodynamic flows with non-negative density were proved in [21]. Moreover, let’s recall some known results for the 2-D classical and gen- eralized MHD equations. It is noticed that the 2D classical MHD equations admits a unique global strong solution in [5,15]. Furthermore, Ren, Wu, et.al [14] have proved the global existence and the decay estimates of small smooth solution for the 2-D classical MHD equations without magnetic dif- fusion and Cao, Regmi and Wu [3] have obtained the global regularity for the 2-D classical MHD equations with mixed partial dissipation and mag- netic diffusion. Besides, Regmi [13] established the global weak solution for 2-D classical MHD equations with partial dissipation and vertical dif- fusion. There are also very interesting investigations about the existence of strong solutions to the 2-D classical and generalized MHD equations, see [8,9,12,15,19,20,22] and references therein. 2 However, it is worth pointing out that the incompressible MHD system (1.1)is a mixed-typedifferential differenceequation, which is combined with the parabolic equation (1.1) and the hyperbolic equation (1.1) . The main 1 2 challenge in obtaining global strong solution of 2-D MHD model(1.1) with (1.2)-(1.3) is the estimate for ||u×rotA|| and ||(u·∇)u|| . L∞(0,T;L2) L∞(0,T;L2) The difficulty is overcome by applying the Solonnikov’s theorem [6,11,16] of Lp − Lq-estimates for the non-stationary Stokes equations and Agmon, Douglis and Nirenberg’s estimates [1,2,11] for the stationary Stokes equa- tions. As is known, Solonnikov [16] first gave the proof of Maximal Lp-Lq- estimates for the Stokes equation (2.4) using potential theoretic arguments. Recently, Geissert, Hess, Hieber et.al [6] provided a short proof of the cor- responding Solonnikov’s theorem in [16]. The rest of this article is organized as follows. In Section 2, we introduce some elementary function spaces, a vital embedding theorem and some reg- ularity results of both the non-stationary Stokes equations and stationary Stokes equations. Section 3 is mainly devoted to the proof of global strong solution of (1.1)−(1.3). 2 Preliminaries 2.1 Notations and definitions First, we introduce some notations and conventions used throughout this paper. Let Ω ⊂ R2 be a bounded sufficiently smooth domain. Let Hτ(Ω)(τ = 1,2) be the general Sobolev space on Ω with the norm ||·||Hτ and L2(Ω) be the Hilbert space with the usual norm ||·||. The space H1(Ω) we mean that 0 the completion of C∞(Ω) under the norm ||·|| . If ̥ is a Banach space, 0 H1 we denote by Lp(0,T;̥)(1 < p < ∞) the Banach space of the ̥-valued functions defined in the interval (0,T) that are Lp-integrable. We also consider the following spaces of divergence-free functions (see Temam [17]) X = {u∈ C∞(Ω,R2) | divu= 0 in Ω}, 0 Y = the closure of X in L2(Ω,R2) = {u∈ L2(Ω,R2) | divu= 0 in Ω}, Z = the closure of X in H1(Ω,R2) = {u∈ H1(Ω,R2) | divu= 0 in Ω}. 0 Definition 2.1. Suppose that φ,η ∈ Y, ψ ∈ Z. For any T > 0, a vector function (u,A) is called a global weak solution of problem (1.1)−(1.3) on (0,T)×Ω if it satisfies the following conditions: 3 1. u∈ L2(0,T;Z)∩L∞(0,T;Y), 2. A∈ L∞(0,T;Z), A ∈ L∞(0,T;Y), t 3. For any function v ∈ X, there hold t ρ e u·vdx+ (u·∇)u·v+ν∇u·∇v− (u×rotA)·vdxdt Z Z Z ρ Ω 0 Ω 0 t = f ·vdxdt+ φ·vdx Z Z Z 0 Ω Ω and ∂A t 1 ρ e ·vdx+ ∇u·∇v+ u·vdxdt = ηvdx. Z ∂t Z Z ǫ µ ǫ Z Ω 0 Ω 0 0 0 Ω Now, we define strong solution of the problem (1.1)−(1.3). Definition 2.2. Suppose that φ,ψ ∈ H2(Ω,R2)∩Z, η ∈ Z, Φ ∈ L2(0,T; H1(Ω)). (u,A) is called a global strong solution to (1.1)−(1.3), if (u,A) 0 satisfy u∈ L∞(0,∞;H2(Ω,R2)∩Z), u ∈ L∞(0,∞;Y)∩L2 (0,∞;Z) loc t loc loc p ∈ L∞(0,∞;H1(Ω)), loc A∈ L∞(0,∞;H2(Ω,R2)∩Z), A ∈L∞(0,∞;Z), A ∈ L∞(0,∞;Y). loc t loc tt loc Furthermore, both (1.1) and (1.3) hold almost everywhere in Ω×(0,T). 2.2 Lemmas Some more lemmas will be frequently used later. One is the following em- bedding result in [11]. Lemma 2.3. For any k ≥0, the following hold Lp((0,T),Wk+1,p(Ω))∩L∞(0,T;Lr(Ω)) ⊂ Lq(0,T;Wk,q(Ω)), (2.1) where q = (r(k + 1)p + np)/(rk + n). In the special case of k = 0, (2.1) equals to Lp(0,T;W1,p(Ω))∩L∞(0,T;Lr(Ω)) ⊂ Lq((Ω)×(0,T)), (2.2) provided that q = (n+r)p/n. Proof. From Gagliardo-Nirenberg interpolation inequality, we have ||u|| ≤ C||u||θ ||u||1−θ , 0≤ θ ≤ 1, (2.3) Wk,q Wm,p Wj,r 4 provided that n n n θ m− +(1−θ) j − ≥k− , (cid:18) p(cid:19) (cid:18) r(cid:19) q where C is a constant independent of u. Inserting j =0, q ≥ p, m = k+1 and θ = p into (2.3), it is easy to see that q 1 1 1(1−p/q) q q r |Dku|qdx ≤ C |Dk+1u|pdx |u|rdx , (cid:18)Z (cid:19) (cid:18)Z (cid:19) (cid:18)Z (cid:19) Ω Ω Ω (r(k+1)p+np) where q = . rk+n Then we get T T |Dku|qdxdt ≤ C sup ||u||(q−p)r |Dk+1u|pdxdt, Z Z Lr Z Z 0 Ω 0≤t≤T 0 Ω which implies (2.1) and (2.2). The other lemma is responsible for the estimates for u,p,u and follows t from the Lp-Lq-estimates [6,16] for non-stationary Stokes equations. For its proof, refer to [6,16]. Let us consider the following Stokes equations ∂u = ν∆u−∇p+f(x,t), ∂t ∇·u =0, (2.4) u| = 0, ∂Ω u(0) = u , 0 where ν > 0 is a constant. Lemma 2.4. Let Ω ⊂ Rn(n = 2,3) be a domain with compact C3-boundary, 1 < r,p < ∞, 0 < T < ∞. Then for any f ∈ Lr(0,T;Lq(Ω,Rn)) and u ∈ W2,q(Ω,Rn)) there exists a unique solution (u,p) of (2.4) satisfying 0 u ∈Lr(0,T;W2,q(Ω,Rn)), u ∈Lr(0,T;Lq(Ω,Rn)), t p ∈ Lr(0,T;W1,q(Ω)) such that ||u|| +||u || +||p|| Lr(0,T;W2,q) t Lr(0,T;Lq) Lr(0,T;W1,q) ≤ C(||f|| +||u || ), Lr(0,T;Lq) 0 W2,q where C > 0 is a constant. 5 Finally, we give some regularity results for the stationary Stokes system. For its proof, refer to [1,2,11]. Lemma 2.5. Assume that (v,p) ∈ W2,p(Ω,Rn)×W1,p(Ω)(1 <p < ∞) is a weak solution of the stationary Stokes equations −ν∆v−∇p = F(x), in Ω, ∇·v = 0, in Ω, v| = 0, on ∂Ω, ∂Ω and F ∈ Wk,q(Ω,Rn)(k ≥ 0,1 < q < ∞). Then it holds that (v,p) ∈ Wk+2,q(Ω,Rn)×Wk+1,q(Ω) and ||v||Wk+2,q +||p||Wk+1,q ≤ C(||F||Wk,q +||(u,p)||Lq) with some constant C depending on n, Ω and q. 3 Main Results In this section, we state the global weak solution existence theorem and the global strong solution existence one for the problem (1.1)−(1.3), and also prove them. Theorem 3.1. Let the initial value φ,η ∈ Y, ψ ∈ Z. If f ∈ Y,Φ ∈ L2(0,T;H1(Ω)), then there exists a global weak solution for the problem 0 (1.1)−(1.3). Proof. By the standard Galerkin method and the similar estimates in [10], the existence of global weak solution of (1.1)−(1.3) is also valid, we omit it. Theorem 3.2. Let Ω be a bounded domain with compact C3-boundary. If φ,ψ ∈ H2(Ω,R2) ∩ Z, η ∈ Z, for any f ∈ Y,Φ ∈ L2(0,T;H1(Ω)), then 0 there exists a global strong solution for the problem (1.1)−(1.3), i.e., for any 0 < T < ∞ u ∈ L∞(0,T;H2(Ω,R2)∩Z), u ∈L∞(0,T;Y)∩L2(0,T;Z) t p ∈ L∞(0,T;H1(Ω)), A ∈ L∞(0,T;H2(Ω,R2)∩Z), A ∈ L∞(0,T;Z), A ∈ L∞(0,T;Y). t tt Proof. The proof can be divided into 3 steps. We will use the same generic constant C to denote various constants that depend on µ ,ρ ,ρ ,ǫ and T 0 0 e 0 only. Step 1 The estimates and regularity for A. 6 From Theorem 3.1, for any 0 < T < ∞, we get the global weak solution u∈ L2(0,T;Z)∩L∞(0,T;Y), (3.1) A∈ L∞(0,T;Z), A ∈ L∞(0,T;Y). t Multiplying both sides of (1.1) by −∆A and integrating over Ω, we have 2 t 1 d 1 ρ |∇A |2+ |∆A|2dx = e ∇u∇A dx (3.2) t t 2dt(cid:18)Z ǫ µ (cid:19) ǫ Z Ω 0 0 0 Ω since divA= 0 and (1.3). Using the H¨older inequality, it is easy to see that d 1 1 ρ2 ||∇A ||2 + ||∆A||2 ≤ 2 ||∇A ||2 + ||∆A||2 + e||∇u||2 . dt(cid:18) t L2 ǫ µ L2(cid:19) (cid:18) t L2 ǫ µ L2 ǫ2 L2(cid:19) 0 0 0 0 0 (3.3) Then, by the Gronwall inequality, (3.3) implies ρ2 T ||∇A ||2 +||∆A||2 ≤ e2T ||∆ψ|| +||∇η|| +2 0 ||∇u||2 ds , t L2 L2 (cid:18) L2 L2 ǫ2 Z L2 (cid:19) 0 0 (3.4) for ∀ 0 < T < ∞. Therefore, we conclude that ∇A ∈ L∞(0,T;Y), ∆A∈ L∞(0,T;Y). (3.5) t Next, we need to derive an estimate on ||A || . tt L∞(0,T;Y) Multiplying both sides of Eqs. (1.1) by A integrating over Ω lead to 2 tt 1 ρ |A |2dx = ∆AA dx+ 0 uA dx (3.6) tt tt tt Z ǫ µ Z ǫ Z Ω 0 0 Ω 0 Ω since − ∇ΦA dx = ΦdivA dx = 0. Ω tt Ω tt Using thRe H¨oder inequaRlity and Young inequality, we deduce from (3.6) that 1 ρ2 1 |A |2dx ≤ |∆A|2dx+ 0 |u|2dx+ |A |2dx. (3.7) Z tt ǫ2µ2 Z ǫ2 Z 2 Z tt Ω 0 0 Ω 0 Ω Ω It is easy to see that 2 2ρ2 ess sup |A |2dx ≤ sup |∆A|2dx+ sup 0 |u|2dx. (3.8) Z tt ǫ2µ2 Z ǫ2 Z 0≤t≤T Ω 0≤t≤T 0 0 Ω 0≤t≤T 0 Ω Putting the estimates (3.1), (3.5) and (3.8) together, we have A ∈ L∞(0,T;Y). (3.9) tt Hence, (3.5) and (3.9) imply the regularity for A. 4 4 Step 2 The L3-L3-estimates for u·∇u and u×A. 7 From (3.1) and Lemma 2.3(the case that k=0), it is easy to check that u∈ L4((0,T)×Ω). (3.10) Note that 2 1 T |Du|43|u|43dxdt ≤ T |Du|2dxdt 3 T |u|4dxdt 3, Z Z (cid:18)Z Z (cid:19) (cid:18)Z Z (cid:19) 0 Ω 0 Ω 0 Ω (3.11) which implies that u·∇u∈ L43(0,T;L43(Ω,R2)). (3.12) Combining (3.1) and (3.10), we get 1 2 T |u×rotA|43dxdt ≤ T |u|4dxdt 3 T |rotA|2dxdt 3 Z Z (cid:18)Z Z (cid:19) (cid:18)Z Z (cid:19) 0 Ω 0 Ω 0 Ω 1 2 T 3 T 3 ≤ C |u|4dxdt |∇A|2dxdt (cid:18)Z Z (cid:19) (cid:18)Z Z (cid:19) 0 Ω 0 Ω < ∞, (3.13) which in turn implies u×rotA ∈L43(0,T;L43(Ω,R2)). (3.14) Recall that (u,p) satisfying the following Stokes system ∂u 1 = ν∆u− ∇p+F(x,t), ∂t ρ0 ∇·u= 0, (3.15) u| = 0, ∂Ω u(0) = φ, where F(x,t) = f −(u·∇)u+ ρe(u×rotA). ρ0 By (3.12)and(3.14), we getF ∈ L34(0,T;L43(Ω,R2)). Applyingthisinto Lemma 2.4, we obtain that u∈ L43(0,T;W2,43(Ω,R2)), ut ∈ L34(0,T;L43(Ω,R2)), (3.16) p ∈ L34(0,T;W1,43(Ω)). Inthenextstep,theLemma2.5willbeused,since(3.15)canberewritten as the following stationary Stokes equations 1 −ν∆u+ ∇p = F(x,t), ρ0 ∇·u = 0, e (3.17) u| = 0, ∂Ω u(0) = φ, 8 where F(x,t) = f −(u·∇)u+ ρe(u×rotA)−u . ρ0 t Step 3 The estimate for ||F|| . e L∞(Ω,L2(Ω,R2)) (i) The estimate for ||∇eu||L∞(0,T;L2). Multiplying Eq. (1.1) by u and integrating over Ω, we have 1 t µ d ρ |∇u|2dx+ |u |2dx = −(u·∇)u·u + e(u×rotA)u dx. (3.18) t t t 2dt Z Z Z ρ Ω Ω Ω 0 Note that the following continuous embeddings W2,34(Ω,R2) ֒→ W1,4(Ω,R2) ֒→ C12(Ω,R2)֒→ C0(Ω,R2). (3.19) Combining (3.19), H¨older inequality and ǫ−Younginequality, we derive that |(u·∇)u·u |dx ≤ C||u || ||u|| ||∇u|| t t L2 C0 L2 Z Ω (3.20) 1 ≤ ||u ||2 +C2||u||2 ||∇u||2 4 t L2 C0 L2 and ρ e |(u×rotA)u |dx ≤ C||u|| ||∇A|| ||u || ρ Z t C0 L2 t L2 0 Ω (3.21) 1 ≤ ||u ||2 +C2||u||2 ||∇A||2 , 4 t L2 C0 L2 which together with Gronwall’s inequality implies ess sup ||∇u|| < ∞. L2 (3.22) 0<t<T (ii) The estimate for ||u || . t L∞(0,T;L2) Taking t-derivative of Eq. (1.1) , then one gets that 1 1 ρ ρ e e u −µ∆u = −(u ·∇)u−(u·∇)u − ∇p + u ×rotA+ u×rotA . (3.23) tt t t t t t t ρ ρ ρ 0 0 0 Multiplying (3.23) by u and integrating over Ω, we obtain t 1 d ρ |u |2dx+µ |∇u |2dx = −(u ·∇)u·u + e(u×rotA )u dx. t t t t t t 2dt Z Z Z ρ Ω Ω Ω 0 (3.24) since 1 (u ×rotA)·u = 0, (u·∇)u ·u dx = − u2divudx = 0. t t Z t t Z 2 t Ω Ω 9 Next, we estimate the two terms on the right hand of (3.24). By (3.19) and integrating by parts yield − (u ·∇)u·u dx = uiuj∂ uj −ui∂ (ujuj)dx t t t i t t i t Z Z Ω Ω (3.25) = uiuj∂ ujdx ≤ C||u|| ||u ||2 +||∇u ||2 . Z t i t C0(cid:18) t L2 t L2(cid:19) Ω And similarly, ρ Cρ e e |(u×rotA )u |dx ≤ |uu ∇A |dx t t t t ρ Z ρ Z 0 Ω 0 Ω (3.26) Cρ ≤ e||u|| ||u ||2 +||∇A ||2 . ρ C0(cid:18) t L2 t L2(cid:19) 0 Hence, by (3.24), (3.25) and (3.26), we get that 1 d |u |2dx+µ |∇u |2dx t t 2dt Z Z Ω Ω Cρ ≤ ||u|| (1+Cρ /ρ )||u ||2 +||∇u ||2 + e||u|| ||∇A ||2 , C0(cid:18) e 0 t L2 t L2(cid:19) ρ C0 t L2 0 (3.27) which together with Gronwall’s inequality completes the estimate ess sup ||u (t)|| < ∞. t L2 (3.28) 0<t<T (iii) The estimates for ||(u·∇u)|| and ||u×A|| . L∞(0,T;L2) L∞(0,T;L2) From (3.22), it is easy to see that ∇u∈ L∞(0,T;Y). (3.29) Hence u ∈L∞(0,T;H1). It is known that H1 ֒→ Lq(1 < q < ∞) when n = 2. Note that 1 1 2−r |(u·∇)u|rdx r ≤ |∇u|2dx 2 |u|22−rrdx 2r < ∞ (3.30) (cid:18)Z (cid:19) (cid:18)Z (cid:19) (cid:18)Z (cid:19) Ω Ω Ω provided that 1 < r < 2. Hence (u·∇)u∈ L∞(0,T;Lr(Ω,R2)). (3.31) By using the H¨older inequality and the Sobolev embedding theorem, it follows that |u×rotA|2dx ≤ C |u|2|∇A|2dx Z Z Ω Ω ≤ C |u|4dx+ |∇A|4dx (3.32) (cid:18)Z Z (cid:19) Ω Ω ≤ C |∇u|2dx+ |∆A|2dx . (cid:18)Z Z (cid:19) Ω Ω 10